Category: Arithmetic

Question Number 211979 by Spillover last updated on 25/Sep/24 Answered by BHOOPENDRA last updated on 25/Sep/24 $$\int \frac{dx}{(x^2{\tan }^{-1}x+{\tan }^{-1}x+x^2\pi +\pi )}$$$$\int\frac{{dx}}{\left({x}^{\mathrm{2}} +\mathrm{1}\right)\left(\mathrm{tan}^{−\mathrm{1}} {x}+\pi\right)}…

Question Number 211895 by Spillover last updated on 23/Sep/24 Answered by mehdee7396 last updated on 23/Sep/24 $${lim}_{x\to \mathrm{\infty }}(1+\frac{a}{x}-\frac{4}{x^2}-1)2x$$$$={lim}_{x\to \mathrm{\infty }}\left(\frac{ax-4}{x^2}\right)2x=2a$$$$\Rightarrow{lim}_{{x}\rightarrow\infty}…

Question Number 211873 by Spillover last updated on 22/Sep/24 Answered by IbtisamAdnan last updated on 23/Sep/24 $${\mathbf{lim}}_{\mathbf{x}\to 4}\frac{{\left(\mathbf{cos}\mathit{\alpha }\right)}^{\mathrm{x}}-{\left(\sin \alpha \right)}^{\mathrm{x}}-\cos 2\alpha }{\mathrm{x}-4}$$$$\boldsymbol{\mathrm{lim}}_{\boldsymbol{\mathrm{x}}\rightarrow\mathrm{4}} \:\frac{\left(\boldsymbol{\mathrm{cos}\alpha}\right)^{\mathrm{x}} .\:\mathrm{ln}\:\mathrm{cos}\alpha\:\:−\:\left(\mathrm{sin}\:\alpha\right)^{\mathrm{x}} .\mathrm{ln}\:\mathrm{sin}\alpha}{\mathrm{1}}\left[\mathrm{L}\:\mathrm{hospital}\:\mathrm{rule}\right]…

Question Number 211636 by BaliramKumar last updated on 15/Sep/24 Answered by Rasheed.Sindhi last updated on 15/Sep/24 $$▸A=x^{8k+3}+x^{8k+6}+x^{8k+9}+x^{8k+12}$$$$\:\:\:\:\:\:\:\:={x}^{\mathrm{8}{k}+\mathrm{3}} \left(\mathrm{1}+{x}^{\mathrm{3}} +{x}^{\mathrm{6}} +{x}^{\mathrm{9}}…

Question Number 211231 by peter frank last updated on 01/Sep/24 Terms of Service Privacy Policy Contact: info@tinkutara.com