Question Number 211430 by a.lgnaoui last updated on 09/Sep/24 $$\mathrm{determiner}\:\mathrm{les}\:\mathrm{valeurs}\:\mathrm{demandees} \\ $$$$\mathrm{en}\:\mathrm{finction}\:\mathrm{des}\:\mathrm{donnes}\::\boldsymbol{\mathrm{a}},\:\boldsymbol{\mathrm{b}}\:,\mathrm{angle}\:\:\boldsymbol{\mathrm{F}}\mathrm{2} \\ $$$$\left(\mathrm{h}=\boldsymbol{\mathrm{MH}}\right) \\ $$ Commented by a.lgnaoui last updated on 09/Sep/24 Terms of…
Question Number 211294 by Jubr last updated on 05/Sep/24 Commented by a.lgnaoui last updated on 05/Sep/24 Commented by Ghisom last updated on 05/Sep/24 $$\mathrm{just}\:\mathrm{saying}:\:\mathrm{it}'\mathrm{s}\:\mathrm{not}\:\mathrm{convex} \\…
Question Number 211216 by Jubr last updated on 31/Aug/24 Answered by nikif99 last updated on 31/Aug/24 Commented by Jubr last updated on 31/Aug/24 $${Thank}\:{you}\:{sir} \\…
Question Number 211180 by Durganand last updated on 30/Aug/24 Answered by mr W last updated on 30/Aug/24 $$\left({ax}+{by}+{c}\right)\left(\frac{{x}}{{a}}+\frac{{y}}{{b}}+{d}\right) \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\left(\frac{{a}}{{b}}+\frac{{b}}{{a}}\right){xy}+\left({ad}+\frac{{c}}{{a}}\right){x}+\left({bd}+\frac{{c}}{{b}}\right)+{cd} \\ $$$$={x}^{\mathrm{2}} +{y}^{\mathrm{2}}…
Question Number 211141 by Durganand last updated on 29/Aug/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 210292 by 281981 last updated on 05/Aug/24 Commented by mr W last updated on 05/Aug/24 $${all}\:{answers}\:{are}\:{wrong}! \\ $$ Answered by mr W last…
Question Number 209398 by SonGoku last updated on 09/Jul/24 $$\mathrm{Is}\:\mathrm{it}\:\mathrm{possible}\:\mathrm{to}\:\mathrm{determine}\:\mathrm{the}\:\mathrm{points}\:\mathrm{A}\left(\mathrm{x}_{\mathrm{1}} ,\:\mathrm{y}_{\mathrm{1}} \right)\:\mathrm{and} \\ $$$$\mathrm{B}\left(\mathrm{x}_{\mathrm{2}} ,\:\mathrm{y}_{\mathrm{2}} \right)\:\mathrm{knowing}\:\mathrm{that}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{them}\:\mathrm{is} \\ $$$$\mathrm{2}\sqrt{\mathrm{29}}? \\ $$ Answered by Frix last updated…
Question Number 209389 by a.lgnaoui last updated on 08/Jul/24 $$\mathrm{Cercle}\:\mathrm{C}\:\:\:\mathrm{de}\:\mathrm{rayon}\:\boldsymbol{\mathrm{R}}=\mathrm{5} \\ $$$$\mathrm{petits}\:\mathrm{cercles}\:\mathrm{de}\:\mathrm{meme}\:\mathrm{rayon}\:\boldsymbol{\mathrm{r}} \\ $$$$\mathrm{Determiner}\:\mathrm{Surface}\:\left(\boldsymbol{\mathrm{ABCDEF}}\right)? \\ $$ Commented by a.lgnaoui last updated on 08/Jul/24 Terms of…
Question Number 209307 by efronzo1 last updated on 06/Jul/24 Commented by mr W last updated on 06/Jul/24 $$\mid{QR}\mid<\frac{\mathrm{8}}{\mathrm{3}}−\mathrm{1}=\frac{\mathrm{5}}{\mathrm{3}} \\ $$$$\frac{{QR}}{{PR}}=\frac{\mathrm{2}}{\mathrm{1}}\:\Rightarrow\frac{{PQ}}{{QR}}=\frac{\sqrt{\mathrm{5}}}{\mathrm{2}} \\ $$$$\mid{PQ}\mid=\frac{\sqrt{\mathrm{5}}}{\mathrm{2}}×{QR}<\frac{\sqrt{\mathrm{5}}}{\mathrm{2}}×\frac{\mathrm{5}}{\mathrm{3}}=\frac{\mathrm{5}\sqrt{\mathrm{5}}}{\mathrm{6}}<\sqrt{\mathrm{5}} \\ $$$$\Rightarrow{impossible}\:{that}\:\mid{PQ}\mid=\sqrt{\mathrm{5}}\:! \\…
Question Number 209301 by alcohol last updated on 06/Jul/24 Terms of Service Privacy Policy Contact: info@tinkutara.com