Question Number 211104 by peter frank last updated on 28/Aug/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 211020 by peter frank last updated on 26/Aug/24 Answered by mahdipoor last updated on 26/Aug/24 $${dV}=\left(\pi{y}^{\mathrm{2}} \right)\left({dx}\right)=\pi\frac{\left({x}−{a}\right)^{\mathrm{2}} \left({x}−{b}\right)^{\mathrm{2}} }{{c}^{\mathrm{2}} }{dx} \\ $$$${V}=\int{dV}=\frac{\pi}{{c}^{\mathrm{2}} }\int_{{a}}…
Question Number 211019 by peter frank last updated on 26/Aug/24 Answered by som(math1967) last updated on 26/Aug/24 $$\:{let}\:{x}={sin}\alpha\:\:{y}={sin}\beta \\ $$$$\:{cos}\alpha+{cos}\beta={a}\left({sin}\alpha−{sin}\beta\right) \\ $$$$\Rightarrow\frac{\mathrm{2}{cos}\frac{\alpha+\beta}{\mathrm{2}}{cos}\frac{\alpha−\beta}{\mathrm{2}}}{\mathrm{2}{sin}\frac{\alpha−\beta}{\mathrm{2}}{cos}\frac{\alpha+\beta}{\mathrm{2}}}={a} \\ $$$$\Rightarrow{cot}\frac{\alpha−\beta}{\mathrm{2}}={a} \\…
Question Number 210974 by bns970 last updated on 25/Aug/24 $$\sqrt{\mathrm{25}} \\ $$ Answered by TonyCWX08 last updated on 25/Aug/24 $$\sqrt{\mathrm{25}} \\ $$$$=\pm\mathrm{5} \\ $$ Commented…
Question Number 210875 by peter frank last updated on 20/Aug/24 Answered by mahdipoor last updated on 20/Aug/24 $${get}\:{time}\:{is}\:{h}\::\:{m}\:\&\:{vertical}\:{line}\:{is}\:{refrence} \\ $$$${angle}\:{huur\_hand}\::\:\frac{\mathrm{360}}{\mathrm{12}}{h}+\frac{\mathrm{360}}{\mathrm{12}×\mathrm{60}}{m} \\ $$$${angle}\:{minute\_hand}\::\:\frac{\mathrm{360}}{\mathrm{60}}{m} \\ $$$$\Rightarrow\angle=\mid{h}−{m}\mid=\mid\mathrm{30}{h}−\mathrm{5}.\mathrm{5}{m}\mid\:{or}\:\mathrm{360}−\mid\mathrm{30}{h}−\mathrm{5}.\mathrm{5}{m}\mid \\…
Question Number 210719 by lmcp1203 last updated on 17/Aug/24 $${find}\:\mathrm{63}!^{\mathrm{36}!} {mod}\mathrm{97}\:\:\:{thanks} \\ $$ Answered by A5T last updated on 19/Aug/24 $$\phi\left(\mathrm{97}\right)=\mathrm{96} \\ $$$$\mathrm{36}!\equiv\mathrm{0}\left({mod}\:\mathrm{96}\right)\Rightarrow\mathrm{36}!=\mathrm{96}{k} \\ $$$$\left(\mathrm{63}!,\mathrm{97}\right)=\mathrm{1}\Rightarrow\mathrm{63}!^{\mathrm{36}!}…
Question Number 210605 by peter frank last updated on 13/Aug/24 Answered by A5T last updated on 13/Aug/24 $${a}=\mathrm{2}^{{x}} ;{b}=\mathrm{2}^{{y}} \Rightarrow{a}+{b}=\mathrm{18};\frac{{a}}{{b}}=\mathrm{5}\Rightarrow{a}=\mathrm{5}{b} \\ $$$$\Rightarrow\mathrm{6}{b}=\mathrm{18}\Rightarrow{b}=\mathrm{3}\Rightarrow{a}=\mathrm{15} \\ $$$$\mathrm{2}^{{x}+{y}} ={ab}=\mathrm{15}×\mathrm{3}=\mathrm{45}…
Question Number 210607 by peter frank last updated on 13/Aug/24 Answered by A5T last updated on 14/Aug/24 $$\mathrm{75}\left(\mathrm{5}^{\mathrm{3}{log}_{\mathrm{2}} {x}} \right)=\mathrm{75}\left(\mathrm{2}^{{log}_{\mathrm{2}} \mathrm{5}} \right)^{{log}_{\mathrm{2}} {x}×\mathrm{3}} =\mathrm{75}\left(\mathrm{2}^{{log}_{\mathrm{2}} {x}}…
Question Number 210456 by peter frank last updated on 09/Aug/24 Commented by mr W last updated on 09/Aug/24 $${who}\:{knows}\:{what}\:{is}\:\mathrm{2}\:{and}\:{what}\:{is}\:{z} \\ $$$${when}\:{you}\:{write}\:{them}\:{identically}? \\ $$ Commented by…
Question Number 209892 by lmcp1203 last updated on 25/Jul/24 $${find}\:\:\mathrm{40}^{\mathrm{71}} {mod}\:\mathrm{437}.\:\:\:{thanks} \\ $$$${its}\:\mathrm{67}\:{but}\:{how}? \\ $$ Answered by Rasheed.Sindhi last updated on 25/Jul/24 $$\mathrm{40}^{\mathrm{25}} \equiv\mathrm{14}\:\left({mod}\:\mathrm{437}\right) \\…