Category: Coordinate Geometry

Question Number 227326 by gregori last updated on 16/Jan/26 $$\:\:\:\mid\:{x}+\mathrm{1}\:\mid\:+\:\mid\:{x}\:\mid\:+\:\mid\:{x}−\mathrm{3}\mid\:>\:\mathrm{8}\:\: \\ $$ Answered by Kassista last updated on 16/Jan/26 $$ \\ $$$${if}\:{x}\geqslant\mathrm{3}: \\ $$$${x}+\mathrm{1}+{x}+{x}−\mathrm{3}>\mathrm{8}\:\Leftrightarrow\:\mathrm{3}{x}−\mathrm{2}>\mathrm{8},\:\mathrm{3}{x}>\mathrm{10},\:{x}>\frac{\mathrm{10}}{\mathrm{3}}…\left(\mathrm{1}\right) \\…

Question Number 227295 by Spillover last updated on 12/Jan/26 Answered by Spillover last updated on 12/Jan/26 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 226913 by Spillover last updated on 18/Dec/25 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 226770 by gregori last updated on 14/Dec/25 Answered by TonyCWX last updated on 14/Dec/25 $$\mathrm{Stewart}'\mathrm{s}\:\mathrm{Theorem}: \\ $$$${b}^{\mathrm{2}} {x}+{b}^{\mathrm{2}} {y}=\left({x}+{y}\right)\left({z}^{\mathrm{2}} −{xy}\right) \\ $$$${b}^{\mathrm{2}} \left({x}+{y}\right)=\left({x}+{y}\right)\left({z}^{\mathrm{2}}…

Question Number 226587 by Spillover last updated on 06/Dec/25 Terms of Service Privacy Policy Contact: info@tinkutara.com