Category: Arithmetic

Question Number 98116 by  M±th+et+s last updated on 11/Jun/20 $$provethecompactformofmultivariable$$$$Taylorseries$$$$$$$$\left({T}\ast{B}\right)=\underset{{n}=\mathrm{1},{n}=\mathrm{2}..{n}_{{d}} =\mathrm{0}} {\overset{\infty} {\sum}}\frac{\prod_{\mathrm{i}=\mathrm{0}} ^{{n}_{{d}} } \left({x}_{\mathrm{i}} −{d}_{\mathrm{i}} \right)}{\prod_{\mathrm{i}=\mathrm{0}} ^{{n}_{{d}}…

Question Number 98060 by  M±th+et+s last updated on 11/Jun/20 $$showthat$$$$\underset{n=1}{\sum ^{\mathrm{\infty }}}arctan\left(\frac{2}{n^2}\right)=\frac{3\pi }{4}$$ Answered by smridha last updated on 11/Jun/20 $${is}\:{it}\:\boldsymbol{{right}}\:\boldsymbol{{ans}}???\boldsymbol{{I}}\:{think}\:\boldsymbol{{it}}'{s}\:{just}…

Question Number 97956 by  M±th+et+s last updated on 10/Jun/20 $$prove$$$$\underset{n=1}{\sum ^{\mathrm{\infty }}}\frac{9n+4}{3n(3n+1)(3n+2)}=\frac{3}{2}-ln\left(3\right)$$ Answered by maths mind last updated on 13/Jun/20 $$=\underset{{n}\geqslant\mathrm{1}}…

Question Number 32328 by abdo imad last updated on 23/Mar/18 $$provethat{2}^{n+1}divide{A}_n=\left[{(1+\sqrt{3})}^{2n+1}\right].$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 163340 by mathlove last updated on 06/Jan/22 Answered by Rasheed.Sindhi last updated on 06/Jan/22 $$\frac{a^2-b^2}{a+b}=a-b$$$$=[1+\frac{1}{1+\frac{1}{100}}-(1-\frac{1}{1+\frac{1}{100}})]$$$$=[1+\frac{1}{1+\frac{1}{100}}-1+\frac{1}{1+\frac{1}{100}}]$$$$\mathrm{2}\left(\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{100}}}\right)=\mathrm{2}×\frac{\mathrm{100}}{\mathrm{101}}=\frac{\mathrm{200}}{\mathrm{101}}\:\:\:\left({b}\right)\checkmark…