Category: Arithmetic

Question Number 188442 by BaliramKumar last updated on 03/Mar/23 $$$$$$Solvebycomputerprograming$$$$\left(ifpossible\right)d<a<b\mathrm{\&}c<a,b>2c$$$$\cancel{a^2+b^2=5c^2+2d^2}(a,b,c,d\in \mathrm{N})$$$${c}^{\mathrm{2}} +{d}^{\mathrm{2}} \:=\:{a}^{\mathrm{2}} \:\:\:\:\:\:\:\:………\left({i}\right)…

Question Number 188375 by Rupesh123 last updated on 28/Feb/23 Commented by Frix last updated on 28/Feb/23 $$M=45\mathrm{at}x=-\frac{17}{2}$$ Commented by Rupesh123 last updated on…

Question Number 122608 by bramlexs22 last updated on 18/Nov/20 $$Sumtheseriesto{10}^{th}terms$$$$\frac{1}{1+\sqrt{x}}+\frac{1}{1-x}+\frac{1}{1-\sqrt{x}}+\dots$$$$equalto\mathrm{\_}\mathrm{\_}\mathrm{\_}$$ Answered by liberty last updated on 18/Nov/20 $$\:\mathrm{T}_{\mathrm{1}}…

Question Number 122484 by JBocanegra last updated on 17/Nov/20 $$\frac{4a}{3b\cdot 2^{\frac{1}{3}}\cdot a^{\frac{2}{3}}\cdot b^{\frac{1}{3}}}$$$$\left(\frac{4}{3\cdot 2^{\frac{1}{3}}}\right)\left(\frac{a}{a^{\frac{2}{3}}\cdot b^{\frac{4}{3}}}\right)$$$$\left(\frac{\mathrm{2}^{\mathrm{2}} }{\mathrm{3}\centerdot\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{3}}} }\right)\left({a}^{\mathrm{1}−\frac{\mathrm{2}}{\mathrm{3}}} \centerdot{b}^{−\frac{\mathrm{4}}{\mathrm{3}}} \right)=\left(\mathrm{2}^{\mathrm{2}−\frac{\mathrm{1}}{\mathrm{3}}} \right)\left({a}^{\frac{\mathrm{1}}{\mathrm{3}}}…

Question Number 56857 by azam2412 last updated on 25/Mar/19 $$romi-romo=0$$$$\mathcal{L}.x_0+\mathcal{G}.y_n=\mathcal{L}.x_n+\mathcal{G}.y_0$$$$\mathcal{L}(x_0-x_n)=\mathcal{G}(y_0-y_n)$$$${y}_{\mathrm{0}} =\frac{\mathcal{L}}{\mathcal{G}}.\left({x}_{\mathrm{0}} −{x}_{{n}}…