Question Number 140008 by ajfour last updated on 03/May/21 $$\:{If}\:{in}\:{a}\:{number}\:{system} \\ $$$$\:\:\mathrm{25}×\mathrm{32}=\mathrm{1163} \\ $$$${find}\:{how}\:{many}\:{digits}\:{are}\:{there} \\ $$$${in}\:{the}\:{number}\:{system}\:{used}. \\ $$ Answered by MJS_new last updated on 03/May/21…
Question Number 139959 by Engr_Jidda last updated on 02/May/21 $${If}\:{W}\:{varies}\:{jointly}\:{as}\:{L}\:{and}\:{the} \\ $$$${square}\:{of}\:{R}.\:{Find}\:{the}\:{percentage} \\ $$$${change}\:{in}\:{W}\:{if}\:{L}\:{increases}\:{by}\:\mathrm{20\%} \\ $$$${and}\:{R}\:{increases}\:{by}\:\mathrm{50\%}. \\ $$$${If}\:{W}=\mathrm{15}\:{when}\:{H}=\mathrm{3}\:{and}\:{R}=\mathrm{2}\frac{\mathrm{1}}{\mathrm{3}}.\:{find}\: \\ $$$${W}\:{when}\:{H}=\mathrm{1}\:{and}\:{R}=\mathrm{10}. \\ $$$${Find}\:{also}\:{W}\:{interms}\:\:{of}\:{H}\:{and}\:{R}. \\ $$ Answered…
Question Number 139941 by metamorfose last updated on 02/May/21 $${find}\:{prime}\:{numbers}\:{p}\:,\:{q}\:{so}\:{that}: \\ $$$$\mathrm{2}^{{p}} ={q}^{{q}} +{q}+\mathrm{2} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 8858 by tawakalitu last updated on 01/Nov/16 Answered by sandy_suhendra last updated on 03/Nov/16 $$\mathrm{1st}\:\mathrm{year}\:\mathrm{he}\:\mathrm{got}=\mathrm{U}_{\mathrm{1}} =\mathrm{122},\mathrm{000} \\ $$$$\mathrm{2nd}\:\mathrm{year}\:\mathrm{he}\:\mathrm{got}=\mathrm{122},\mathrm{800} \\ $$$$\mathrm{3rd}\:\mathrm{year}\:\mathrm{he}\:\mathrm{got}=\mathrm{123},\mathrm{600} \\ $$$$. \\…
Question Number 8847 by tawakalitu last updated on 31/Oct/16 Commented by Rasheed Soomro last updated on 01/Nov/16 $$\mathrm{Let}\:\mathrm{r}\:\mathrm{be}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{in}\:\mathrm{each}\:\mathrm{case} \\ $$$$\mathrm{N}\:\mathrm{is}\:\mathrm{GCD}\:\mathrm{of}\:\mathrm{1305}−\mathrm{r},\mathrm{4665}−\mathrm{r}\:\mathrm{and}\:\mathrm{6905}−\mathrm{r} \\ $$$$\mathrm{Let}\:\mathrm{1305}−\mathrm{r}=\mathrm{AN},\:\mathrm{4665}−\mathrm{r}=\mathrm{BN}\:\:\mathrm{and}\:\:\mathrm{6905}−\mathrm{r}=\mathrm{CN} \\ $$$$\mathrm{AN}+\mathrm{r}=\mathrm{1305}\:,\:\mathrm{BN}+\mathrm{r}=\mathrm{4665}\:\:\mathrm{and}\:\:\mathrm{CN}+\mathrm{r}=\mathrm{6905} \\…
Question Number 8846 by Rasheed Soomro last updated on 31/Oct/16 $$\mathrm{Let}\:\mathrm{by}\:\left(\mathrm{a}_{\mathrm{1}} ,\mathrm{a}_{\mathrm{2}} ,…\mathrm{a}_{\mathrm{n}} \right)\:\mathrm{we}\:\mathrm{mean}\:\mathrm{LCM} \\ $$$$\mathrm{of}\:\:\mathrm{a}_{\mathrm{1}} ,\mathrm{a}_{\mathrm{2}} ,…\mathrm{a}_{\mathrm{n}} \:,\mathrm{where}\:\mathrm{a}_{\mathrm{i}} \in\mathbb{N}. \\ $$$$\mathrm{Prove}\:\mathrm{or}\:\mathrm{disprove}\:\mathrm{that}\:\left(\:\left(\mathrm{a},\mathrm{b}\right),\left(\mathrm{b},\mathrm{c}\right)\:\:\right)=\left(\mathrm{a},\mathrm{b},\mathrm{c}\right). \\ $$ Answered…
Question Number 8845 by tawakalitu last updated on 31/Oct/16 $$\mathrm{Please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{figure}\:\mathrm{out}\:\mathrm{this}\: \\ $$$$\mathrm{Quantitative}\:\mathrm{reasoning} \\ $$$$\mathrm{How}\:\mathrm{did}\:\mathrm{they}\:\mathrm{get}\:\mathrm{this}\:\mathrm{answers}. \\ $$$$ \\ $$$$\mathrm{2},\mathrm{613},\mathrm{400}\:=\:\mathrm{3} \\ $$$$\mathrm{2},\mathrm{451},\mathrm{100}\:=\:\mathrm{1} \\ $$$$\mathrm{2},\mathrm{541},\mathrm{100}\:=\:\mathrm{2} \\ $$$$\mathrm{3},\mathrm{000},\mathrm{001}\:=\:\mathrm{1} \\…
Question Number 8829 by tawakalitu last updated on 30/Oct/16 $$\mathrm{The}\:\mathrm{LCM}\:\mathrm{of}\:\mathrm{three}\:\mathrm{whole}\:\mathrm{number}\:\mathrm{is}\:\mathrm{144}.\: \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{their}\:\mathrm{third}\:\mathrm{common}\:\mathrm{multiple}. \\ $$ Commented by Rasheed Soomro last updated on 31/Oct/16 $$\mathrm{All}\:\mathrm{the}\:\mathrm{common}\:\mathrm{multiples}\:\mathrm{are}\:\mathrm{multiples}\:\mathrm{of}\:\mathrm{LCM}. \\ $$$$\mathrm{First}\:\mathrm{common}\:\mathrm{multiple}\:\mathrm{is}\:\mathrm{LCM}\:\mathrm{itself}.\:\mathrm{The}\:\mathrm{second}…
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Question Number 8764 by tawakalitu last updated on 26/Oct/16 $$\left(\mathrm{a}\right)\:\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{given}\:\mathrm{by} \\ $$$$\mathrm{S}_{\mathrm{n}} \:=\:\frac{\mathrm{1}}{\mathrm{1}.\mathrm{3}}\:+\:\frac{\mathrm{1}}{\mathrm{3}.\mathrm{5}}\:+\:\frac{\mathrm{1}}{\mathrm{5}.\mathrm{7}}\:+\:…\:+\:\frac{\mathrm{1}}{\left(\mathrm{2n}\:−\:\mathrm{1}\right)\left(\mathrm{2n}\:+\:\mathrm{1}\right)} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{find}\:\mathrm{the}\:\mathrm{limit}\:\mathrm{of}\:\:\:\mathrm{S}_{\mathrm{n}} \:\:\mathrm{as}\:\:\mathrm{n}\:\rightarrow\:\infty \\ $$ Commented by sou1618 last updated on 26/Oct/16…