Question Number 44325 by Rio Michael last updated on 26/Sep/18 Commented by Rio Michael last updated on 26/Sep/18 $${The}\:{farm}\:{land}\:{above}\:{has}\:{lenght}\:\mathrm{80}{m}\:{and}\:{width}\:\mathrm{25}{m},{it}\: \\ $$$${seperated}\:{by}\:{paths}\:{of}\:{width}\:\mathrm{1}{m}\:{to}\:{two}\:{farm}\:{lands}\:{as}\:{shown} \\ $$$${above}.{find}\:{the}\:{total}\:{area}\:{of}\:{the}\:{paths}. \\ $$…
Question Number 44324 by Rio Michael last updated on 26/Sep/18 $$\:\:\:\:\:\:\:\:\:\mathrm{5}\:\mathrm{2}\:{a} \\ $$$$\:\:\:\:+\:\:\:\:\mathrm{3}\:\:\mathrm{5} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\_\_\_\:\:\:\:\:{the}\:{addition}\:{on}\:{the}\:{left}\:{is}\:{in}\:{base}\:\mathrm{6}.{find}\:{a}. \\ $$$$\:\:\:\:\:\:\:\:\mathrm{1001} \\ $$ Answered by MJS last updated on…
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Question Number 44222 by Necxx last updated on 23/Sep/18 $${A}\:{man}\:{borrowed}\:{x}\:{at}\:\mathrm{5\%}\:{per}\:{annum} \\ $$$${simple}\:{interest}.{He}\:{paid}\:\mathrm{198000}\: \\ $$$${after}\:\mathrm{2}{years}.{Calculate}\:_{} \\ $$$$\left.{a}\right){the}\:{value}\:{of}\:{x} \\ $$$$\left.{b}\right){simple}\:{interest} \\ $$ Answered by olj55336@awsoo.com last updated…
Question Number 109746 by Joel574 last updated on 25/Aug/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\underset{{n}\:=\:\mathrm{0}} {\overset{\mathrm{2020}} {\sum}}\:\left[\frac{\mathrm{2}^{{n}} }{\mathrm{1}\:+\:\mathrm{3}^{\left(\mathrm{2}^{{n}} \right)} }\right] \\ $$ Commented by Her_Majesty last updated on…
Question Number 44094 by peter frank last updated on 21/Sep/18 Commented by tanmay.chaudhury50@gmail.com last updated on 22/Sep/18 $${is}\:{it}\:{z}^{\mathrm{5}} \:\:\:{or}\:{z}^{\mathrm{3}} \:\:\:{pls}\:{clarify} \\ $$ Commented by peter…
Question Number 175103 by Tawa11 last updated on 19/Aug/22 $$\mathrm{If}\:\:\mathrm{20}\:\left(\mathrm{mod}\:\mathrm{9}\right)\:\:\mathrm{is}\:\mathrm{equivalent}\:\mathrm{to}\:\:\:\mathrm{y}\:\left(\mathrm{mod}\:\mathrm{6}\right).\:\:\mathrm{Find}\:\:\mathrm{y} \\ $$ Answered by Rasheed.Sindhi last updated on 19/Aug/22 $$\mathrm{20}\left(\mathrm{mod}\:\mathrm{9}\right)=\mathrm{11} \\ $$$$\mathrm{y}\equiv\mathrm{11}\left(\mathrm{mod}\:\mathrm{6}\right) \\ $$$$\mathrm{y}\equiv\mathrm{11}−\mathrm{6}=\mathrm{5}\left(\mathrm{mod}\:\mathrm{6}\right) \\…
Question Number 175004 by saboorhalimi last updated on 15/Aug/22 Commented by kaivan.ahmadi last updated on 15/Aug/22 $${s}_{\mathrm{9}} =\mathrm{6}{s}_{\mathrm{6}} \Rightarrow\frac{\mathrm{9}}{\mathrm{2}}\left(\mathrm{2}{a}+\mathrm{8}{d}\right)=\mathrm{6}×\mathrm{3}\left(\mathrm{2}{a}+\mathrm{5}{d}\right) \\ $$$$\Rightarrow\mathrm{9}{a}+\mathrm{36}{d}=\mathrm{36}{a}+\mathrm{90}{d} \\ $$$$\Rightarrow−\mathrm{27}{a}=\mathrm{54}{d}\Rightarrow\mathrm{d}=\frac{−\mathrm{1}}{\mathrm{2}}\mathrm{a} \\ $$$$\mathrm{so}…
Question Number 174939 by BaliramKumar last updated on 14/Aug/22 $$\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{all}\:\mathrm{proper}\:\mathrm{factors}\:\mathrm{of}\:\mathrm{360}\:? \\ $$ Answered by JDamian last updated on 14/Aug/22 $$\mathrm{360}=\mathrm{2}^{\mathrm{3}} ×\mathrm{3}^{\mathrm{2}} ×\mathrm{5} \\ $$$$\frac{\mathrm{2}^{\mathrm{3}+\mathrm{1}} −\mathrm{1}}{\mathrm{2}−\mathrm{1}}×\frac{\mathrm{3}^{\mathrm{2}+\mathrm{1}}…
Question Number 43793 by gunawan last updated on 15/Sep/18 $$\mathrm{The}\:\mathrm{value}\:\mathrm{of}\:\:^{\mathrm{3}} \sqrt{\mathrm{20}+\mathrm{14}\sqrt{\mathrm{2}}}+^{\mathrm{3}} \sqrt{\mathrm{20}−\mathrm{14}\sqrt{\mathrm{2}}}\:\mathrm{is}\ldots \\ $$ Answered by Joel578 last updated on 15/Sep/18 $$\mathrm{Let}\:{a}\:=\:\mathrm{20}\:+\:\mathrm{14}\sqrt{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\:{b}\:=\:\mathrm{20}\:−\:\mathrm{14}\sqrt{\mathrm{2}} \\…