Category: Arithmetic

Question Number 200121 by Mingma last updated on 14/Nov/23 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 200004 by Mingma last updated on 12/Nov/23 Answered by aleks041103 last updated on 12/Nov/23 $$-1<x<1$$$${f}\left({x}\right)=\frac{{x}+\mathrm{2}^{{k}} }{\mathrm{2}^{{k}+\mathrm{1}} }=\frac{{x}}{\mathrm{2}^{{k}+\mathrm{1}} }+\frac{\mathrm{1}}{\mathrm{2}}\Rightarrow\frac{\mathrm{1}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{2}^{{k}+\mathrm{1}} }<{f}\left({x}\right)<\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}^{{k}+\mathrm{1}} } \…

Question Number 199863 by Karanji last updated on 10/Nov/23 $$-5+(-8)+(-11)+\dots +(-230)$$ Answered by som(math1967) last updated on 10/Nov/23 $$c.d=(-8)-(-5)=-3$$$$-230=-5+(n-1)\times -3$$$$\Rightarrow\left({n}−\mathrm{1}\right)=\mathrm{75} \…

Question Number 199729 by Mingma last updated on 08/Nov/23 Answered by mathfreak01 last updated on 08/Nov/23 $$N=\underset{n=1}{\sum ^{450}}({10}^n-1)$$$${N}\:=\:\underset{{n}=\mathrm{1}} {\overset{\mathrm{450}} {\sum}}\mathrm{10}^{{n}} \:−\:\mathrm{450}…

Question Number 199621 by Mingma last updated on 06/Nov/23 Answered by AST last updated on 06/Nov/23 $$x+y\stackrel{3}{\equiv }2\dots \left(i\right)$$$$(6+6+y)-(7+x)=5+y-x\stackrel{11}{\equiv }0\Rightarrow x-y\stackrel{11}{\equiv }5\dots \left(ii\right)$$$$\left({i}\right)\wedge\left({ii}\right)\Rightarrow\left({x},{y}\right)=\left(\mathrm{8},\mathrm{3}\right);\left(\mathrm{5},\mathrm{0}\right);\left(\mathrm{1},\mathrm{7}\right) \…