Question Number 189921 by cortano12 last updated on 26/Mar/23 Commented by nikif99 last updated on 25/Mar/23 Commented by cortano12 last updated on 26/Mar/23 $$\mathrm{i}\:\mathrm{have}\:\mathrm{corrected}\:\mathrm{the}\:\mathrm{question}\: \\…
Question Number 189923 by alcohol last updated on 24/Mar/23 $$\int\frac{{dx}}{{a}\:+\:{btanx}} \\ $$ Answered by CElcedricjunior last updated on 24/Mar/23 $$\int\frac{\boldsymbol{{dx}}}{\boldsymbol{{a}}+\boldsymbol{{btanx}}}=\boldsymbol{{k}} \\ $$$$\boldsymbol{{posons}}\:\boldsymbol{{tanx}}=\boldsymbol{{t}}=>\boldsymbol{{dx}}=\frac{\mathrm{1}}{\mathrm{1}+\boldsymbol{{t}}^{\mathrm{2}} }\boldsymbol{{dt}} \\ $$$$\boldsymbol{{k}}=\int\frac{\boldsymbol{{dt}}}{\left(\boldsymbol{{a}}+\boldsymbol{{bt}}\right)\left(\mathrm{1}+\boldsymbol{{t}}^{\mathrm{2}}…
Question Number 189854 by a.lgnaoui last updated on 22/Mar/23 $$\mathrm{1}−{determiner}\:{l}\:{aire}\:{de}\:{la} \\ $$$${partie}\:{hachuree}\left({SDEB}\right) \\ $$$$\mathrm{2}−{le}\:{raport}\:\frac{{R}_{\mathrm{1}} }{{R}_{\mathrm{2}} } \\ $$$${sachant}\:{que}:\:{AB}=\mathrm{20}\left({diametre}\:{de}\:\left({C}\right)\right. \\ $$$$\:\:\measuredangle{CDE}=\mathrm{60}^{°} \:\:\:\measuredangle{OAD}=\mathrm{30}°.\:\:\left[{AI}\mid\mid{EF}\right. \\ $$$$\:\: \\ $$…
Question Number 58652 by peter frank last updated on 27/Apr/19 Commented by peter frank last updated on 27/Apr/19 $${a}\:{and}\:{b} \\ $$ Answered by tanmay last…
Question Number 124001 by Don08q last updated on 30/Nov/20 $$\mathrm{A}\:\mathrm{variable}\:\mathrm{point}\:{P}\left({x},\:{y}\right)\:\mathrm{moves}\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{curve}\:\:{xy}\:=\:\mathrm{6}\:\mathrm{and}\:{R}\:\mathrm{is}\:\mathrm{the}\:\mathrm{point}\:\mathrm{which}\: \\ $$$$\mathrm{divides}\:\mathrm{the}\:\mathrm{straight}\:\mathrm{line}\:\mathrm{that}\:\mathrm{joins}\:\mathrm{the} \\ $$$$\mathrm{points}\:{A}\left(−\mathrm{2},\:\mathrm{0}\right)\:\:\mathrm{and}\:\:{B}\left(\mathrm{0},\:−\mathrm{1}\right)\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{ratio}\:\mathrm{3}:\mathrm{1},\:\mathrm{internally}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{locus}\:\mathrm{of} \\ $$$${PR}. \\ $$ Answered by liberty…
Question Number 58400 by rahul 19 last updated on 22/Apr/19 $${If}\:{parabola}\:{y}=−{x}^{\mathrm{2}} −\mathrm{2}{x}+{k}\:{touches} \\ $$$${the}\:{parabola}\:{y}=−\frac{\mathrm{1}}{\mathrm{2}}{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{3}\:,\:{then} \\ $$$${the}\:{value}\:{of}\:{k}\:{is}\:? \\ $$$$\left.{a}\left.\right)\left.\:\left.\mathrm{1}\:\:\:\:{b}\right)\mathrm{2}\:\:\:\:\:{c}\right)\mathrm{3}\:\:\:\:\:{d}\right)\mathrm{4} \\ $$ Commented by rahul 19…
Question Number 123880 by 676597498 last updated on 29/Nov/20 $$\frac{\mathrm{20202020}}{\mathrm{2020}} \\ $$$$\mathrm{show}\:\mathrm{working} \\ $$ Commented by john_santu last updated on 29/Nov/20 $$\frac{\mathrm{20202020}}{\mathrm{2020}}=\:\frac{\mathrm{10001}×\mathrm{2020}}{\mathrm{2020}}=\mathrm{10001} \\ $$$$ \\…
Question Number 189339 by cortano12 last updated on 15/Mar/23 Answered by HeferH last updated on 15/Mar/23 Commented by HeferH last updated on 15/Mar/23 $$\:\mathrm{cos}\:\left(\mathrm{90}°+\alpha\right)=? \\…
Question Number 123799 by benjo_mathlover last updated on 28/Nov/20 Commented by benjo_mathlover last updated on 28/Nov/20 $${Identify}\:{the}\:{functions}\:{extreme} \\ $$$${values}\:{in}\:{given}\:{domain}\:{and}\: \\ $$$${say}\:{where}\:{they}\:{are}\:{assumed}\:. \\ $$$${Tell}\:{which}\:{of}\:{extreme}\:{values} \\ $$$${if}\:{any}\:{are}\:{absolute}\:…
Question Number 58254 by pete last updated on 20/Apr/19 $$\mathrm{The}\:\mathrm{line}\:\mathrm{3x}−\mathrm{2y}−\mathrm{5}=\mathrm{0}\:\mathrm{is}\:\mathrm{parallel}\:\mathrm{to}\:\mathrm{a}\:\mathrm{diameter} \\ $$$$\mathrm{of}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} −\mathrm{4x}+\mathrm{2y}−\mathrm{4}=\mathrm{0}.\:\mathrm{find}\:\mathrm{the} \\ $$$$\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{diameter}. \\ $$ Answered by tanmay last updated on 20/Apr/19…