Question Number 74617 by Raxreedoroid last updated on 27/Nov/19 $$\mathrm{Expand} \\ $$$$\mathrm{1}+\underset{{k}=\mathrm{1}} {\overset{{n}−\mathrm{1}} {\sum}}\left[\mid\frac{\mathrm{2}\sqrt{\mathrm{3}}}{\mathrm{3}}{sin}\left(\mathrm{120}{x}\right)\mid+\mathrm{2}\right] \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9041 by tawakalitu last updated on 16/Nov/16 Commented by sou1618 last updated on 16/Nov/16 $$ \\ $$$$ \\ $$$$\begin{pmatrix}{}&{{X}}&{}\\{{A}}&{{B}}&{{C}}\end{pmatrix} \\ $$$${X}=\frac{{A}×{B}×{C}}{\mathrm{10}} \\ $$…
Question Number 74573 by Raxreedoroid last updated on 26/Nov/19 $$\mathrm{Find}\:\left(\mathrm{turn}\:\mathrm{it}\:\mathrm{into}\:\mathrm{non}-\mathrm{segma}\:\mathrm{expression}\right) \\ $$$$\mathrm{1}+\underset{{k}=\mathrm{1}} {\overset{{n}−\mathrm{1}} {\sum}}\frac{\left(−\mathrm{1}\right)^{{k}} +\mathrm{3}}{\mathrm{2}} \\ $$ Commented by mathmax by abdo last updated on…
Question Number 74559 by lalitchand last updated on 26/Nov/19 $$\mathrm{The}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{N}\:\mathrm{Arithmetic}\:\mathrm{means}\:\mathrm{between}\:\mathrm{two}\:\mathrm{numbers} \\ $$$$\mathrm{is}\:\mathrm{20}.\:\mathrm{If}\:\mathrm{last}\:\mathrm{mean}\:\mathrm{is}\:\mathrm{double}\:\mathrm{of}\:\mathrm{1st}\:\mathrm{mean} \\ $$$$\mathrm{and}\:\mathrm{one}\:\mathrm{is}\:\mathrm{three}\:\mathrm{times}\:\mathrm{the}\:\mathrm{another}\:\mathrm{number}.\: \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{numbers} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 140029 by metamorfose last updated on 03/May/21 $${si}\:{p}={ab}\:{and}\:\left({a}=\mathrm{1}\:{ou}\:{b}=\mathrm{1}\right)\:{then}\:{p}\:{is}\:{prime}? \\ $$ Answered by MJS_new last updated on 03/May/21 $$\mathrm{example}:\:{a}=\mathrm{1}\wedge{b}=\mathrm{4}\:\Rightarrow\:{p}=\mathrm{4}\:\mathrm{not}\:\mathrm{prime} \\ $$ Terms of Service…
Question Number 140008 by ajfour last updated on 03/May/21 $$\:{If}\:{in}\:{a}\:{number}\:{system} \\ $$$$\:\:\mathrm{25}×\mathrm{32}=\mathrm{1163} \\ $$$${find}\:{how}\:{many}\:{digits}\:{are}\:{there} \\ $$$${in}\:{the}\:{number}\:{system}\:{used}. \\ $$ Answered by MJS_new last updated on 03/May/21…
Question Number 139959 by Engr_Jidda last updated on 02/May/21 $${If}\:{W}\:{varies}\:{jointly}\:{as}\:{L}\:{and}\:{the} \\ $$$${square}\:{of}\:{R}.\:{Find}\:{the}\:{percentage} \\ $$$${change}\:{in}\:{W}\:{if}\:{L}\:{increases}\:{by}\:\mathrm{20\%} \\ $$$${and}\:{R}\:{increases}\:{by}\:\mathrm{50\%}. \\ $$$${If}\:{W}=\mathrm{15}\:{when}\:{H}=\mathrm{3}\:{and}\:{R}=\mathrm{2}\frac{\mathrm{1}}{\mathrm{3}}.\:{find}\: \\ $$$${W}\:{when}\:{H}=\mathrm{1}\:{and}\:{R}=\mathrm{10}. \\ $$$${Find}\:{also}\:{W}\:{interms}\:\:{of}\:{H}\:{and}\:{R}. \\ $$ Answered…
Question Number 139941 by metamorfose last updated on 02/May/21 $${find}\:{prime}\:{numbers}\:{p}\:,\:{q}\:{so}\:{that}: \\ $$$$\mathrm{2}^{{p}} ={q}^{{q}} +{q}+\mathrm{2} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 8858 by tawakalitu last updated on 01/Nov/16 Answered by sandy_suhendra last updated on 03/Nov/16 $$\mathrm{1st}\:\mathrm{year}\:\mathrm{he}\:\mathrm{got}=\mathrm{U}_{\mathrm{1}} =\mathrm{122},\mathrm{000} \\ $$$$\mathrm{2nd}\:\mathrm{year}\:\mathrm{he}\:\mathrm{got}=\mathrm{122},\mathrm{800} \\ $$$$\mathrm{3rd}\:\mathrm{year}\:\mathrm{he}\:\mathrm{got}=\mathrm{123},\mathrm{600} \\ $$$$. \\…
Question Number 8847 by tawakalitu last updated on 31/Oct/16 Commented by Rasheed Soomro last updated on 01/Nov/16 $$\mathrm{Let}\:\mathrm{r}\:\mathrm{be}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{in}\:\mathrm{each}\:\mathrm{case} \\ $$$$\mathrm{N}\:\mathrm{is}\:\mathrm{GCD}\:\mathrm{of}\:\mathrm{1305}−\mathrm{r},\mathrm{4665}−\mathrm{r}\:\mathrm{and}\:\mathrm{6905}−\mathrm{r} \\ $$$$\mathrm{Let}\:\mathrm{1305}−\mathrm{r}=\mathrm{AN},\:\mathrm{4665}−\mathrm{r}=\mathrm{BN}\:\:\mathrm{and}\:\:\mathrm{6905}−\mathrm{r}=\mathrm{CN} \\ $$$$\mathrm{AN}+\mathrm{r}=\mathrm{1305}\:,\:\mathrm{BN}+\mathrm{r}=\mathrm{4665}\:\:\mathrm{and}\:\:\mathrm{CN}+\mathrm{r}=\mathrm{6905} \\…