Question Number 200750 by arif1234567890 last updated on 22/Nov/23 $$\mathrm{5}×\mathrm{5} \\ $$$$ \\ $$ Answered by Frix last updated on 22/Nov/23 $$\sqrt{\mathrm{625}} \\ $$ Terms…
Question Number 200627 by cherokeesay last updated on 21/Nov/23 Answered by Frix last updated on 21/Nov/23 $$\mathrm{The}\:\mathrm{1}^{\mathrm{st}} \:\mathrm{equation}\:\mathrm{is}\:\mathrm{true}\:\mathrm{for}\:{y}=\frac{\mathrm{1}}{{x}} \\ $$$$\Rightarrow\:{x}=\mathrm{2}\wedge{y}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Commented by cherokeesay…
Question Number 200657 by cherokeesay last updated on 21/Nov/23 Answered by Frix last updated on 21/Nov/23 $$\mathrm{3}\sqrt[{\mathrm{4}}]{\mathrm{27}{x}^{\mathrm{2}} +\mathrm{24}{x}+\frac{\mathrm{28}}{\mathrm{3}}}=\mathrm{4}+\sqrt[{\mathrm{3}}]{\frac{\mathrm{81}{x}}{\mathrm{2}}−\mathrm{1}} \\ $$$$\mathrm{3}\sqrt[{\mathrm{4}}]{\frac{\mathrm{81}{x}^{\mathrm{2}} +\mathrm{72}{x}+\mathrm{28}}{\mathrm{3}}}=\mathrm{4}+\sqrt[{\mathrm{3}}]{\frac{\mathrm{81}{x}−\mathrm{2}}{\mathrm{2}}} \\ $$$${x}=\frac{{t}}{\mathrm{9}} \\ $$$$\mathrm{3}\sqrt[{\mathrm{4}}]{\frac{{t}^{\mathrm{2}}…
Question Number 200531 by cherokeesay last updated on 19/Nov/23 Answered by witcher3 last updated on 21/Nov/23 $$\mathrm{witch}\:\mathrm{Quation}? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 200321 by mr W last updated on 17/Nov/23 $${for}\:{x},{y},{z}\:\in{N},\:{if} \\ $$$$\mathrm{38}{x}+\mathrm{40}{y}+\mathrm{41}{z}=\mathrm{520} \\ $$$${find}\:{x}+{y}+{z}=? \\ $$ Answered by Rasheed.Sindhi last updated on 17/Nov/23 $$\mathrm{520}−\mathrm{38}{x}−\mathrm{40}{y}=\mathrm{41}{z}…
Question Number 200236 by mr W last updated on 16/Nov/23 $${what}\:{is}\:{the}\:{smallest}\:{natural}\:{number} \\ $$$${which}\:{has}\:{at}\:{least}\:\mathrm{100}\:{divisors}? \\ $$ Answered by MM42 last updated on 16/Nov/23 $$\mathrm{2}^{\mathrm{4}} ×\mathrm{3}^{\mathrm{4}} ×\mathrm{5}×\mathrm{7}=\mathrm{45360}\:\checkmark…
Question Number 200265 by cherokeesay last updated on 16/Nov/23 Answered by witcher3 last updated on 16/Nov/23 $$\begin{cases}{\left(\mathrm{x}^{\mathrm{2}} −\mathrm{y}\right)^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} −\mathrm{2}.\mathrm{5}\left(\mathrm{x}^{\mathrm{2}} −\mathrm{y}\right)=\mathrm{0}}\\{\left(\mathrm{2}\right)\Leftrightarrow\left(\mathrm{2}\right)}\end{cases} \\ $$$$\Leftrightarrow\begin{cases}{\left(\mathrm{x}^{\mathrm{2}} −\mathrm{y}−\mathrm{5}\right)^{\mathrm{2}} =\mathrm{0}}\\{\sqrt{\left(\mathrm{x}^{\mathrm{2}}…
Question Number 200205 by cherokeesay last updated on 15/Nov/23 Commented by Frix last updated on 15/Nov/23 $$\mathrm{min}\:=\mathrm{4} \\ $$$$\mathrm{max}=+\infty \\ $$ Terms of Service Privacy…
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Question Number 200005 by Mingma last updated on 12/Nov/23 Answered by AST last updated on 12/Nov/23 $$\left(\frac{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} }{\mathrm{3}}\right)^{\frac{\mathrm{1}}{\mathrm{2}}} \geqslant\left(\frac{{a}+{b}+{c}}{\mathrm{3}}\right)\Rightarrow{a}+{b}+{c}\leqslant\mathrm{3} \\ $$$$\Sigma\frac{\mathrm{1}}{\mathrm{2}{a}+{b}}\geqslant\frac{\mathrm{9}}{\mathrm{3}\left({a}+{b}+{c}\right)}\geqslant\frac{\mathrm{9}}{\mathrm{3}×\mathrm{3}}=\mathrm{1} \\ $$$${Equality}\:{holds}\:{when}\:{a}={b}={c}=\mathrm{1}…