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Question Number 162366 by cortano last updated on 29/Dec/21 $$\:{Given}\:{that}\:{the}\:{solution}\:{set}\:{of}\:{the}\: \\ $$$$\:{quadratic}\:{inequality}\:{ax}^{\mathrm{2}} +{bx}+{c}\:>\mathrm{0} \\ $$$$\:{is}\:\left(\mathrm{2},\mathrm{3}\right).\:{Then}\:{the}\:{solution}\:{set}\: \\ $$$$\:{of}\:{the}\:{inequality}\:{cx}^{\mathrm{2}} +{bx}+{a}\:<\mathrm{0}\: \\ $$$$\:{will}\:{be}\: \\ $$ Answered by mr…
Question Number 96811 by Ar Brandon last updated on 05/Jun/20 $$\mathrm{Prove}\:\mathrm{that}; \\ $$$$\mathrm{a}\backslash\:\mathrm{A}+\mathrm{A}\centerdot\mathrm{B}=\mathrm{A}\:\:\:\:\:\:\:\:\:\:\:\mathrm{c}\backslash\:\left(\mathrm{A}+\mathrm{B}^{} \right)\centerdot\left(\mathrm{A}+\overset{−} {\mathrm{B}}\right)=\mathrm{A} \\ $$$$\mathrm{b}\backslash\:\mathrm{A}\centerdot\left(\mathrm{A}+\mathrm{B}\right)=\mathrm{A}\:\:\:\:\:\:\:\mathrm{d}\backslash\:\mathrm{A}+\overset{−} {\mathrm{A}B}=\mathrm{A}+\mathrm{B} \\ $$ Answered by 1549442205 last updated…
Question Number 31229 by abdo imad last updated on 03/Mar/18 $${simplify}\:{A}_{{n}} =\:{C}_{{n}} ^{\mathrm{1}} \:\:+\mathrm{2}\:{C}_{{n}} ^{\mathrm{2}} \:+\mathrm{3}\:{C}_{{n}} ^{\mathrm{3}} \:+…\:+\:{n}\:{C}_{{n}} ^{{n}} \:. \\ $$ Commented by abdo…
Question Number 31045 by abdo imad last updated on 02/Mar/18 $${simlify}\:{A}_{{n}} =\left({C}_{{n}} ^{\mathrm{1}} \right)^{\mathrm{2}} \:+\mathrm{2}\left({C}_{{n}} ^{\mathrm{2}} \right)^{\mathrm{2}} \:\:+{n}\:\left({C}_{{n}} ^{{n}} \right)^{\mathrm{2}} . \\ $$ Terms of…
Question Number 31044 by abdo imad last updated on 02/Mar/18 $${if}\:\mathrm{1}\:+\mathrm{2}^{{n}} \:+\mathrm{3}^{{n}} \:+\mathrm{4}^{{n}} =\mathrm{4}{q}\:+{r}\:\:{find}\:{r}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 31043 by abdo imad last updated on 02/Mar/18 $${find}\:{n}\:{in}\:{ordre}\:{to}\:{have}\:\mathrm{7}\:{divide}\:{n}^{\mathrm{3}} \:+{n}−\mathrm{2} \\ $$ Commented by MJS last updated on 03/Mar/18 $$\mathrm{the}\:\mathrm{sequence}\:\mathrm{of}\:\mathrm{remains}\:\mathrm{of} \\ $$$${n}^{\mathrm{3}} /\mathrm{7}\:\mathrm{is}\:\langle\mathrm{1},\mathrm{1},\mathrm{6},\mathrm{1},\mathrm{6},\mathrm{6},\mathrm{0},…\rangle…
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Question Number 161947 by mathlove last updated on 24/Dec/21 $${abc}=\mathrm{8} \\ $$$${a}+{b}+{c}=\mathrm{7} \\ $$$${a}^{\mathrm{3}} +{b}^{\mathrm{3}} +{c}^{\mathrm{3}} =\mathrm{73} \\ $$$${then}\:{faind}\:\:{the}\:{vole}\:{of} \\ $$$$\frac{\mathrm{1}}{{a}}+\frac{\mathrm{1}}{{b}}+\frac{\mathrm{1}}{{c}}=? \\ $$ Answered by…
Question Number 161888 by henderson last updated on 23/Dec/21 $$\mathrm{help}\:\mathrm{me}\:! \\ $$$$\mathrm{solve}\:\mathrm{this}\:\mathrm{one}\::\:\mathrm{C}_{\mathrm{40}} ^{\mathrm{2n}} \:=\:\mathrm{C}_{\mathrm{40}} ^{\mathrm{16}+\mathrm{n}} \\ $$ Commented by mr W last updated on 23/Dec/21…