Question Number 191642 by a.lgnaoui last updated on 30/Apr/23 $$\mathrm{Comparer}\:\left[\mathrm{OHDF}\right]\:\:\mathrm{avec}\:\left[\mathrm{ABHEF}\right] \\ $$$$\left({avec}\:{preuve}\right) \\ $$$$\:\:{Sa}\mathrm{c}{h}\mathrm{a}{nt}\:{que}: \\ $$$$\mathrm{OH}\mid\mid\mathrm{DF}\:\:\:\mathrm{HE}=\mathrm{EF}\:\:\:\mathrm{OB}=\mathrm{4OA} \\ $$$$\:\:\:\mathrm{CH}=\mathrm{2BC}\:\mathrm{et}\:\mathrm{BC}<\mathrm{OB}.\:\:\: \\ $$$$ \\ $$ Commented by a.lgnaoui…
Question Number 191639 by a.lgnaoui last updated on 28/Apr/23 $$\mathrm{Une}\:\mathrm{feuille}\:\mathrm{de}\:\mathrm{papier}\:\mathrm{format}\:\boldsymbol{\mathrm{A}}\mathrm{4}\:\mathrm{est}\:\mathrm{plie} \\ $$$$\:\boldsymbol{\mathrm{n}}\:\mathrm{fois}\:\mathrm{simultanement}\:\mathrm{en}\:\mathrm{longueur}\:\mathrm{et} \\ $$$$\mathrm{largeur}\:\left(\mathrm{total}\:\mathrm{plie}=\mathrm{2n}\right) \\ $$$$−\mathrm{Quel}\:\mathrm{son}\:\mathrm{les}\:\mathrm{nouvelles}\:\mathrm{dimensions}\:\mathrm{de}\:\mathrm{cette}\:\mathrm{feuille} \\ $$$$\:\:\:\mathrm{la}\:\mathrm{feuille}\:\mathrm{a}\:\mathrm{la}\:\mathrm{fin}\:. \\ $$$$−\mathrm{quel}\:\mathrm{seront}\:\mathrm{ses}\:\mathrm{dimensions}\:\:\mathrm{apres}\: \\ $$$$\:\:\:\:\mathrm{6}\:\boldsymbol{\mathrm{pliages}} \\ $$$$−\mathrm{Quel}\:\mathrm{seront}\:\:\mathrm{les}\:\mathrm{dimensions}\:\mathrm{pour}\:\mathrm{une}\:\mathrm{feuille}\:\boldsymbol{\mathrm{care}}\:\mathrm{de}\:\mathrm{30}\:\boldsymbol{\mathrm{cm}}\: \\…
Question Number 60459 by tanmay last updated on 21/May/19 Commented by bhanukumarb2@gmail.com last updated on 21/May/19 $${source}\:{of}\:{question} \\ $$ Commented by tanmay last updated on…
Question Number 60439 by ajfour last updated on 21/May/19 Commented by ajfour last updated on 21/May/19 $$\mathrm{Find}\:\mathrm{length}\:\mathrm{AB}.\:\mathrm{The}\:\mathrm{curve}\:\mathrm{is}\:\mathrm{cubic}. \\ $$ Answered by tanmay last updated on…
Question Number 191364 by cortano12 last updated on 23/Apr/23 Commented by cortano12 last updated on 23/Apr/23 $$\mathrm{find}\:\mathrm{CD}. \\ $$ Commented by mr W last updated…
Question Number 125782 by ajfour last updated on 13/Dec/20 Commented by ajfour last updated on 13/Dec/20 $${Find}\:{radius}\:{of}\:{the}\:{smaller}\:{circle}. \\ $$ Commented by MJS_new last updated on…
Question Number 191307 by cortano12 last updated on 22/Apr/23 Answered by HeferH last updated on 22/Apr/23 $$\mathrm{60}°\:+\:\mathrm{90}°\:+\:?\:=\:\mathrm{180}° \\ $$$$\:?\:=\:\mathrm{30}° \\ $$ Commented by AROUNAMoussa last…
Question Number 60212 by peter frank last updated on 18/May/19 Commented by maxmathsup by imad last updated on 19/May/19 $${we}\:{have}\:\mathrm{3}{x}^{\mathrm{3}} −{x}^{\mathrm{2}} \:+\mathrm{2}{x}−\mathrm{4}\:=\mathrm{3}{x}^{\mathrm{3}} −\mathrm{3}{x}^{\mathrm{2}} \:+\mathrm{2}{x}^{\mathrm{2}} \:+\mathrm{2}{x}−\mathrm{4}…
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Question Number 125709 by mr W last updated on 13/Dec/20 Commented by mr W last updated on 13/Dec/20 $${the}\:{parabola}\:{of}\:{shape}\:{y}={x}^{\mathrm{2}} \:{rolls} \\ $$$${along}\:{the}\:{circle}\:{with}\:{radius}\:{r}.\: \\ $$$$\mathrm{1}.\:{find}\:{the}\:{locus}\:{of}\:{its}\:{vertex}\:{A}. \\…