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Category: Arithmetic

Determine-the-integer-which-can-be-written-N-xyz-7-zyx-11-

Question Number 119440 by mathocean1 last updated on 24/Oct/20 $$\mathrm{Determine}\:\mathrm{the}\:\mathrm{integer}\:\mathrm{which}\:\mathrm{can}\: \\ $$$$\mathrm{be}\:\mathrm{written}:\:\mathrm{N}=\overline {\mathrm{xyz}}\:^{\mathrm{7}} =\overline {\mathrm{zyx}}\:^{\mathrm{11}} \\ $$ Commented by mathocean1 last updated on 24/Oct/20 $$\mathrm{Please}\:\mathrm{can}\:\mathrm{you}\:\mathrm{detail}\:\mathrm{sir}…

675-54-100-

Question Number 119241 by harenderkumar last updated on 23/Oct/20 $$\mathrm{675}×\mathrm{54}/\mathrm{100} \\ $$ Answered by sahiljakhar04 last updated on 23/Oct/20 $$\mathrm{675}×\frac{\mathrm{54}}{\mathrm{100}}\:=\:\frac{\mathrm{675}×\mathrm{54}}{\mathrm{100}}\:=\:\frac{\mathrm{27}×\mathrm{27}}{\mathrm{4}}\:=\frac{\left(\mathrm{27}\right)^{\mathrm{2}} }{\left(\mathrm{2}\right)^{\mathrm{2}} }\:=\left(\frac{\mathrm{27}}{\mathrm{2}}\right)^{\mathrm{2}} \\ $$$$\Rightarrow\:\left(\mathrm{13}.\mathrm{5}\right)^{\mathrm{2}} \:=\:\mathrm{182}.\mathrm{25}…

Question-119013

Question Number 119013 by zakirullah last updated on 21/Oct/20 Commented by zakirullah last updated on 21/Oct/20 $$\:\:\:\:\:\:\boldsymbol{{find}}\:\boldsymbol{{the}}\:\boldsymbol{{component}}\:\boldsymbol{{and}}\: \\ $$$$\:\:\:\:\:\:\boldsymbol{{the}}\:\boldsymbol{{magnitude}}\:\boldsymbol{{of}}\:\boldsymbol{{P}}\overset{\rightarrow} {\boldsymbol{{Q}}} \\ $$$${i}.\:\:\boldsymbol{{P}}\left(−\mathrm{1},\mathrm{2}\right),\:\boldsymbol{{Q}}\left(\mathrm{2},−\mathrm{1}\right) \\ $$$${ii}.\:\:\boldsymbol{{P}}\left(−\mathrm{2},\mathrm{1}\right),\:\boldsymbol{{Q}}\left(\mathrm{2},\mathrm{3}\right) \\…

find-x-1-x-1-x-2-x-2-x-x-1-

Question Number 53262 by Tawa1 last updated on 19/Jan/19 $$\mathrm{find}\:\mathrm{x}:\:\:\:\:\:\:\:\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{x}\:+\:\mathrm{1}\:+\:\sqrt{\mathrm{x}}}}\:\:−\:\:\frac{\mathrm{2}}{\:\sqrt{\mathrm{x}\:−\:\mathrm{2}\:+\:\sqrt{\mathrm{x}}}}\:\:=\:\:\sqrt{\mathrm{x}\:−\:\mathrm{1}} \\ $$ Commented by mr W last updated on 20/Jan/19 $${there}\:{is}\:{no}\:{real}\:{solution}! \\ $$$${LHS}: \\ $$$${say}\:{x}+\sqrt{{x}}={u}\:>\mathrm{2}…