Menu Close

Category: Arithmetic

Prove-that-a-A-A-B-A-c-A-B-A-B-A-b-A-A-B-A-d-A-A-B-A-B-

Question Number 96811 by Ar Brandon last updated on 05/Jun/20 $$\mathrm{Prove}\:\mathrm{that}; \\ $$$$\mathrm{a}\backslash\:\mathrm{A}+\mathrm{A}\centerdot\mathrm{B}=\mathrm{A}\:\:\:\:\:\:\:\:\:\:\:\mathrm{c}\backslash\:\left(\mathrm{A}+\mathrm{B}^{} \right)\centerdot\left(\mathrm{A}+\overset{−} {\mathrm{B}}\right)=\mathrm{A} \\ $$$$\mathrm{b}\backslash\:\mathrm{A}\centerdot\left(\mathrm{A}+\mathrm{B}\right)=\mathrm{A}\:\:\:\:\:\:\:\mathrm{d}\backslash\:\mathrm{A}+\overset{−} {\mathrm{A}B}=\mathrm{A}+\mathrm{B} \\ $$ Answered by 1549442205 last updated…

find-n-in-ordre-to-have-7-divide-n-3-n-2-

Question Number 31043 by abdo imad last updated on 02/Mar/18 $${find}\:{n}\:{in}\:{ordre}\:{to}\:{have}\:\mathrm{7}\:{divide}\:{n}^{\mathrm{3}} \:+{n}−\mathrm{2} \\ $$ Commented by MJS last updated on 03/Mar/18 $$\mathrm{the}\:\mathrm{sequence}\:\mathrm{of}\:\mathrm{remains}\:\mathrm{of} \\ $$$${n}^{\mathrm{3}} /\mathrm{7}\:\mathrm{is}\:\langle\mathrm{1},\mathrm{1},\mathrm{6},\mathrm{1},\mathrm{6},\mathrm{6},\mathrm{0},…\rangle…