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Category: Arithmetic

Question-57770

Question Number 57770 by Tawa1 last updated on 11/Apr/19 Answered by Kunal12588 last updated on 11/Apr/19 13k=11sin(π4+(k1)π6)sin(π4+kπ6)sin(π4+(k1)π6)sin(π4+kπ6)=sin(3π+2(k1)π12)sin(3π+2kπ12)$$={sin}\left(\frac{\left(\mathrm{2}{k}+\mathrm{1}\right)\pi}{\mathrm{12}}\right){sin}\left(\frac{\left(\mathrm{2}{k}+\mathrm{3}\right)\pi}{\mathrm{12}}\right)…

1-2-2-3-3-4-24-25-

Question Number 188564 by BaliramKumar last updated on 03/Mar/23 1×2+2×3+3×4++24×25=? Answered by universe last updated on 03/Mar/23 $$\left(\mathrm{1}^{\mathrm{2}} +\mathrm{1}\right)+\left(\mathrm{2}^{\mathrm{2}} +\mathrm{2}\right)+\left(\mathrm{3}^{\mathrm{2}} +\mathrm{3}\right)+……\left(\mathrm{24}^{\mathrm{2}} +\mathrm{24}\right) \