Question Number 209460 by Shubha51343 last updated on 10/Jul/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 209453 by peter frank last updated on 10/Jul/24 Commented by peter frank last updated on 10/Jul/24 $$\mathrm{help}\:\mathrm{B} \\ $$ Answered by mr W…
Question Number 209452 by peter frank last updated on 10/Jul/24 Answered by Ghisom last updated on 10/Jul/24 $$\mathrm{12}\:\mathrm{units} \\ $$$$−\mathrm{4}\:\mathrm{units}\:\left(\mathrm{12}/\mathrm{3}\right)\:\mathrm{for}\:\mathrm{sugar}\:=\:\mathrm{8}\:\mathrm{units} \\ $$$$−\mathrm{2}\:\mathrm{units}\:\left(\mathrm{8}/\mathrm{4}\right)\:\mathrm{for}\:\mathrm{soap}\:=\:\mathrm{6}\:\mathrm{units} \\ $$$$\mathrm{6}\:\mathrm{units}\:=\:\mathrm{6000} \\…
Question Number 209342 by essaad last updated on 07/Jul/24 Answered by Berbere last updated on 07/Jul/24 $${U}_{{n}+\mathrm{1}} ={f}\left({U}_{{n}} \right) \\ $$$${x}\overset{{f}} {\rightarrow}\frac{{x}}{\mathrm{2}}+\frac{{x}^{\mathrm{2}} }{\mathrm{4}};{f}\:{increase} \\ $$$${f}\left(\left[\mathrm{0},\mathrm{1}\right]\right)=\left[\mathrm{0},\frac{\mathrm{3}}{\mathrm{4}}\right]\subset\left[\mathrm{0},\mathrm{1}\right]…
Question Number 209166 by Tawa11 last updated on 02/Jul/24 Answered by mr W last updated on 02/Jul/24 $$\left({a}\right) \\ $$$${p}=\left(\frac{\mathrm{3}}{\mathrm{4}}\right)^{\mathrm{3}} =\mathrm{0}.\mathrm{42} \\ $$$$\left({b}\right) \\ $$$${p}={C}_{\mathrm{2}}…
Question Number 209128 by Spillover last updated on 02/Jul/24 Answered by A5T last updated on 02/Jul/24 $${The}\:{length}\:{of}\:{the}\:{diagonal}\:{of}\:{the}\:{square}=\mathrm{2}{r} \\ $$$$\Rightarrow{s}^{\mathrm{2}} +{s}^{\mathrm{2}} =\mathrm{4}{r}^{\mathrm{2}} \Rightarrow\mathrm{2}{s}^{\mathrm{2}} =\mathrm{4}{r}^{\mathrm{2}} \Rightarrow{s}^{\mathrm{2}} =\mathrm{2}{r}^{\mathrm{2}}…
Question Number 209167 by lmcp1203 last updated on 02/Jul/24 $${please}\:{convert}\:\:\mathrm{2531}_{\left(\mathrm{5000}\right)\:} {to}\:\:{base}\:\mathrm{5002}.\:\:{thanks}.\:\: \\ $$ Answered by mr W last updated on 03/Jul/24 $$\mathrm{2531}_{\left(\mathrm{5000}\right)} =\mathrm{2}×\mathrm{5000}^{\mathrm{3}} +\mathrm{5}×\mathrm{5000}^{\mathrm{2}} +\mathrm{3}×\mathrm{5000}+\mathrm{1}…
Question Number 209127 by Spillover last updated on 02/Jul/24 Answered by efronzo1 last updated on 02/Jul/24 $$\:\:\underline{\underbrace{\boldsymbol{{x}}}} \\ $$ Commented by Spillover last updated on…
Question Number 209123 by Spillover last updated on 02/Jul/24 Answered by A5T last updated on 02/Jul/24 $${max}\left(\mathrm{1000}{x}+\mathrm{600}{c}\right)\:{given}\:{c}\geqslant\mathrm{4}{x}\:{and}\:{x}+{c}\leqslant\mathrm{200} \\ $$$$\mathrm{4}{x}−{c}\leqslant\mathrm{0}\:{and}\:{x}+{c}\leqslant\mathrm{200}\Rightarrow{x}\leqslant\mathrm{40} \\ $$$$\Rightarrow{max}\left(\mathrm{1000}{x}+\mathrm{600}{c}\right)=\mathrm{1000}×\mathrm{40}+\mathrm{600}×\mathrm{160} \\ $$$$=\mathrm{136000}. \\ $$…
Question Number 209066 by Tawa11 last updated on 01/Jul/24 Commented by Tawa11 last updated on 01/Jul/24 Answered by A5T last updated on 01/Jul/24 $${cos}\mathrm{48}°=\frac{{XA}}{\mathrm{19}}\Rightarrow{XA}=\mathrm{19}{cos}\mathrm{48}° \\…