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Category: Arithmetic

Question-77132

Question Number 77132 by peter frank last updated on 03/Jan/20 Commented by kaivan.ahmadi last updated on 03/Jan/20 z=43(12+i32)4(32+i12)=23+6i+232i=43+4i=4(3+i)=8(32+i12)=8eiπ6$$\Rightarrow\frac{{z}}{\mathrm{8}}+{i}\left(\frac{{z}}{\mathrm{8}}\right)^{\mathrm{2}} +\left(\frac{{z}}{\mathrm{8}}\right)^{\mathrm{3}}…