Question Number 178992 by Spillover last updated on 23/Oct/22 Answered by som(math1967) last updated on 23/Oct/22 $$\theta_{\mathrm{2}} −\theta_{\mathrm{1}} =\theta_{\mathrm{3}} −\theta_{\mathrm{2}} =…=\theta_{{n}} −\theta_{{n}−\mathrm{1}} ={d} \\ $$$${sec}\theta_{\mathrm{1}}…
Question Number 178993 by Spillover last updated on 23/Oct/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 178994 by Spillover last updated on 23/Oct/22 Commented by Spillover last updated on 23/Oct/22 Answered by mr W last updated on 23/Oct/22 $${say}\:{the}\:{digits}\:{are}\:{a},{b},{c}\:{from}\:{left}\:{to}…
Question Number 178969 by Tawa11 last updated on 23/Oct/22 "How many integers between 100 – 999 inclusive consist of distinct odd digit" Answered by Rasheed.Sindhi…
Question Number 178932 by cherokeesay last updated on 22/Oct/22 Answered by MJS_new last updated on 23/Oct/22 $${S}_{{n}} =\underset{{j}=\mathrm{1}} {\overset{{n}} {\sum}}\mathrm{8}^{{j}} =\frac{\mathrm{8}}{\mathrm{7}}\left(\mathrm{8}^{{n}} −\mathrm{1}\right) \\ $$$${S}_{\mathrm{1}} =\mathrm{8}=\mathrm{0}×\mathrm{73}+\mathrm{8}…
Question Number 113374 by Aina Samuel Temidayo last updated on 12/Sep/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{next}\:\mathrm{term}\:\mathrm{in}\:\mathrm{this} \\ $$$$\mathrm{sequence}:\:\mathrm{26},\mathrm{63},\mathrm{124},\:\_\_ \\ $$ Commented by Tony6400 last updated on 13/Sep/20 Ans is 209 Commented…
Question Number 178869 by ARUNG_Brandon_MBU last updated on 22/Oct/22 Answered by Rasheed.Sindhi last updated on 22/Oct/22 $$\:\:\:\:\:\:\:\:\:\begin{array}{|c|c|c|c|c|}{\:\mathrm{2}\:}&\hline{\:\:\:\:\:\:\:\:\mathrm{4}}&\hline{\:\mathrm{8}}\\{\:}&\hline{\:}&\hline{\:}\\{\:\mathrm{7}}&\hline{\:}&\hline{\:\mathrm{3}}\\{\:}&\hline{\:\begin{array}{|c|}{?=\mathrm{1}}\\\hline\end{array}\:}&\hline{\:}\\{\:\mathrm{5}}&\hline{\:}&\hline{\:\mathrm{6}\:}\\\hline\end{array}\:\: \\ $$ Commented by ARUNG_Brandon_MBU last updated on…
Question Number 178870 by ARUNG_Brandon_MBU last updated on 22/Oct/22 Answered by Rasheed.Sindhi last updated on 22/Oct/22 $$\mathrm{Rule}: \\ $$$$\begin{array}{|c|c|c|}{\begin{array}{|c|}{{a}}\\\hline\end{array}}&\hline{\:\:\:\:\:}&\hline{\begin{array}{|c|}{{b}}\\\hline\end{array}}\\{\:\:\:}&\hline{\begin{array}{|c|}{\frac{{ad}+{bc}}{\mathrm{2}}}\\\hline\end{array}}&\hline{\:\:}\\{\begin{array}{|c|}{{c}}\\\hline\end{array}}&\hline{\:\:\:}&\hline{\begin{array}{|c|}{{d}}\\\hline\end{array}}\\\hline\end{array}\:\:\: \\ $$$$\mathrm{Applying}\:\mathrm{rule}: \\ $$$$\begin{array}{|c|c|c|}{\begin{array}{|c|}{{x}+\mathrm{2}}\\\hline\end{array}}&\hline{\:\:\:\:\:}&\hline{\begin{array}{|c|}{{x}+\mathrm{1}}\\\hline\end{array}}\\{\:\:\:}&\hline{\begin{array}{|c|}{\frac{\left({x}+\mathrm{2}\right)\left(\mathrm{3}\right)+\left({x}\right)\left({x}+\mathrm{1}\right)}{\mathrm{2}}=\mathrm{1}}\\\hline\end{array}}&\hline{\:\:}\\{\begin{array}{|c|}{\:\:\:\:{x}\:\:\:}\\\hline\end{array}}&\hline{\:\:\:}&\hline{\begin{array}{|c|}{\:\:\:\:\mathrm{3}\:\:}\\\hline\end{array}}\\\hline\end{array} \\ $$$$\:\:\:\frac{\left({x}+\mathrm{2}\right)\left(\mathrm{3}\right)+\left({x}\right)\left({x}+\mathrm{1}\right)}{\mathrm{2}}=\mathrm{1}…
Question Number 113261 by Aina Samuel Temidayo last updated on 12/Sep/20 $$\frac{\sqrt{\sqrt{\mathrm{5}}+\mathrm{2}}+\sqrt{\sqrt{\mathrm{5}}−\mathrm{2}}}{\:\sqrt{\sqrt{\mathrm{5}}+\mathrm{1}}}−\sqrt{\mathrm{3}−\mathrm{2}\sqrt{\mathrm{2}}} \\ $$ Answered by som(math1967) last updated on 12/Sep/20 $$\mathrm{let}\:\mathrm{p}=\sqrt{\sqrt{\mathrm{5}}+\mathrm{2}}+\sqrt{\sqrt{\mathrm{5}}−\mathrm{2}} \\ $$$$\mathrm{p}^{\mathrm{2}} =\sqrt{\mathrm{5}}+\mathrm{2}+\sqrt{\mathrm{5}}−\mathrm{2}+\mathrm{2}\sqrt{\left(\sqrt{\mathrm{5}}\right)^{\mathrm{2}}…
Question Number 113097 by nimnim last updated on 11/Sep/20 $$\mathrm{If}\:\mathrm{4}\:\mathrm{women}\:\mathrm{earn}\:\mathrm{as}\:\mathrm{much}\:\mathrm{as}\:\mathrm{9}\:\mathrm{boys};\:\mathrm{4}\:\mathrm{men}\:\mathrm{as}\:\mathrm{much}\:\mathrm{as} \\ $$$$\mathrm{15}\:\mathrm{boys};\:\mathrm{27}\:\mathrm{girls}\:\mathrm{as}\:\mathrm{much}\:\mathrm{as}\:\mathrm{20}\:\mathrm{women},\:\mathrm{how}\:\mathrm{many}\:\mathrm{girls} \\ $$$$\mathrm{will}\:\mathrm{earn}\:\mathrm{the}\:\mathrm{same}\:\mathrm{amount}\:\mathrm{as}\:\mathrm{24}\:\mathrm{men}? \\ $$ Answered by 1549442205PVT last updated on 11/Sep/20 $$\mathrm{4}\:\mathrm{men}\:\mathrm{as}\:\mathrm{much}\:\mathrm{as}\:\mathrm{15}\:\mathrm{boys} \\…