Category: Arithmetic

Question Number 103623 by Lordose last updated on 16/Jul/20 $$\mathbf{find}\mathbf{the}\mathbf{sum}\mathbf{of}\mathbf{the}\mathbf{series}\mathbf{whose}\mathbf{nth}$$$$\mathbf{term}\mathbf{is}\frac{2\mathbf{n}-1}{\mathbf{n}(\mathbf{n}+1)(\mathbf{n}+2}.$$$$\mathbf{i}\mathbf{have}\mathbf{a}\mathbf{problem}\mathbf{with}\mathbf{this}\mathbf{and}\mathbf{i}\mathbf{need}$$$$\mathbf{help}\mathbf{please}$$ Answered by OlafThorendsen last updated on 16/Jul/20…

Question Number 103497 by I want to learn more last updated on 15/Jul/20 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 103321 by bemath last updated on 14/Jul/20 $$5+\sqrt{5-\sqrt{5+\sqrt{5-\sqrt{5+\sqrt{5-\sqrt{5+\dots }}}}}}$$ Answered by Dwaipayan Shikari last updated on 14/Jul/20 $$\sqrt{5-\sqrt{5+\sqrt{5\dots }}}=p$$$$5-\sqrt{5+\sqrt{5-\sqrt{5}}}\dots =p^2$$$$\mathrm{5}+{p}=\left(\mathrm{5}−{p}^{\mathrm{2}}…

Question Number 168391 by Florian last updated on 09/Apr/22 $$\frac{3\sqrt{3}}{3\sqrt{3}}=1or3\times \sqrt{3}\mathbf{÷}3\times \sqrt{3}=3???$$ Commented by Rasheed.Sindhi last updated on 09/Apr/22 $$\frac{3\sqrt{3}}{3\sqrt{3}}=\left(3\times \sqrt{3}\right)\mathbf{÷}\left(3\times \sqrt{3}\right)$$$$\mathrm{Where}\mathrm{as}$$$$\mathrm{3}×\sqrt{\mathrm{3}}\boldsymbol{\div}\mathrm{3}×\sqrt{\mathrm{3}}\:=\mathrm{3}×\left(\sqrt{\mathrm{3}}\boldsymbol{\div}\mathrm{3}\right)×\sqrt{\mathrm{3}} \…

Question Number 102773 by Ar Brandon last updated on 11/Jul/20 $$\mathrm{During}\mathrm{a}\mathrm{sales}\mathrm{period}\mathrm{a}\mathrm{magazine}\mathrm{offers}\mathrm{a}\mathrm{t}\mathrm{\%}\mathrm{discount}$$$$\mathrm{For}\mathrm{clients}\mathrm{in}\mathrm{possession}\mathrm{of}\mathrm{the}\mathrm{fidelity}\mathrm{card},\mathrm{an}\mathrm{extra}\mathrm{discount}$$$$\mathrm{of}(\mathrm{t}+5)\mathrm{\%}\mathrm{is}\mathrm{offered}.$$$$\mathrm{A}\mathrm{client}\mathrm{benefits}\mathrm{from}\mathrm{these}\mathrm{two}\mathrm{discounts}\mathrm{and}\mathrm{pays}$$$$150ϵ\mathrm{for}\mathrm{an}\mathrm{article}\mathrm{whose}\mathrm{initial}\mathrm{price}\mathrm{is}250ϵ$$$$\left(i\right)\mathrm{Show}\mathrm{that}\mathrm{t}\mathrm{is}\mathrm{solution}\mathrm{to}\mathrm{the}\mathrm{equation}$$$$250\times (1-\frac{\mathrm{t}}{100})\times (1-\frac{\mathrm{t}+5}{100})=150$$$$\left({ii}\right)\:\mathrm{Solve}\:\mathrm{this}\:\mathrm{equation}\:\mathrm{and}\:\mathrm{deduce}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{t}.…