Question Number 60115 by cesar.marval.larez@gmail.com last updated on 17/May/19 Commented by mr W last updated on 18/May/19 Commented by cesar.marval.larez@gmail.com last updated on 18/May/19 $${thannks}\:{buddy}…
Question Number 125572 by ajfour last updated on 12/Dec/20 Commented by ajfour last updated on 12/Dec/20 $${If}\:{equilateral}\:{triangle}\:{ABC}\:{has} \\ $$$${side}\:{length}\:{s}=\mathrm{3}\:{units},\:{find}\:{x}_{{A}} . \\ $$$${Parabola}\:{eq}.\:{is}\:\:{y}={x}^{\mathrm{2}} . \\ $$…
Question Number 191071 by cortano12 last updated on 17/Apr/23 $$\:\:\underbrace{\boldsymbol{{R}}} \\ $$ Commented by cortano12 last updated on 17/Apr/23 Commented by horsebrand11 last updated on…
Question Number 59992 by ajfour last updated on 16/May/19 Commented by ajfour last updated on 16/May/19 $$\mathrm{Find}\:{l}\:\mathrm{in}\:\mathrm{terms}\:\mathrm{of}\:\mathrm{a}\:\mathrm{and}\:\mathrm{b}. \\ $$ Answered by ajfour last updated on…
Question Number 59870 by ajfour last updated on 15/May/19 Commented by ajfour last updated on 15/May/19 $$\mathrm{Find}\:\mathrm{minimum}\:\mathrm{length}\:\mathrm{of}\:\mathrm{AB}.\:\mathrm{A}\:\mathrm{is}\:\mathrm{on} \\ $$$$\mathrm{an}\:\mathrm{ellipse}\:\mathrm{while}\:\mathrm{B}\:\mathrm{on}\:\mathrm{shown}\:\mathrm{parabola}. \\ $$ Commented by MJS last…
Question Number 190891 by mustafazaheen last updated on 13/Apr/23 $$\frac{\mathrm{a}}{\mathrm{b}}=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$$\mathrm{a}+\mathrm{b}=? \\ $$ Answered by mehdee42 last updated on 13/Apr/23 $${there}\:{is}\:{no}\:{unique}\:{answer} \\ $$$${if}\:\:{a}=\mathrm{2}\:\&\:{b}=\mathrm{3}\Rightarrow{a}+{b}=\mathrm{5} \\…
Question Number 125295 by mr W last updated on 09/Dec/20 Commented by mr W last updated on 09/Dec/20 $${the}\:{small}\:{circle}\:{with}\:{radius}\:\mathrm{1}\:{rolls} \\ $$$${along}\:{the}\:{parabola}\:{y}={x}^{\mathrm{2}} \:{as}\:{shown}. \\ $$$${find}\:{the}\:{locus}\:{of}\:{the}\:{point}\:{A}. \\…
Question Number 190694 by cortano12 last updated on 09/Apr/23 Commented by nikif99 last updated on 10/Apr/23 Answered by nikif99 last updated on 10/Apr/23 $$ \\…
Question Number 190678 by cortano12 last updated on 08/Apr/23 Answered by som(math1967) last updated on 09/Apr/23 $$\:{x}^{\mathrm{2}} ={AG}^{\mathrm{2}} −{GD}^{\mathrm{2}} \\ $$$$=\mathrm{12}^{\mathrm{2}} +{GE}^{\mathrm{2}} −{GD}^{\mathrm{2}} \\ $$$$=\mathrm{12}^{\mathrm{2}}…
Question Number 190665 by cortano12 last updated on 08/Apr/23 Terms of Service Privacy Policy Contact: info@tinkutara.com