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Category: Arithmetic

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Question Number 98434 by  M±th+et+s last updated on 14/Jun/20 provethatΩ=+n=0+m=0Γ(n+12).Γ(m+12)Γ(n+1).Γ(m+1).(23)n.(12)m(n+m+12)$$=\frac{\sqrt{\mathrm{3}}}{\mathrm{2}\sqrt{\mathrm{2}}}.{G}_{\mathrm{2},\mathrm{2}} ^{\mathrm{2},\mathrm{2}} \left(\frac{\mathrm{1}}{\mathrm{4}}\mid_{\mathrm{0}\:\:,\:\mathrm{0}} ^{\frac{\mathrm{1}}{\mathrm{2}},\frac{\mathrm{1}}{\mathrm{2}}} \right) \