Question Number 206353 by BaliramKumar last updated on 12/Apr/24 Commented by Rasheed.Sindhi last updated on 15/Apr/24 $${I}\:{think}\:\mathrm{15}\:{is}\:{wrong}\:{here},\:{it}\:{should} \\ $$$${be}\:\mathrm{14}\:{or}\:{otherwise}\:{the}\:{answer}\:{is} \\ $$$${not}\:{correct}. \\ $$ Commented by…
Question Number 206309 by BaliramKumar last updated on 11/Apr/24 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{ways}\:\mathrm{to}\:\mathrm{express}\:\mathrm{11025}\: \\ $$$$\mathrm{as}\:\mathrm{product}\:\mathrm{of}\:\mathrm{two}\:\mathrm{factors}. \\ $$$$\left(\mathrm{a}\right)\:\mathrm{13}\:\:\:\:\:\:\:\:\:\left(\mathrm{b}\right)\:\mathrm{14}\:\:\:\:\:\:\:\:\left(\mathrm{c}\right)\:\mathrm{26}\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{d}\right)\:\mathrm{27} \\ $$ Answered by TheHoneyCat last updated on 11/Apr/24 $$\mathrm{11025} \\…
Question Number 206253 by mnjuly1970 last updated on 10/Apr/24 $$\:\:\: \\ $$$$\:\:\:\:\:\:\:{f}\left({x}\right)=\:{log}_{\:\mathrm{2}} \:\left(\:{x}\:+\:\mathrm{2}\sqrt{{x}}\:+\mathrm{4}\:\right) \\ $$$$\:\:\:\:\:\:\:\Rightarrow\:\:{f}^{\:−\mathrm{1}} \left(\:\mathrm{13}\:−\mathrm{4}\sqrt{\mathrm{3}}\:\right)\:=\:? \\ $$$$\:\:\:\:\:\:\:−−−−− \\ $$$$\:\:\:\: \\ $$ Answered by cortano21…
Question Number 206230 by BaliramKumar last updated on 09/Apr/24 $$\mathrm{Expand}\:\:\:\:{x}^{\mathrm{2}} \:+\:\mathrm{2}{x}\:+\:\mathrm{3}\:\:\:{respect}\:{to}\:{x}\:=\:−\mathrm{2}. \\ $$$$\left(\mathrm{a}\right)\:\left({x}\:−\:\mathrm{2}\right)^{\mathrm{2}} −\mathrm{2}\left({x}\:+\:\mathrm{2}\right)\:+\:\mathrm{3} \\ $$$$\left(\mathrm{b}\right)\:\left({x}\:+\:\mathrm{2}\right)^{\mathrm{2}} −\mathrm{2}\left({x}\:+\:\mathrm{2}\right)\:+\:\mathrm{3} \\ $$$$\left(\mathrm{c}\right)\:\left({x}\:+\:\mathrm{2}\right)^{\mathrm{2}} +\:\mathrm{2}\left({x}\:+\:\mathrm{2}\right)\:+\:\mathrm{3} \\ $$$$\left(\mathrm{d}\right)\:\left({x}\:−\:\mathrm{2}\right)^{\mathrm{2}} −\mathrm{2}\left({x}\:−\:\mathrm{2}\right)\:−\:\mathrm{3} \\ $$$$…
Question Number 206038 by BaliramKumar last updated on 05/Apr/24 $$\sqrt{\mathrm{1}\:+\:\mathrm{2023}\sqrt{\mathrm{1}\:+\:\mathrm{2024}\sqrt{\mathrm{1}+\:\mathrm{2025}\sqrt{\mathrm{1}\:+\:\mathrm{2026}\sqrt{\mathrm{1}\:+\:…………..\infty}}}}}\:=\:?\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$ Answered by mr W last updated on 05/Apr/24 $${x}+\mathrm{1}=\sqrt{\mathrm{1}+{x}\sqrt{\mathrm{1}+\left({x}+\mathrm{1}\right)\sqrt{\mathrm{1}+\left({x}+\mathrm{2}\right)\sqrt{\mathrm{1}+…}}}} \\ $$$$\Rightarrow\mathrm{2024}=\sqrt{\mathrm{1}\:+\:\mathrm{2023}\sqrt{\mathrm{1}\:+\:\mathrm{2024}\sqrt{\mathrm{1}+\:\mathrm{2025}\sqrt{\mathrm{1}\:+\:\mathrm{2026}\sqrt{\mathrm{1}\:+\:…………..\infty}}}}} \\ $$…
Question Number 205893 by BaliramKumar last updated on 02/Apr/24 Commented by BaliramKumar last updated on 02/Apr/24 $$−\mathrm{33}\:\mathrm{or}\:−\mathrm{1}\:\:?? \\ $$ Commented by A5T last updated on…
Question Number 205842 by BaliramKumar last updated on 31/Mar/24 $$\frac{\mathrm{32}^{\mathrm{32}^{\mathrm{32}} } }{\mathrm{9}}\:\overset{\mathrm{R}} {\equiv}\:? \\ $$ Answered by A5T last updated on 01/Apr/24 $$\mathrm{32}^{\mathrm{32}^{\mathrm{32}} } \overset{\mathrm{9}}…
Question Number 205794 by mnjuly1970 last updated on 30/Mar/24 $$ \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\mathrm{A}\:=\:\left\{\:\frac{{k}}{\mathrm{2}^{{n}} }\:\mid\:\mathrm{1}\leqslant\:{k}\:\leqslant\:\mathrm{2}^{{n}} \:,\:{n}\in\mathbb{N}\:\right\} \\ $$$$\:\:\:\:\:{find}\:.\:\:\overset{\:−} {\mathrm{A}}\:=\:? \\ $$$$ \\ $$ Commented by…
Question Number 205577 by BaliramKumar last updated on 25/Mar/24 $$\mathrm{is}\:\infty\:\mathrm{a}\:\mathrm{real}\:\mathrm{number}? \\ $$ Commented by mr W last updated on 25/Mar/24 $${it}\:{is}\:{only}\:{a}\:{symbol}.\:{it}\:{may}\:{have}\:\: \\ $$$${different}\:{meanings}\:{depending}\:{on}\: \\ $$$${in}\:{which}\:{context}\:{it}\:{is}\:{used}.\:…
Question Number 205574 by Red1ight last updated on 24/Mar/24 $${S}=\frac{\mathrm{1}}{\mathrm{2}!}−\frac{\mathrm{1}}{\mathrm{3}!}+\frac{\mathrm{1}}{\mathrm{4}!}−\frac{\mathrm{1}}{\mathrm{5}!}… \\ $$$${S}=? \\ $$ Commented by Frix last updated on 25/Mar/24 $${S}=\frac{\mathrm{1}}{\mathrm{e}} \\ $$ Answered…