Question Number 48983 by peter frank last updated on 30/Nov/18 Answered by tanmay.chaudhury50@gmail.com last updated on 01/Dec/18 $$\left({x}−\mathrm{0}\right)^{\mathrm{2}} +\left({y}−\mathrm{0}\right)^{\mathrm{2}} =\mathrm{4}^{\mathrm{2}} \\ $$$${x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{1}+{y}^{\mathrm{2}} −\mathrm{4}{y}+\mathrm{4}=\mathrm{5} \\…
Question Number 48981 by peter frank last updated on 30/Nov/18 Answered by tanmay.chaudhury50@gmail.com last updated on 01/Dec/18 $$\left.\mathrm{1}\right)\frac{{dy}}{{dx}}={y}\leftarrow{ordinate} \\ $$$$\frac{{dy}}{{y}}={dx}\:\:{so}\:\int\frac{{dy}}{{y}}=\int{dx} \\ $$$${lny}={x}+{lnc} \\ $$$${ln}\left(\frac{{y}}{{c}}\right)={x} \\…
Question Number 48976 by peter frank last updated on 30/Nov/18 Answered by $@ty@m last updated on 01/Dec/18 $${L}=\mathrm{3}{B}−\mathrm{4}\:…\left(\mathrm{1}\right) \\ $$$${b}={B}−\mathrm{2}\:…\left(\mathrm{2}\right) \\ $$$${l}=\mathrm{2}{b}+\mathrm{2}…\left(\mathrm{3}\right) \\ $$$${L}.{B}−{lb}=\mathrm{44}\:…\left(\mathrm{4}\right) \\…
Question Number 48966 by peter frank last updated on 30/Nov/18 Commented by tanmay.chaudhury50@gmail.com last updated on 30/Nov/18 $${purchase}\:{good}\:{books}\:{from}\:{market}..{stop}\:{reading} \\ $$$${non}\:{standard}\:{books}.. \\ $$ Commented by peter…
Question Number 48958 by Rio Michael last updated on 30/Nov/18 $${Given}\:{the}\:{position}\:{vectors}\:{v}_{\mathrm{1}} =\:\mathrm{2}\boldsymbol{{i}}−\mathrm{2}\boldsymbol{{j}}\:{and}\:{v}_{\mathrm{2}} =\mathrm{2}\boldsymbol{{j}} \\ $$$$\left.{a}\right)\:{show}\:{that}\:{the}\:{unit}\:{vector}\:{in}\:{the}\:{direction}\:{of}\:{v}_{\mathrm{1}} −{v}_{\mathrm{2}} =\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}\left({i}−\mathrm{2}{j}\right) \\ $$$$\left.{b}\right)\:{Write}\:{down}\:{the}\:{equation}\:{of}\:{the}\:{line}\:{that}\:{contains} \\ $$$${the}\:{position}\:{vectors}\:{v}_{\mathrm{1}} \:{and}\:{v}_{\mathrm{2}} \\ $$$$\left.{c}\right)\:{Find}\:{the}\:{cosine}\:{of}\:{the}\:{angle}\:{between}\:{v}_{\mathrm{1}} \:{and}\:{v}_{\mathrm{2}}…
Question Number 114461 by Jamshidbek2311 last updated on 19/Sep/20 Commented by bemath last updated on 19/Sep/20 $$\mid\left({x}+\mathrm{2}\right)\left({x}+\mathrm{5}\right)\mid\:+\:\mathrm{10}\mid\left({x}−\mathrm{2}\right)\left({x}+\mathrm{2}\right)>\mid\left(\mathrm{2}{x}+\mathrm{3}\right)\left({x}+\mathrm{2}\right)\mid \\ $$$$\mid{x}+\mathrm{2}\mid\:\left\{\mid{x}+\mathrm{5}\mid−\mathrm{10}\mid{x}−\mathrm{2}\mid−\mid\mathrm{2}{x}+\mathrm{3}\mid\right\}>\mathrm{0} \\ $$$${now}\:{its}\:{can}\:{solve} \\ $$$$ \\ $$…
Question Number 48921 by peter frank last updated on 30/Nov/18 Commented by maxmathsup by imad last updated on 30/Nov/18 $${we}\:{have}\:{cos}\left(\mathrm{3}\theta\right)\:\sim\mathrm{1}−\frac{\mathrm{9}\theta^{\mathrm{2}} }{\mathrm{2}}\:\:\:\left(\theta\rightarrow\mathrm{0}\right)\:{and}\:{cos}\theta\:\sim\mathrm{1}−\frac{\theta^{\mathrm{2}} }{\mathrm{2}} \\ $$$${cos}\left(\mathrm{4}\theta\right)\sim\:\mathrm{1}−\mathrm{8}\theta^{\mathrm{2}} \:\:\:{and}\:{cos}\left(\mathrm{2}\theta\right)\sim\mathrm{1}−\mathrm{2}\theta^{\mathrm{2}}…
Question Number 48872 by peter frank last updated on 29/Nov/18 Commented by mr W last updated on 29/Nov/18 $$\left.{i}\right)\:{ellipse} \\ $$$$\left.{i}\left.{i}\right)\:{and}\:{iii}\right)\:{parabola} \\ $$ Terms of…
Question Number 48871 by peter frank last updated on 29/Nov/18 Commented by maxmathsup by imad last updated on 01/Jan/19 $$\left.\mathrm{2}\right)\:{we}\:{have}\:{x}^{\mathrm{2}} −\mathrm{2}{x}−\mathrm{3}\:={x}^{\mathrm{2}} +{x}−\mathrm{3}{x}−\mathrm{3}\:={x}\left({x}+\mathrm{1}\right)−\mathrm{3}\left({x}+\mathrm{1}\right)=\left({x}+\mathrm{1}\right)\left({x}−\mathrm{3}\right)\Rightarrow \\ $$$${f}\left({x}\right)=\frac{{x}\left({x}+\mathrm{1}\right)}{\left({x}+\mathrm{1}\right)\left({x}−\mathrm{3}\right)}\:{and}\:{for}\:{x}\neq−\mathrm{1}\:{f}\left({x}\right)=\frac{{x}}{{x}−\mathrm{3}}\:\:{but}\:{remember}\:{that} \\…
Question Number 114326 by 1549442205PVT last updated on 18/Sep/20 $$\left.\mathrm{a}\right)\mathrm{Find}\:\mathrm{a}\:\mathrm{four}−\mathrm{digit}\:\mathrm{number}\:\mathrm{that} \\ $$$$\mathrm{satisfies}\:\mathrm{the}\:\mathrm{following}\:\mathrm{condition}: \\ $$$$\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{squares}\:\mathrm{of}\:\mathrm{the}\:\mathrm{extreme}\:\mathrm{digits} \\ $$$$\mathrm{is}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{13};\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{squares}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{middle}\:\mathrm{digits}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{85};\mathrm{if}\:\mathrm{we} \\ $$$$\mathrm{substract}\:\mathrm{1089}\:\mathrm{from}\:\mathrm{the}\:\mathrm{desired} \\ $$$$\mathrm{number}\:\mathrm{we}\:\mathrm{obtain}\:\mathrm{a}\:\mathrm{number}\:\mathrm{containing} \\ $$$$\mathrm{the}\:\mathrm{same}\:\mathrm{digits}\:\mathrm{as}\:\mathrm{the}\:\mathrm{desired}\:\mathrm{number} \\…