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Category: Arithmetic

Question-180498

Question Number 180498 by Spillover last updated on 12/Nov/22 Commented by Frix last updated on 13/Nov/22 morechallengingextrawork:$$\omega=\frac{\left(\frac{\mathrm{log}_{{a}^{\mathrm{3}} +{b}^{\mathrm{4}} } ^{\mathrm{2}} \:{z}}{\mathrm{25}}−{R}^{\mathrm{2}} \right)^{\frac{\mathrm{1}}{\mathrm{3}}} \pm\left(\left(\left(\frac{\mathrm{log}_{{a}^{\mathrm{3}}…