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Category: Coordinate Geometry

Let-the-points-P-x-n-1-y-n-1-Q-x-n-y-n-and-R-x-n-1-y-n-1-lies-on-the-curve-y-f-x-Prove-that-y-n-1-y-n-1-2h-dy-dx-n-

Question Number 122187 by physicstutes last updated on 14/Nov/20 $$\mathrm{Let}\:\mathrm{the}\:\mathrm{points}\:{P}\left({x}_{{n}−\mathrm{1}} ,{y}_{{n}−\mathrm{1}} \right),\:{Q}\left({x}_{{n}} ,{y}_{{n}} \right)\:\mathrm{and}\:{R}\left({x}_{{n}+\mathrm{1}} ,{y}_{{n}+\mathrm{1}} \right)\:\mathrm{lies} \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{curve}\:{y}\:=\:{f}\left({x}\right).\:\mathrm{Prove}\:\mathrm{that}\: \\ $$$$\:\:{y}_{{n}+\mathrm{1}} \approx\:{y}_{{n}−\mathrm{1}} \:+\:\mathrm{2}{h}\:\left(\frac{{dy}}{{dx}}\right)_{{n}} .\: \\ $$…

Quel-est-la-condition-necessaire-et-sufisante-pour-que-les-medianes-des-triangles-ABC-et-CDE-soient-alignes-avec-le-point-c-

Question Number 187541 by a.lgnaoui last updated on 18/Feb/23 $${Quel}\:{est}\:{la}\:{condition}\:{necessaire} \\ $$$${et}\:{sufisante}\:{pour}\:{que}\:{les}\:{medianes} \\ $$$${des}\:{triangles}\:{ABC}\:{et}\:\:{CDE}\:{soient} \\ $$$${alignes}\:{avec}\:{le}\:{point}\:\boldsymbol{{c}} \\ $$$$ \\ $$ Commented by a.lgnaoui last updated…

pls-help-k-x-0-k-v-3-k-v-k-x-1-1-find-k-v-

Question Number 121955 by 676597498 last updated on 12/Nov/20 $$\mathrm{pls}\:\mathrm{help} \\ $$$$\mathrm{k}\left(\mathrm{x}\right)=\mathrm{0} \\ $$$$\mathrm{k}\left(\mathrm{v}+\mathrm{3}\right)=\mathrm{k}\left(\mathrm{v}\right) \\ $$$$\mathrm{k}\left(\mathrm{x}+\mathrm{1}\right)=\mathrm{1} \\ $$$$\mathrm{find}\:\mathrm{k}\left(\mathrm{v}\right) \\ $$ Terms of Service Privacy Policy…

Question-187059

Question Number 187059 by ajfour last updated on 13/Feb/23 Commented by ajfour last updated on 13/Feb/23 $${Bigger}\:{curve}\:\:\:{y}={x}^{\mathrm{3}} −{x}−{c} \\ $$$${the}\:{other}\:\:\:{y}={m}\left({x}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\right)^{\mathrm{2}} \left({x}−{s}\right) \\ $$$${say}\:{their}\:{intersections}\:{be}\:{at} \\ $$$${x}={p},\:{q},\:{t}…

Question-121355

Question Number 121355 by john santu last updated on 07/Nov/20 Answered by liberty last updated on 07/Nov/20 $$\mathrm{using}\:\mathrm{the}\:\mathrm{formula}\:\Rightarrow\left(\mathrm{x}−\mathrm{x}_{\mathrm{1}} \right)\left(\mathrm{x}−\mathrm{x}_{\mathrm{2}} \right)+\left(\mathrm{y}−\mathrm{y}_{\mathrm{1}} \right)\left(\mathrm{y}−\mathrm{y}_{\mathrm{2}} \right)=\mathrm{0} \\ $$$$\mathrm{where}\:\mathrm{the}\:\mathrm{point}\:\left(\mathrm{x}_{\mathrm{1}} ,\mathrm{y}_{\mathrm{1}}…