Question Number 50445 by ANTARES VY last updated on 16/Dec/18 $$\boldsymbol{\mathrm{The}}\:\:\boldsymbol{\mathrm{roots}}\:\:\boldsymbol{\mathrm{of}}\:\:\boldsymbol{\mathrm{the}}\:\:\boldsymbol{\mathrm{fallowing}} \\ $$$$\boldsymbol{\mathrm{functions}}\:\:\boldsymbol{\mathrm{are}}\:\:\boldsymbol{\mathrm{the}}\:\:\boldsymbol{\mathrm{Sequences}}\:\:\boldsymbol{\mathrm{of}} \\ $$$$\boldsymbol{\mathrm{arithmetic}}\:\:\boldsymbol{\mathrm{progressiyon}} \\ $$$$\boldsymbol{\mathrm{f}}\left(\boldsymbol{\mathrm{x}}\right)=\boldsymbol{\mathrm{x}}^{\mathrm{5}} −\mathrm{20}\boldsymbol{\mathrm{x}}^{\mathrm{4}} +\boldsymbol{\mathrm{ax}}^{\mathrm{3}} +\boldsymbol{\mathrm{bx}}^{\mathrm{2}} +\boldsymbol{\mathrm{cx}}+\mathrm{24} \\ $$$$\boldsymbol{\mathrm{f}}\left(\mathrm{8}\right)=? \\ $$…
Question Number 181484 by Linton last updated on 25/Nov/22 $${If}\:{a}\:{hen}\:{and}\:{a}\:{half} \\ $$$${lay}\:{an}\:{egg}\:{and}\:{a}\:{half} \\ $$$${in}\:{a}\:{day}\:{and}\:{a}\:{half} \\ $$$${how}\:{many}\:{eggs}\:{would} \\ $$$${one}\:{hen}\:{lay}\:{in}\:{one} \\ $$$${day}? \\ $$ Commented by MJS_new…
Question Number 115856 by bemath last updated on 29/Sep/20 $${Which}\:{is}\:{greater} \\ $$$${P}\:=\:\left(\mathrm{1983}\right)\left(\mathrm{1}+\mathrm{2}+\mathrm{3}+…+\mathrm{1984}\right)\:,\:{or} \\ $$$${Q}\:=\:\left(\mathrm{1984}\right)\left(\mathrm{1}+\mathrm{2}+\mathrm{3}+…+\mathrm{1983}\right) \\ $$ Answered by bobhans last updated on 29/Sep/20 $${let}\:{z}\:=\:\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{4}+…+\mathrm{1983} \\…
Question Number 50248 by peter frank last updated on 15/Dec/18 Answered by mr W last updated on 15/Dec/18 $${P}\left({p},\frac{{c}^{\mathrm{2}} }{{p}}\right) \\ $$$${Q}\left({q},\frac{{c}^{\mathrm{2}} }{{q}}\right) \\ $$$${PQ}=\sqrt{\left({p}−{q}\right)^{\mathrm{2}}…
Question Number 181275 by Linton last updated on 23/Nov/22 $${what}\:{is}\:{the}\:{sum}\:{of}\:{all} \\ $$$${even}\:{factors}\:{of}\:\mathrm{1000}? \\ $$ Commented by Rasheed.Sindhi last updated on 24/Nov/22 ���� Commented by Linton…
Question Number 50135 by peter frank last updated on 14/Dec/18 Commented by maxmathsup by imad last updated on 01/Jan/19 $${let}\:{solve}\:\left(\mathrm{2}{x}−\mathrm{1}\right){y}^{''} \:−{y}^{'} =\mathrm{0}\:\:\:{withy}\left(\mathrm{0}\right)=\mathrm{2}\:{and}\:{y}^{'} \left(\mathrm{0}\right)=\mathrm{3}\:\:{let}\:{use}\:{changement} \\ $$$${y}^{'}…
Question Number 181039 by depressiveshrek last updated on 20/Nov/22 $${Prove}\:{that}\:{for}\:{all}\:{a}^{\mathrm{2}} \:{divisible}\:{by}\:{b}, \\ $$$${a}\:{is}\:{also}\:{divisible}\:{by}\:{b} \\ $$$${for}\:{all}\:{a},\:{b}\:\in\:\mathbb{N} \\ $$ Commented by mr W last updated on 20/Nov/22…
Question Number 180828 by Vynho last updated on 17/Nov/22 $${H}_{{n}} =\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+…+\frac{\mathrm{1}}{{n}} \\ $$$${H}_{\mathrm{2}{n}} =?\:{compute}\:{H}_{\mathrm{2}{n}} −{H}_{{n}} \:{and}\:{H}_{{n}+\mathrm{1}} −{H}_{{n}} \\ $$ Commented by Frix last updated on…
Question Number 49680 by peter frank last updated on 09/Dec/18 Answered by math1967 last updated on 09/Dec/18 $${Total}\:{surface}\:{area}\:=\mathrm{2}×\mathrm{6}×\frac{\sqrt{\mathrm{3}}}{\mathrm{4}}×\mathrm{20}^{\mathrm{2}} +\mathrm{6}×\mathrm{20}×\mathrm{15} \\ $$$$=\mathrm{3878}.\mathrm{46}{cm}^{\mathrm{2}} \left({aprox}\right) \\ $$$${Volume}=\frac{\sqrt{\mathrm{3}}}{\mathrm{4}}×\mathrm{6}×\mathrm{20}^{\mathrm{2}} ×\mathrm{15}=\mathrm{233826}.\mathrm{85}{cm}^{\mathrm{3}}…
Question Number 115194 by 1549442205PVT last updated on 24/Sep/20 $$\mathrm{Find}\:\mathrm{a}\:\mathrm{three}−\mathrm{digits}\:\mathrm{number}\:\mathrm{whose} \\ $$$$\mathrm{digits}\:\mathrm{form}\:\mathrm{a}\:\mathrm{geometry}\:\mathrm{progression} \\ $$$$;\mathrm{if}\:\mathrm{you}\:\mathrm{known}\:\mathrm{that}\:\mathrm{after}\:\mathrm{substract}\:\mathrm{that} \\ $$$$\mathrm{number}\:\mathrm{by}\:\mathrm{495}\:,\mathrm{get}\:\mathrm{a}\:\mathrm{number} \\ $$$$\mathrm{written}\:\mathrm{by}\:\mathrm{the}\:\mathrm{same}\:\mathrm{digits}\:\mathrm{as}\:\mathrm{the} \\ $$$$\mathrm{number}\:\mathrm{you}\:\mathrm{are}\:\mathrm{looking}\:\mathrm{for}\:\mathrm{but}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{reverse}\:\mathrm{order};\mathrm{if}\:\mathrm{the}\:\mathrm{digits}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{number}\:\mathrm{obtained}\:\mathrm{after} \\…