Question Number 127116 by physicstutes last updated on 27/Dec/20 $$\mathrm{Given}\:\mathrm{a}\:\mathrm{sequence}\:\left({u}_{{n}} \right)\:\mathrm{defined}\:\mathrm{reculsively}\:\mathrm{by} \\ $$$$\:{u}_{{n}+\mathrm{1}} \:=\:\mathrm{3}{u}_{{n}} +\:\mathrm{4}{u}_{{n}−\mathrm{1}} ,\:\:{u}_{\mathrm{0}} =\:\mathrm{1}\:,\:{u}_{\mathrm{2}} \:=\:\mathrm{3} \\ $$$$\:\mathrm{show}\:\mathrm{that}\:\:{u}_{{n}+\mathrm{1}} −\mathrm{4}{u}_{{n}} \:=\:\left(−\mathrm{1}\right)^{{n}+\mathrm{1}} \left(\mathrm{3}{u}_{\mathrm{0}} −\mathrm{4}{u}_{\mathrm{1}} \right)…
Question Number 61274 by alphaprime last updated on 31/May/19 $${If}\:{p}\:,\:{x}_{\mathrm{1}} ,{x}_{\mathrm{2}} ,…{x}_{{i}} \:{and}\:{q},{y}_{\mathrm{1}} ,{y}_{\mathrm{2}} ,…{y}_{{i}} \:{form}\:{two}\: \\ $$$${infinite}\:{arithmetic}\:{sequences}\:{with}\:{common}\: \\ $$$${difference}\:\:{a}\:{and}\:{b}\:{respectively}\:, \\ $$$${then}\:{find}\:{the}\:{locus}\:{of}\:{the}\:{point}\:\left(\:\alpha\:,\:\beta\:\right)\: \\ $$$${where}\:\alpha\:=\:\frac{\mathrm{1}}{{n}}\:\sum_{{i}=\mathrm{1}} ^{{n}}…
Question Number 192099 by a.lgnaoui last updated on 08/May/23 $$\mathrm{demontrer}\:\:\mathrm{l}\:\mathrm{expression}\:\mathrm{suivante} \\ $$ Commented by a.lgnaoui last updated on 08/May/23 Terms of Service Privacy Policy Contact:…
Question Number 192073 by a.lgnaoui last updated on 07/May/23 $$\mathrm{Reponse}\:\mathrm{a}\:\:\mathrm{l}\:\mathrm{exercice}\:\mathrm{deja}\:\:\mathrm{pose} \\ $$ Answered by a.lgnaoui last updated on 07/May/23 Commented by a.lgnaoui last updated on…
Question Number 191930 by a.lgnaoui last updated on 05/May/23 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{inside}\:\mathrm{Area}\:\mathrm{of} \\ $$$$\left(\mathrm{ABCDEF}\right)? \\ $$$$\mathrm{Such}\:\mathrm{that}:\:\measuredangle\mathrm{AOB}=\mathrm{120}\:\:\:\measuredangle\mathrm{ANB}=\mathrm{60};°\mathrm{R}=\mathrm{ON} \\ $$$$\:\left(\mathrm{OA}=\mathrm{OB}=\mathrm{32cm}\right)\:\mathrm{ArcAE}=\mathrm{ArcBF}\left(\mathrm{r}=\mathrm{12cm}\right) \\ $$$$\mathrm{BASE}\:\mathrm{is}\:\mathrm{circulare} \\ $$$$\left({Aider}\:{le}\:{tailleur}\:{a}\:{savoir}\:{la}\:{surface}\right. \\ $$$${du}\:{tissu}\:{necessaire}\:{pour}\:{couvrir}\: \\ $$$$\left.\:{l}\:'\mathrm{e}{space}\:{indique}\:{dans}\:{la}\:{figure}?\right) \\…
Question Number 191927 by a.lgnaoui last updated on 04/May/23 $$\boldsymbol{\mathrm{W}}\mathrm{hat}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{laterale}\:\mathrm{Shaded} \\ $$$$\:\mathrm{Area}\:\:\left(\boldsymbol{\mathrm{couronne}}\:\boldsymbol{\mathrm{circulaire}}\:\:\boldsymbol{\mathrm{coloree}}?\right) \\ $$$$\:\:\boldsymbol{\mathrm{R}}=\mathrm{10}\boldsymbol{\mathrm{cm}}\:\:\:\mathrm{20}\boldsymbol{\mathrm{cm}}\leqslant\:\boldsymbol{\mathrm{h}}\leqslant\mathrm{24}\boldsymbol{\mathrm{cm}}\:\:\measuredangle\mathrm{COD}=\mathrm{45}° \\ $$$$\:\: \\ $$ Commented by a.lgnaoui last updated on 04/May/23…
Question Number 60812 by peter frank last updated on 26/May/19 Commented by tanmay last updated on 26/May/19 $${area}\:{of}\:{BCADB}=\mathrm{2}×\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{5}×\mathrm{12}=\mathrm{60} \\ $$$$\mathrm{60}=\mathrm{2}\left[\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{13}×{h}\right] \\ $$$${h}=\frac{\mathrm{60}}{\mathrm{13}} \\ $$$${sin}\theta_{\mathrm{1}} =\frac{{h}}{\mathrm{12}}\:\:\:{and}\:{sin}\theta_{\mathrm{2}}…
Question Number 60788 by ajfour last updated on 25/May/19 Commented by ajfour last updated on 25/May/19 $${In}\:{terms}\:{of}\:\alpha\:{and}\:{ellipse}\:{parameters} \\ $$$${a}\:{and}\:{b},\:{find}\:{maximum}\:{colored}\:{area}. \\ $$ Answered by mr W…
Question Number 126192 by ajfour last updated on 18/Dec/20 Commented by ajfour last updated on 18/Dec/20 $${If}\:{shape}\:{of}\:{parabola}\:{is}\:{same}\:{as} \\ $$$${that}\:{of}\:{y}={x}^{\mathrm{2}} ,\:{find}\:\:{radius}\:{of} \\ $$$${the}\:{smaller}\:{circle}. \\ $$ Commented…
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