Question Number 122954 by mr W last updated on 21/Nov/20 Commented by Dwaipayan Shikari last updated on 21/Nov/20 $${Infinitely}\:\:{many}\:{answers}\:{sir}! \\ $$$${If}\:{they}\:{are}\:{in}\:{a}\:{relation}\:\:{C}=\mathrm{1}+\left({n}−\mathrm{1}\right) \\ $$$${then}\:\mathrm{12}\:{will}\:{cost}\:\mathrm{12}\:\$\:\:\:\left({for}\:{the}\:{people}\:{who}…..\right) \\ $$$${If}\:{they}\:{are}\:{in}\:{a}\:{relation}…
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Question Number 57377 by Tawa1 last updated on 03/Apr/19 $$\mathrm{Can}\:\mathrm{i}\:\mathrm{find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{a}\:\mathrm{product}\:\mathrm{to}\:\mathrm{infinity}\:? \\ $$$$\:\:\:\mathrm{e}.\mathrm{g}\:\:\:\:\:\:\:\mathrm{1}.\mathrm{2}.\mathrm{3}.\mathrm{4}.\mathrm{5}\:….\:\:\:\:\mathrm{infinity} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 188442 by BaliramKumar last updated on 03/Mar/23 $$ \\ $$$${Solve}\:{by}\:{computer}\:{programing} \\ $$$$\left({if}\:{possible}\right)\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{d}<{a}<{b}\:\&\:{c}\:<\:{a},\:{b}>\mathrm{2}{c} \\ $$$$\cancel{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} =\:\mathrm{5}{c}^{\mathrm{2}} +\mathrm{2}{d}^{\mathrm{2}} }\:\:\:\:\:\:\:\:\:\:\:\:\left({a},\:{b},\:{c},\:{d}\:\:\in\:\mathrm{N}\right) \\ $$$${c}^{\mathrm{2}} +{d}^{\mathrm{2}} \:=\:{a}^{\mathrm{2}} \:\:\:\:\:\:\:\:………\left({i}\right)…
Question Number 122850 by liberty last updated on 20/Nov/20 $$\:\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\:\frac{\mathrm{4}{k}}{\mathrm{4}{k}^{\mathrm{4}} +\mathrm{1}}\:=\:? \\ $$ Answered by bemath last updated on 20/Nov/20 $$\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\:\frac{\left(\mathrm{2}{k}^{\mathrm{2}}…
Question Number 188375 by Rupesh123 last updated on 28/Feb/23 Commented by Frix last updated on 28/Feb/23 $${M}=\mathrm{45}\:\mathrm{at}\:{x}=−\frac{\mathrm{17}}{\mathrm{2}} \\ $$ Commented by Rupesh123 last updated on…
Question Number 122705 by john santu last updated on 19/Nov/20 Commented by liberty last updated on 19/Nov/20 $$\Rightarrow{a}\::\:{b}\:=\:\mathrm{2}\::\:\mathrm{3}\: \\ $$$$\Rightarrow{b}\::\:{c}\:=\:\mathrm{3}\::\:\mathrm{4} \\ $$$$\Rightarrow\:{c}\::\:{d}\:=\:\mathrm{5}\::\:\mathrm{6}\: \\ $$$${then}\:{a}\::\:{b}\::\:{c}\::\:{d}\:=\:\mathrm{10}\::\:\mathrm{15}\::\:\mathrm{20}\::\:\mathrm{24} \\…
Question Number 122608 by bramlexs22 last updated on 18/Nov/20 $$\:{Sum}\:{the}\:{series}\:{to}\:\mathrm{10}^{{th}} \:{terms}\: \\ $$$$\:\frac{\mathrm{1}}{\mathrm{1}+\sqrt{{x}}}\:+\:\frac{\mathrm{1}}{\mathrm{1}−{x}}\:+\frac{\mathrm{1}}{\mathrm{1}−\sqrt{{x}}}\:+… \\ $$$${equal}\:{to}\:\_\_\_\: \\ $$ Answered by liberty last updated on 18/Nov/20 $$\:\mathrm{T}_{\mathrm{1}}…
Question Number 122605 by bramlexs22 last updated on 18/Nov/20 Answered by Dwaipayan Shikari last updated on 18/Nov/20 $${T}_{{n}} =\frac{\mathrm{2}}{{n}\left({n}+\mathrm{1}\right)} \\ $$$${S}_{{n}} +\mathrm{1}=\overset{{n}} {\sum}\frac{\mathrm{2}}{{n}\left({n}+\mathrm{1}\right)} \\ $$$${S}_{{n}}…
Question Number 122484 by JBocanegra last updated on 17/Nov/20 $$\:\frac{\mathrm{4}{a}}{\mathrm{3}{b}\centerdot\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{3}}} \centerdot{a}^{\frac{\mathrm{2}}{\mathrm{3}}} \centerdot{b}^{\frac{\mathrm{1}}{\mathrm{3}}} } \\ $$$$\left(\frac{\mathrm{4}}{\mathrm{3}\centerdot\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{3}}} }\right)\left(\frac{{a}}{{a}^{\frac{\mathrm{2}}{\mathrm{3}}} \centerdot{b}^{\frac{\mathrm{4}}{\mathrm{3}}} }\right) \\ $$$$\left(\frac{\mathrm{2}^{\mathrm{2}} }{\mathrm{3}\centerdot\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{3}}} }\right)\left({a}^{\mathrm{1}−\frac{\mathrm{2}}{\mathrm{3}}} \centerdot{b}^{−\frac{\mathrm{4}}{\mathrm{3}}} \right)=\left(\mathrm{2}^{\mathrm{2}−\frac{\mathrm{1}}{\mathrm{3}}} \right)\left({a}^{\frac{\mathrm{1}}{\mathrm{3}}}…