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Question Number 64153 by meme last updated on 14/Jul/19 $${solve}\:{to}\:{z}^{\mathrm{2}} \:\:\:{x}^{\mathrm{2}} −{y}^{\mathrm{2}} =\mathrm{24} \\ $$ Answered by mr W last updated on 15/Jul/19 $$\left({x}−{y}\right)\left({x}+{y}\right)=\mathrm{24}={a}×{b}=\mathrm{1}×\mathrm{24}=\mathrm{2}×\mathrm{12}=\mathrm{3}×\mathrm{8}=\mathrm{4}×\mathrm{6} \\…
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Question Number 63956 by meme last updated on 11/Jul/19 $${x}^{\mathrm{2}} −{y}^{\mathrm{2}} =\mathrm{24} \\ $$ Answered by meme last updated on 12/Jul/19 $${solve}\:{at}\:{z}^{\mathrm{2}} \\ $$ Terms…
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Question Number 63561 by aliesam last updated on 05/Jul/19 Answered by MJS last updated on 05/Jul/19 $$=\underset{{k}=\mathrm{1}} {\overset{{n}} {\prod}}\left(\mathrm{2}{k}−\mathrm{1}\right)×\underset{{k}=\mathrm{1}} {\overset{{n}} {\prod}}\mathrm{2}{k}= \\ $$$$=\left[\mathrm{1}×\mathrm{3}×\mathrm{5}×…×\left(\mathrm{2}{n}−\mathrm{1}\right)\right]×\left[\mathrm{2}×\mathrm{4}×\mathrm{6}×…×\mathrm{2}{n}\right]= \\ $$$$=\mathrm{1}×\mathrm{2}×\mathrm{3}×\mathrm{4}×…×\left(\mathrm{2}{n}−\mathrm{1}\right)\left(\mathrm{2}{n}\right)=…
Question Number 128907 by bramlexs22 last updated on 11/Jan/21 $$\:\mathrm{Given}\:\mathrm{U}_{\mathrm{n}} \:=\:\begin{cases}{\mathrm{2n}+\mathrm{1}\:;\:\mathrm{n}\:\mathrm{even}}\\{\mathrm{3n}+\mathrm{3}\:;\:\mathrm{n}\:\mathrm{odd}}\end{cases} \\ $$$$\mathrm{The}\:\mathrm{value}\:\mathrm{of}\:\mathrm{U}_{\mathrm{3}} +\mathrm{U}_{\mathrm{6}} +\mathrm{U}_{\mathrm{7}} +\mathrm{U}_{\mathrm{10}} +\mathrm{U}_{\mathrm{11}} + \\ $$$$\:\mathrm{U}_{\mathrm{14}} +…+\mathrm{U}_{\mathrm{27}} +\mathrm{U}_{\mathrm{28}} =? \\ $$…
Question Number 128849 by I want to learn more last updated on 10/Jan/21 Commented by Tawa11 last updated on 15/Sep/21 $$\mathrm{nice} \\ $$ Answered by…
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