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Category: Arithmetic

Question-6788

Question Number 6788 by Tawakalitu. last updated on 26/Jul/16 Commented by Yozzii last updated on 27/Jul/16 $$\mathrm{60}=\mathrm{6}×\mathrm{10}=\left(\mathrm{3}×\mathrm{2}\right)\left(\mathrm{7}+\mathrm{3}\right) \\ $$$$\mathrm{17},\mathrm{23},\mathrm{32} \\ $$$${Add}\:{the}\:{two}\:{largest}\:{unit}\:{digit}\:{values}\:{among} \\ $$$${the}\:{three}\:{numbers}\:\left(\mathrm{3}\:\&\:\mathrm{7}\right)\:{and}\:{multiply}\:{this} \\ $$$${answer}\:{with}\:{the}\:{two}\:{largest}\:{digit}\:{values}\:{in}…

Three-Arabs-A-B-and-C-were-traveling-together-On-the-lunch-time-A-and-B-produce-m-and-n-loaves-of-bread-respectively-for-eating-but-C-have-no-loaf-of-bread-All-the-three-ate-together-After-compl

Question Number 6786 by Rasheed Soomro last updated on 25/Jul/16 $${Three}\:{Arabs}\:{A},{B}\:{and}\:{C}\:{were}\:{traveling} \\ $$$${together}.\:{On}\:{the}\:{lunch}\:{time}\:{A}\:{and}\:\:{B} \\ $$$${produce}\:{m}\:{and}\:\:{n}\:{loaves}\:{of}\:{bread}\:{respectively} \\ $$$${for}\:{eating}\:{but}\:{C}\:{have}\:{no}\:{loaf}\:{of}\:{bread}.\:{All} \\ $$$${the}\:{three}\:{ate}\:{together}.\:\:{After}\:{completing} \\ $$$${lunch}\:{C}\:\:{gave}\:{A}\:{and}\:{B}\:{m}+{n}\:{darhams}. \\ $$$${How}\:{shoud}\:{they}\:{divide}\:{this}\:{sum}? \\ $$$$…

P-and-Q-are-partners-in-a-venture-P-contributed-20-000-for-nine-month-and-Q-contributed-50-000-for-one-year-find-each-person-share-of-profit-of-6-300-

Question Number 6743 by Tawakalitu. last updated on 20/Jul/16 $${P}\:{and}\:{Q}\:{are}\:{partners}\:{in}\:{a}\:{venture},\:\:{P}\:\:{contributed}\:#\mathrm{20},\mathrm{000}\:{for} \\ $$$${nine}\:{month},\:{and}\:{Q}\:{contributed}\:#\mathrm{50},\mathrm{000}\:{for}\:{one}\:{year}.\:{find}\:{each} \\ $$$${person}\:{share}\:{of}\:\:{profit}\:{of}\:#\mathrm{6},\mathrm{300} \\ $$$$ \\ $$ Answered by Rasheed Soomro last updated on…

Question-6593

Question Number 6593 by Tawakalitu. last updated on 04/Jul/16 Commented by Yozzii last updated on 05/Jul/16 $${Given}\:{that}\:{p}\:{is}\:{prime}\:{and}\:{p}\leqslant\mathrm{100}, \\ $$$${show}\:{that}\:{there}\:{are}\:{solutions}\:\left({x},{y}\right),\: \\ $$$${x},{y}\in\mathbb{Z},\:{for}\:{which}\:{y}^{\mathrm{37}} \equiv{x}^{\mathrm{3}} +\mathrm{37}\:\left({mod}\:{p}\right). \\ $$$$−−−−−−−−−−−−−−−−−−−−−−−…

Prove-and-show-why-k-1-n-H-k-n-1-H-n-1-1-Where-H-k-1-1-2-1-3-1-k-

Question Number 6487 by Temp last updated on 29/Jun/16 $$\mathrm{Prove}\:\mathrm{and}\:\mathrm{show}\:\mathrm{why}: \\ $$$$\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{H}_{{k}} =\left({n}+\mathrm{1}\right)\left({H}_{{n}+\mathrm{1}} −\mathrm{1}\right) \\ $$$$\mathrm{Where}: \\ $$$${H}_{{k}} =\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+…+\frac{\mathrm{1}}{{k}} \\ $$ Commented by…

Solve-1-x-2-x-4-3-

Question Number 71925 by Henri Boucatchou last updated on 22/Oct/19 $$\:\boldsymbol{{Solve}}\:\:\sqrt{\mathrm{1}\:−\:\boldsymbol{{x}}^{\mathrm{2}} }\:=\:\boldsymbol{{x}}^{\mathrm{4}/\mathrm{3}} \\ $$ Answered by MJS last updated on 23/Oct/19 $${x}={t}^{\mathrm{3}/\mathrm{2}} \\ $$$$\sqrt{\mathrm{1}−{t}^{\mathrm{3}} }={t}^{\mathrm{2}}…