Question Number 103633 by Lordose last updated on 16/Jul/20 $$ \\ $$$$\boldsymbol{\mathrm{The}}\:\boldsymbol{\mathrm{question}}\:\boldsymbol{\mathrm{is}} \\ $$$$\underset{\boldsymbol{\mathrm{n}}=\mathrm{1}} {\overset{\infty} {\sum}}\left(\frac{\mathrm{2}\boldsymbol{\mathrm{n}}−\mathrm{1}}{\boldsymbol{\mathrm{n}}\left(\boldsymbol{\mathrm{n}}+\mathrm{1}\right)\left(\boldsymbol{\mathrm{n}}+\mathrm{2}\right.}\right)=… \\ $$ Commented by bobhans last updated on 16/Jul/20…
Question Number 38099 by Cheyboy last updated on 21/Jun/18 $${x}^{{x}} =\mathrm{0}.\mathrm{25} \\ $$$${find}\:{x} \\ $$ Commented by MrW3 last updated on 22/Jun/18 $${no}\:{real}\:{solution},\: \\ $$$${since}\:{x}^{{x}}…
Question Number 103623 by Lordose last updated on 16/Jul/20 $$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{sum}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{series}}\:\boldsymbol{\mathrm{whose}}\:\boldsymbol{\mathrm{nth}} \\ $$$$\boldsymbol{\mathrm{term}}\:\boldsymbol{\mathrm{is}}\:\frac{\mathrm{2}\boldsymbol{\mathrm{n}}−\mathrm{1}}{\boldsymbol{\mathrm{n}}\left(\boldsymbol{\mathrm{n}}+\mathrm{1}\right)\left(\boldsymbol{\mathrm{n}}+\mathrm{2}\right.}. \\ $$$$\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{have}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{problem}}\:\boldsymbol{\mathrm{with}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{need}} \\ $$$$\boldsymbol{\mathrm{help}}\:\boldsymbol{\mathrm{please}} \\ $$ Answered by OlafThorendsen last updated on 16/Jul/20…
Question Number 103620 by bobhans last updated on 16/Jul/20 $${If}\:{a}^{\mathrm{2}} −{bc},\:{b}^{\mathrm{2}} −{ac},\:{c}^{\mathrm{2}} −{ab}\:{is}\:{AP}\:{where}\:{a}+{c} \\ $$$$=\:\mathrm{12},\:{find}\:{the}\:{value}\:{of}\:{a}+{b}+{c}\: \\ $$ Answered by bemath last updated on 16/Jul/20 $$\Rightarrow{AP}\::\:\mathrm{2}\left({b}^{\mathrm{2}}…
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Question Number 103389 by M±th+et+s last updated on 14/Jul/20 Commented by M±th+et+s last updated on 14/Jul/20 $${find}\:{the}\:{hypotenuse}\:{of}\:{the}\:{triangle} \\ $$$${as}\:\left({x}\right) \\ $$ Answered by OlafThorendsen last…
Question Number 103321 by bemath last updated on 14/Jul/20 $$\mathrm{5}+\sqrt{\mathrm{5}−\sqrt{\mathrm{5}+\sqrt{\mathrm{5}−\sqrt{\mathrm{5}+\sqrt{\mathrm{5}−\sqrt{\mathrm{5}+…}}}}}} \\ $$ Answered by Dwaipayan Shikari last updated on 14/Jul/20 $$\sqrt{\mathrm{5}−\sqrt{\mathrm{5}+\sqrt{\mathrm{5}…}}}={p} \\ $$$$\mathrm{5}−\sqrt{\mathrm{5}+\sqrt{\mathrm{5}−\sqrt{\mathrm{5}}}}…={p}^{\mathrm{2}} \\ $$$$\mathrm{5}+{p}=\left(\mathrm{5}−{p}^{\mathrm{2}}…
Question Number 37712 by Rio Mike last updated on 16/Jun/18 $${Evaluate}\:\underset{{r}=\mathrm{0}} {\overset{\infty} {\sum}}\mathrm{2}^{{r}−\mathrm{1}} \\ $$ Commented by prakash jain last updated on 17/Jun/18 $$−\mathrm{1}/\mathrm{2}\:\mathrm{is}\:\mathrm{also}\:\mathrm{a}\:\mathrm{valid}\:\mathrm{answer}\:\mathrm{using} \\…
Question Number 168391 by Florian last updated on 09/Apr/22 $$\:\:\:\frac{\mathrm{3}\sqrt{\mathrm{3}}}{\mathrm{3}\sqrt{\mathrm{3}}}=\mathrm{1}\:\:\:\:{or}\:\:\mathrm{3}×\sqrt{\mathrm{3}}\boldsymbol{\div}\mathrm{3}×\sqrt{\mathrm{3}}\:=\mathrm{3}\:\:\:\:\:\:\:\:\:\:\:??? \\ $$ Commented by Rasheed.Sindhi last updated on 09/Apr/22 $$\:\frac{\mathrm{3}\sqrt{\mathrm{3}}}{\mathrm{3}\sqrt{\mathrm{3}}}=\left(\mathrm{3}×\sqrt{\mathrm{3}}\:\right)\boldsymbol{\div}\left(\mathrm{3}×\sqrt{\mathrm{3}}\:\right) \\ $$$$\mathrm{Where}\:\mathrm{as} \\ $$$$\mathrm{3}×\sqrt{\mathrm{3}}\boldsymbol{\div}\mathrm{3}×\sqrt{\mathrm{3}}\:=\mathrm{3}×\left(\sqrt{\mathrm{3}}\boldsymbol{\div}\mathrm{3}\right)×\sqrt{\mathrm{3}} \\…
Question Number 102819 by aurpeyz last updated on 11/Jul/20 Commented by Rasheed.Sindhi last updated on 11/Jul/20 $${Perhaps}\:{he}\:{doesn}'{t}\:{know}\:{to}\:{use} \\ $$$${the}\:{keyboard}\:{of}\:{this}\:{app}. \\ $$ Commented by JDamian last…