Question Number 74948 by vishalbhardwaj last updated on 04/Dec/19 $$\mathrm{The}\:\mathrm{hhpotenuse}\:\mathrm{of}\:\mathrm{a}\:\mathrm{right}\:\mathrm{angled}\:\mathrm{triangle} \\ $$$$\mathrm{has}\:\mathrm{its}\:\mathrm{ends}\:\mathrm{at}\:\mathrm{the}\:\mathrm{points}\:\left(\mathrm{1},\mathrm{3}\right)\:\mathrm{and}\:\left(−\mathrm{4},\mathrm{1}\right) \\ $$$$.\:\mathrm{Find}\:\mathrm{an}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{legs}\:\left(\mathrm{perpendicar}\right. \\ $$$$\left.\:\mathrm{sides}\right)\:\mathrm{of}\:\mathrm{the}\:\mathrm{triangle}. \\ $$ Answered by MJS last updated on 04/Dec/19…
Question Number 9391 by Joel575 last updated on 04/Dec/16 $$\underset{{n}=\mathrm{2}} {\overset{\mathrm{100}} {\sum}}\:\left(\mathrm{1}\:−\:\frac{\mathrm{1}}{{n}^{\mathrm{2}\:} }\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 74923 by aliesam last updated on 04/Dec/19 $$\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{k}^{\mathrm{3}} =\left[\frac{{n}\left({n}+\mathrm{1}\right)\:}{\mathrm{2}}\right]^{\mathrm{2}} \\ $$ Commented by aliesam last updated on 04/Dec/19 $${god}\:{bless}\:{you} \\ $$…
Question Number 9379 by FilupSmith last updated on 03/Dec/16 $${S}=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left(−{n}\right)^{\mathrm{1}−{n}} \\ $$$${S}=?? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9325 by tawakalitu last updated on 30/Nov/16 Answered by RasheedSoomro last updated on 30/Nov/16 $$\left(\mathrm{B}\right)\:\mathrm{12}\: \\ $$$$\mathrm{25}\equiv−\mathrm{1}\left(\mathrm{mod}\:\mathrm{13}\right) \\ $$$$\left(\mathrm{25}\right)^{\mathrm{15}} \equiv\left(−\mathrm{1}\right)^{\mathrm{15}} \left(\mathrm{mod}\:\mathrm{13}\right) \\ $$$$\left(\mathrm{25}\right)^{\mathrm{15}}…
Question Number 74817 by peter frank last updated on 01/Dec/19 Answered by mr W last updated on 03/Dec/19 $${parallel}\:{chords}: \\ $$$${y}={mx}+{k} \\ $$$${x}\left({mx}+{k}\right)={c}^{\mathrm{2}} \\ $$$${mx}^{\mathrm{2}}…
Question Number 74819 by Raxreedoroid last updated on 01/Dec/19 $$\mathrm{Expand}\:\Sigma \\ $$$$\frac{\mathrm{4}{n}−\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{2}}{\mathrm{3}}\underset{{k}=\mathrm{1}} {\overset{{n}−\mathrm{1}} {\sum}}{cos}\left(\mathrm{120}{k}\right) \\ $$ Commented by mathmax by abdo last updated on 01/Dec/19…
Question Number 9250 by tawakalitu last updated on 25/Nov/16 Commented by sou1618 last updated on 26/Nov/16 Commented by tawakalitu last updated on 26/Nov/16 $$\mathrm{Wow}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\…
Question Number 9189 by raj bunsha last updated on 22/Nov/16 $${x}+{y}+{z}=−\mathrm{6} \\ $$$${xy}+{xz}+{yz}=\mathrm{11} \\ $$$${xyz}=−\mathrm{6} \\ $$$${then}\:{wbat}\:{are}\:{thd}\:{value}\:{of}\:{x}\:{yand}\:{z} \\ $$ Answered by mrW last updated on…
Question Number 74622 by Raxreedoroid last updated on 27/Nov/19 $$\mathrm{Expand} \\ $$$$\mathrm{1}+\frac{\mathrm{2}}{\mathrm{3}}\centerdot\left(\underset{{k}=\mathrm{1}} {\overset{{n}−\mathrm{1}} {\sum}}\left[{cos}\left(\frac{\mathrm{2}\pi}{\mathrm{3}}{x}\right)\right]+\mathrm{2}{n}−\mathrm{2}\right) \\ $$ Commented by Raxreedoroid last updated on 28/Nov/19 $$\mathrm{No}\:\mathrm{its}\:\mathrm{just}\:\mathrm{to}\:\mathrm{clarify}\:\mathrm{whats}\:\mathrm{inside}\:\mathrm{sigma} \\…