Question Number 6914 by Tawakalitu. last updated on 02/Aug/16 $${How}\:{many}\:{digits}\:{are}\:{in}\:\:\:\:\:\mathrm{3}^{\mathrm{5000}} \\ $$ Commented by Rasheed Soomro last updated on 03/Aug/16 $$\mathrm{3}^{\mathrm{1}} =\mathrm{3}\:\left(\mathrm{1}\:{digit}\right)\:,\:\mathrm{3}^{\mathrm{2}} =\mathrm{9}\:\left(\mathrm{1}\:{digit}\right) \\ $$$$\mathrm{3}^{\mathrm{3}}…
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Question Number 6905 by rahma last updated on 02/Aug/16 Answered by sandy_suhendra last updated on 02/Aug/16 $$\sqrt[{\mathrm{3}}]{\mathrm{120}\:{x}^{\mathrm{5}} }\:\boldsymbol{\div}\:\mathrm{2}\sqrt[{\mathrm{3}}]{\mathrm{5}{x}} \\ $$$$=\sqrt[{\mathrm{3}}]{\mathrm{8}×\mathrm{15}{x}^{\mathrm{5}} }\:\boldsymbol{\div}\:\mathrm{2}\sqrt[{\mathrm{3}}]{\mathrm{5}{x}} \\ $$$$=\mathrm{2}{x}\sqrt[{\mathrm{3}}]{\mathrm{15}{x}^{\mathrm{2}} }\:\boldsymbol{\div}\:\mathrm{2}\sqrt[{\mathrm{3}}]{\mathrm{5}{x}} \\…
Question Number 6906 by Tawakalitu. last updated on 02/Aug/16 Commented by Rasheed Soomro last updated on 02/Aug/16 $${Let}\:{there}\:{are}\:{x}\:{students}\:{in}\:{Class}\:{C} \\ $$$${There}\:{will}\:{be}\:{x}+\mathrm{4}\:{students}\:{in}\:{Class}\:{B}\:\left[\mathrm{4}\:{more}\:{than}\:{C}\right] \\ $$$$\:\:\:\:\:\:\:{and}\:\:{x}+\mathrm{8}\:{in}\:{Class}\:{A}.\left[\mathrm{4}\:{more}\:{than}\:{B}\right] \\ $$$$ \\…
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Question Number 6902 by Tawakalitu. last updated on 02/Aug/16 $$\mathrm{1}^{\mathrm{6}} \:+\:\mathrm{3}^{\mathrm{6}} \:+\:\mathrm{5}^{\mathrm{6}} \:+\:…\:+\:\left(\mathrm{2}{n}\:−\:\mathrm{1}\right)^{\mathrm{6}} \:\:=\:\:{B} \\ $$$$ \\ $$$${Solve}\:{for}\:{B}. \\ $$ Commented by Yozzii last updated…
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Question Number 6892 by Tawakalitu. last updated on 01/Aug/16 $$\mathrm{1}^{\mathrm{6}} \:+\:\mathrm{3}^{\mathrm{6}} \:+\:\mathrm{5}^{\mathrm{6}} \:+\:….\:+\:\left(\mathrm{2}{n}\:−\:\mathrm{1}\right)^{\mathrm{6}} \:\:=\:\:{B} \\ $$$$ \\ $$$${Find}\:{the}\:{value}\:{of}\:{B}\: \\ $$ Terms of Service Privacy Policy…
Question Number 6843 by Tawakalitu. last updated on 30/Jul/16 $$\mathrm{2}^{\mathrm{10}} \:+\:\mathrm{3}^{\mathrm{20}} \:+\:\mathrm{4}^{\mathrm{30}} \:+\:\mathrm{5}^{\mathrm{40}} \:+\:\mathrm{6}^{\mathrm{50}} \:\:\left({mod}\:\mathrm{7}\right)\:=\:? \\ $$ Commented by prakash jain last updated on 31/Jul/16…
Question Number 137907 by peter frank last updated on 08/Apr/21 Answered by EnterUsername last updated on 08/Apr/21 $$\int_{\mathrm{1}} ^{{e}} \frac{\mathrm{1}+{lnx}}{{x}}{dx}=\int_{\mathrm{1}} ^{{e}} \left(\frac{\mathrm{1}}{{x}}+\frac{{lnx}}{{x}}\right){dx} \\ $$$$=\left[{lnx}+\frac{{ln}^{\mathrm{2}} {x}}{\mathrm{2}}\right]_{\mathrm{1}}…