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Category: Arithmetic

Question-39058

Question Number 39058 by jasno91 last updated on 02/Jul/18 Commented by maxmathsup by imad last updated on 25/Jul/18 $${if}\:{you}\:{want}\:{developpement}\:{let} \\ $$$${A}\left({x}\right)=\left(\mathrm{5}{x}−\mathrm{3}\right)\left({x}+\mathrm{4}\right)−\left(\mathrm{2}{x}+\mathrm{5}\right)\left(\mathrm{3}{x}−\mathrm{4}\right) \\ $$$${A}\left({x}\right)=\mathrm{5}{x}^{\mathrm{2}} \:+\mathrm{20}{x}\:−\mathrm{3}{x}\:−\mathrm{12}\:−\left(\mathrm{6}{x}^{\mathrm{2}} \:−\mathrm{8}{x}\:+\mathrm{15}{x}\:−\mathrm{20}\right)…

1-8-1-8-1-8-1-8-

Question Number 104571 by ajfour last updated on 22/Jul/20 $$\frac{\mathrm{1}}{\mathrm{8}}\:\boldsymbol{\div}\:\frac{\mathrm{1}}{\mathrm{8}}\:\boldsymbol{\div}\:\frac{\mathrm{1}}{\mathrm{8}}\:\boldsymbol{\div}\:\frac{\mathrm{1}}{\mathrm{8}}\:=\:? \\ $$ Answered by OlafThorendsen last updated on 22/Jul/20 $$=\:\left(\frac{\mathrm{1}}{\mathrm{8}}\:\boldsymbol{\div}\:\frac{\mathrm{1}}{\mathrm{8}}\right)\:\boldsymbol{\div}\left(\:\frac{\mathrm{1}}{\mathrm{8}}\:\boldsymbol{\div}\:\frac{\mathrm{1}}{\mathrm{8}}\right) \\ $$$$=\:\left(\mathrm{1}\right)\:\boldsymbol{\div}\left(\:\mathrm{1}\right) \\ $$$$=\:\mathrm{1} \\…

The-diagonals-of-a-trapezoid-ABCD-intersect-at-point-Q-lies-between-the-parallel-line-BC-and-AD-such-that-AQD-CQB-line-CD-separates-points-P-and-Q-Prove-that-BQP-DAQ-

Question Number 104221 by bemath last updated on 20/Jul/20 $${The}\:{diagonals}\:{of}\:{a} \\ $$$${trapezoid}\:{ABCD}\:{intersect} \\ $$$${at}\:{point}\:{Q}\:{lies}\:{between}\:{the} \\ $$$${parallel}\:{line}\:{BC}\:{and}\:{AD} \\ $$$${such}\:{that}\:\angle{AQD}\:=\:\angle{CQB}\:, \\ $$$${line}\:{CD}\:{separates}\:{points}\:{P} \\ $$$${and}\:{Q}\:.\:{Prove}\:{that} \\ $$$$\angle{BQP}\:=\:\angle{DAQ}\: \\…