Category: Arithmetic

Question Number 208980 by lmcp1203 last updated on 30/Jun/24 $$please.find{2}^{{11001}^{666}}mod23thanks.$$ Answered by A5T last updated on 30/Jun/24 $$\mathrm{2}^{\mathrm{11001}^{\mathrm{666}} } {mod}\left(\mathrm{23}\right)\equiv\mathrm{2}^{\mathrm{11001}^{\mathrm{666}} \left[{mod}\:\phi\left(\mathrm{23}\right)\right]}…

Question Number 208445 by alcohol last updated on 16/Jun/24 $$u_{n+1}=u_n-u_n^3,u_0\in ]0,1[$$$${v}_{{n}} \:=\:\frac{\mathrm{1}}{{u}_{{n}+\mathrm{1}} ^{\mathrm{2}} }−\frac{\mathrm{1}}{{u}_{{n}} ^{\mathrm{2}} }\:=\:{f}\left({u}_{{n}} ^{\mathrm{2}} \right)\:;\:{f}\left({x}\right)\:=\:\frac{\mathrm{2}−{x}}{\left(\mathrm{1}−{x}\right)^{\mathrm{2}} }…

Question Number 207979 by Tawa11 last updated on 01/Jun/24 generate nth term for the sequence: 1, 1, 1, 2, 3, 5, 9, 18, 35, 75…

Question Number 207594 by MATHEMATICSAM last updated on 19/May/24 $$\frac{x\cos \theta }{a}+\frac{y\sin \theta }{b}=1$$$$x\sin \theta -y\cos \theta =\sqrt{a^2{\sin }^2\theta +b^2{\cos }^2\theta }$$$$\mathrm{Eliminate}\theta .$$ Answered by Frix last updated…

Question Number 207416 by efronzo1 last updated on 14/May/24 $$$$ Answered by mr W last updated on 14/May/24 $$\frac{{U}_{\mathrm{2}} }{{q}}+{U}_{\mathrm{2}} +{qU}_{\mathrm{2}} =\mathrm{9}\left(\frac{{q}}{{U}_{\mathrm{2}} }+\frac{\mathrm{1}}{{U}_{\mathrm{2}}…