Question Number 87878 by Cmr 237 last updated on 06/Apr/20 $${posons}\: \\ $$$$\left(\mathrm{1}+\mathrm{2}\sqrt{\mathrm{3}}\right)^{\boldsymbol{{n}}} =\boldsymbol{\mathrm{a}}_{\boldsymbol{\mathrm{n}}} +\boldsymbol{\mathrm{b}}_{\boldsymbol{\mathrm{n}}} \sqrt{\mathrm{3}} \\ $$$$\boldsymbol{\mathrm{montre}}\:\boldsymbol{\mathrm{que}}\:\boldsymbol{\mathrm{pgcd}}\left(\boldsymbol{\mathrm{a}}_{\boldsymbol{\mathrm{n}}} ;\boldsymbol{{b}}_{\boldsymbol{{n}}} \right)=\mathrm{1} \\ $$ Answered by mind…
Question Number 87877 by Cmr 237 last updated on 06/Apr/20 $${posons}\: \\ $$$$\left(\mathrm{1}+\mathrm{2}\sqrt{\mathrm{3}}\right)^{\boldsymbol{{n}}} =\boldsymbol{\mathrm{a}}_{\boldsymbol{\mathrm{n}}} +\boldsymbol{\mathrm{b}}_{\boldsymbol{\mathrm{n}}} \sqrt{\mathrm{3}} \\ $$$$\boldsymbol{\mathrm{montre}}\:\boldsymbol{\mathrm{que}}\:\boldsymbol{\mathrm{pgcd}}\left(\boldsymbol{\mathrm{a}}_{\boldsymbol{\mathrm{n}}} ;\boldsymbol{{b}}_{\boldsymbol{{n}}} \right)=\mathrm{1} \\ $$ Terms of Service…
Question Number 153392 by ArielVyny last updated on 06/Sep/21 $$\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{k}^{{a}} =?\:\:\: \\ $$ Commented by prakash jain last updated on 07/Sep/21 $$\zeta\left(−{a}\right)−\zeta\left(−{a},{n}+\mathrm{1}\right) \\…
Question Number 22276 by kasiulka202 last updated on 14/Oct/17 Answered by Joel577 last updated on 14/Oct/17 $$\mathrm{9}\:+\:\left(\mathrm{7}\:×\:\mathrm{2}\right)\:−\:\left(\mathrm{10}\:×\:\mathrm{4}\right)\:−\:\mathrm{5} \\ $$$$=\:\mathrm{9}\:+\:\mathrm{14}\:−\:\mathrm{40}\:−\:\mathrm{5} \\ $$$$=\:\mathrm{23}\:−\:\mathrm{40}\:−\:\mathrm{5} \\ $$$$=\:−\mathrm{17}\:−\:\mathrm{5} \\ $$$$=\:−\mathrm{22}…
Question Number 22273 by kasiulka202 last updated on 14/Oct/17 $${Ant}\:{rided}\:\mathrm{30}\:{meters}\:{in}\:\mathrm{12}\:{seconds}.\:{How}\:{fast}\:{are}\:{rided}\:{ant}? \\ $$ Commented by Rasheed.Sindhi last updated on 14/Oct/17 $$\:\mathrm{Speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{ant}=\frac{\mathrm{30}}{\mathrm{12}}\:\:=\mathrm{2}.\mathrm{5}\:\mathrm{m}/\mathrm{s}. \\ $$ Terms of Service…
Question Number 22269 by kasiulka202 last updated on 14/Oct/17 $${Product}\:{costs}\:\mathrm{599}.\mathrm{99}\:{zloty}.\:{Person}\:{have}\:\mathrm{433}.\mathrm{94}\:{zloty}. \\ $$$${How}\:{muh}\:{zloty}\:{is}\:{a}\:{rest}\:{or}\:{missing}? \\ $$ Answered by FilupS last updated on 14/Oct/17 $$\mathrm{599}.\mathrm{99}={x}+\mathrm{433}.\mathrm{94} \\ $$$${x}=\mathrm{599}.\mathrm{99}−\mathrm{433}.\mathrm{94} \\…
Question Number 22263 by kasiulka202 last updated on 14/Oct/17 Answered by Joel577 last updated on 14/Oct/17 $$\frac{\mathrm{0}}{\mathrm{0}}\:{is}\:{an}\:{indeterminate}\:{form} \\ $$ Answered by FilupS last updated on…
Question Number 22264 by kasiulka202 last updated on 14/Oct/17 $${What}\:{is}\:\mathrm{1}+\mathrm{5}\frac{\mathrm{2}}{\mathrm{3}} \\ $$ Answered by Joel577 last updated on 14/Oct/17 $$\mathrm{U}\:\mathrm{have}\:\mathrm{1}\:\mathrm{cake},\:\mathrm{and}\:\mathrm{then}\:\mathrm{u}\:\mathrm{buy}\:\mathrm{5}\frac{\mathrm{2}}{\mathrm{3}}\:\mathrm{cakes} \\ $$$$\mathrm{So},\:\mathrm{u}\:\mathrm{have}\:\mathrm{total}\:\mathrm{6}\frac{\mathrm{2}}{\mathrm{3}}\:\mathrm{cakes} \\ $$ Terms…
Question Number 87647 by john santu last updated on 05/Apr/20 $$\mathrm{If}\:\mathrm{a}_{\mathrm{1}} \:=\:\mathrm{1}\:,\:\mathrm{a}_{\mathrm{n}+\mathrm{1}\:} =\:\mathrm{2a}_{\mathrm{n}} \:+\:\mathrm{5}\:,\:\mathrm{n}\:=\: \\ $$$$\mathrm{1},\mathrm{2},\mathrm{3},….\:\mathrm{then}\:\mathrm{a}_{\mathrm{100}} \:=\:? \\ $$ Answered by mr W last updated…
Question Number 22090 by tawa tawa last updated on 10/Oct/17 Answered by Tikufly last updated on 11/Oct/17 $$\left(\mathrm{i}\right)\:\mathrm{3},\:\:\mathrm{15},\:\:\:\mathrm{75},\:\:\:\mathrm{375},……. \\ $$$$\left(\mathrm{ii}\right)\mathrm{3},\:\:\mathrm{15},\:\:\:\mathrm{27},\:\:\:\mathrm{39},……… \\ $$ Commented by tawa…