Question Number 25377 by Mr eaay last updated on 09/Dec/17 Answered by mrW1 last updated on 09/Dec/17 $$\frac{\mathrm{1}}{\mathrm{15}}+\frac{\mathrm{1}}{\mathrm{12}}=\frac{\mathrm{4}+\mathrm{5}}{\mathrm{60}}=\frac{\mathrm{3}}{\mathrm{20}} \\ $$$$\frac{\mathrm{20}}{\mathrm{3}}\approx\mathrm{7} \\ $$$$\Rightarrow{in}\:\mathrm{7}\:{days}\:{the}\:{work}\:{will}\:{be} \\ $$$${completed}. \\…
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Question Number 156334 by mathlove last updated on 10/Oct/21 Commented by Rasheed.Sindhi last updated on 10/Oct/21 $${Insufficient}\:\:{data}\Rightarrow{Not}\:{unique}\:{answer}. \\ $$$${Do}\:{you}\:{mean}\:{a},{b},{c}\in\mathbb{Z},\:{or}\:{any}\:{condition} \\ $$$${else}? \\ $$ Terms of…
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Question Number 156295 by cortano last updated on 10/Oct/21 Answered by MJS_new last updated on 10/Oct/21 $$\frac{\mathrm{14}}{\mathrm{2}}×\left(\mathrm{14}−\frac{\mathrm{12}}{\mathrm{26}}×\mathrm{14}\right)+\frac{\mathrm{12}}{\mathrm{2}}×\left(\mathrm{12}−\frac{\mathrm{12}}{\mathrm{26}}×\mathrm{14}\right)=\mathrm{86} \\ $$ Commented by cortano last updated on…
Question Number 156186 by DavidSmath last updated on 09/Oct/21 Commented by DavidSmath last updated on 09/Oct/21 $$\mathrm{show}\:\mathrm{clear}\:\mathrm{workings}… \\ $$ Commented by MJS_new last updated on…
Question Number 90637 by Tony Lin last updated on 25/Apr/20 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\mathrm{2}^{{n}} }{tan}\left(\frac{\mathrm{1}}{\mathrm{2}^{{n}} }\right) \\ $$ Answered by TANMAY PANACEA. last updated on 25/Apr/20…
Question Number 90570 by Tony Lin last updated on 24/Apr/20 $${find}\:{the}\:{sum}\:{of}\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)\mathrm{3}^{{n}} } \\ $$ Commented by mathmax by abdo last updated on…
Question Number 90562 by Tony Lin last updated on 24/Apr/20 $${prove}\:{that} \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\mathrm{2}{n}\left(\mathrm{2}{n}−\mathrm{1}\right)}={ln}\mathrm{2} \\ $$ Commented by mathmax by abdo last updated on…
Question Number 90561 by Tony Lin last updated on 24/Apr/20 $${prove}\:{that} \\ $$$$\underset{{n}=\mathrm{2}} {\overset{\infty} {\prod}}\left(\mathrm{1}−\frac{\mathrm{1}}{{n}^{\mathrm{2}} }\right)=\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Commented by mathmax by abdo last updated…