Question Number 47185 by peter frank last updated on 05/Nov/18 Commented by MrW3 last updated on 07/Nov/18 $${the}\:{question}\:{is}\:{not}\:{clear}\:{sir}. \\ $$$${please}\:{post}\:{a}\:{picture}\:{showing}\:\:{where} \\ $$$${are}\:{the}\:{points}\:{P}\:{and}\:{Q}. \\ $$$$ \\…
Question Number 47111 by peter frank last updated on 04/Nov/18 Commented by MrW3 last updated on 04/Nov/18 $$\frac{\mathrm{4}!/\mathrm{2}!}{\mathrm{7}!/\mathrm{3}!/\mathrm{2}!}=\frac{\mathrm{4}!\mathrm{3}!}{\mathrm{7}!}=\frac{\mathrm{3}×\mathrm{2}×\mathrm{1}}{\mathrm{7}×\mathrm{6}×\mathrm{5}}=\frac{\mathrm{1}}{\mathrm{35}} \\ $$ Commented by peter frank last…
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Question Number 46860 by 786786AM last updated on 01/Nov/18 $$\:\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{to}\:\mathrm{infinity}\:\mathrm{whose}\:\mathrm{n}^{\mathrm{th}} \:\mathrm{term}\:\mathrm{is}\:\frac{\mathrm{n}}{\mathrm{2}^{\mathrm{n}−\mathrm{1}} }\:. \\ $$ Commented by maxmathsup by imad last updated on 01/Nov/18 $${let}\:{s}\left({x}\right)=\sum_{{n}=\mathrm{1}} ^{\infty}…
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Question Number 46829 by peter frank last updated on 01/Nov/18 Answered by tanmay.chaudhury50@gmail.com last updated on 01/Nov/18 $${eqn}\:{of}\:{focal}\:{chord}\:{is} \\ $$$${y}={tan}\theta\left({x}−\sqrt{{a}^{\mathrm{2}} −{b}^{\mathrm{2}} }\:\right)\:{focaus}\left(\sqrt{{a}^{\mathrm{2}} −{b}^{\mathrm{2}} }\:,\mathrm{0}\right) \\…
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Question Number 46816 by peter frank last updated on 31/Oct/18 Answered by tanmay.chaudhury50@gmail.com last updated on 01/Nov/18 $${slope}\:{M}_{\mathrm{1}} =\frac{\frac{{a}}{{m}_{\mathrm{2}\:} }−\frac{{a}}{{m}_{\mathrm{1}} }}{{a}\left({m}_{\mathrm{2}} −{m}_{\mathrm{1}} \right)} \\ $$$$\:\:\:\:\:{M}_{\mathrm{1}}…
Question Number 46813 by peter frank last updated on 31/Oct/18 Commented by peter frank last updated on 02/Nov/18 $$\mathrm{help}\:\mathrm{please} \\ $$ Answered by ajfour last…
Question Number 46814 by peter frank last updated on 31/Oct/18 Answered by tanmay.chaudhury50@gmail.com last updated on 01/Nov/18 $${cos}\theta=\frac{{OP}^{\mathrm{2}} +{OQ}^{\mathrm{2}} −{PQ}^{\mathrm{2}} }{\mathrm{2}×{OP}×{OQ}} \\ $$$$\:\:\:=\frac{\left({a}^{\mathrm{2}} +{b}^{\mathrm{2}} \right)+\left({c}^{\mathrm{2}}…