Coordinate Geometry – Page 29

Prove-that-the-perpendicilar-tangent-to-the-ellipse-x-2-a-2-y-2-b-2-1-meets-on-the-circle-x-2-y-2-a-2-b-2-

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Question Number 51613 by peter frank last updated on 29/Dec/18 $P r o v e t h a t t h e p e r p e n d i c i l a r$ $t a n g e n t t o t h e e l l i p s e$ $\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1 m e e t s o n t h e$ $${circle}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} ={a}^{\mathrm{2}} +{b}^{\mathrm{2}} .…

The-tangent-at-P-to-an-ellipse-meets-directrix-at-Q-prove-that-the-line-joining-the-corresponding-focus-to-P-and-Q-are-perpendicular-

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Question Number 51588 by peter frank last updated on 28/Dec/18 $T h e t a n g e n t a t P t o a n e l l i p s e$ $m e e t s d i r e c t r i x a t Q$ $p r o v e t h a t t h e l i n e$ $j o i n i n g t h e c o r r e s p o n d i n g$ $f o c u s t o P a n d Q a r e$ $p e r p e n d i c u l a r$ Answered by…

The-line-y-mx-c-touches-ellipse-x-2-a-2-y-2-b-2-1-prove-that-the-foot-of-perpendicular-from-focus-into-this-line-lie-on-auxillary-circle-x-2-y-2-a-2-

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Question Number 51590 by peter frank last updated on 28/Dec/18 $T h e l i n e y = m x + c t o u c h e s$ $e l l i p s e \frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$ $p r o v e t h a t t h e f o o t o f$ $p e r p e n d i c u l a r f r o m$ $f o c u s i n t o t h i s l i n e l i e o n$ $${auxillary}\:{circle}\:…

For-ellipse-16x-2-4y-2-96x-8y-84-0-find-i-centre-ii-verteces-iii-focus-iv-directrix-v-length-of-major-and-minor-axis-vi-ecentricity-vii-graph-the-ellipse-

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Question Number 51492 by peter frank last updated on 27/Dec/18 $F o r e l l i p s e$ $16 x^{2} + 4 y^{2} + 96 x - 8 y - 84 = 0$ $f i n d$ $i) c e n t r e$ $i i) v e r t e c e s$ $i i i) f o c u s$ $$\left.{iv}\right){directrix}…

Given-that-y-mx-c-is-equation-of-tangent-to-the-ellipse-x-2-a-2-y-2-b-2-1-find-coordinate-of-point-of-contact-

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Question Number 51489 by peter frank last updated on 27/Dec/18 $G i v e n t h a t y = m x + c$ $i s e q u a t i o n o f t a n g e n t$ $t o t h e e l l i p s e \frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$ $f i n d c o o r d i n a t e o f$ $p o i n t o f c o n t a c t .$ …

Question-51485

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Question Number 51485 by ajfour last updated on 27/Dec/18 Commented by ajfour last updated on 27/Dec/18 $R e g i o n s A, B, C h a v e t h e s a m e a r e a .$ $F i n d e q u a t i o n o f t h e p a r a b o l a .$ Terms of Service Privacy…

Question-182542

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Question Number 182542 by cortano1 last updated on 11/Dec/22 Commented by cortano1 last updated on 11/Dec/22 $Radius semi circle PQR = 24 cm$ $radius semi circle BML = 21 cm$ $find the area ABCD .$ Answered by…

Question-51372

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Question Number 51372 by ajfour last updated on 26/Dec/18 Commented by ajfour last updated on 26/Dec/18 $F o r t h e t w o c o l o u r e d a r e a s t o b e$ $e q u a l, w h a t i s t h e s l o p e o f b l u e l i n e ?$ Answered by mr W…

Question-51279

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Question Number 51279 by ajfour last updated on 25/Dec/18 Commented by ajfour last updated on 25/Dec/18 $I f b o t h e l l i p s e s h a v e t h e s a m e$ $p a r a m e t e r s a a n d b, f i n d h .$ Answered by mr W…

Find-the-ecentricity-If-1-lactus-rectum-is-half-major-axis-2-lactus-rectum-is-half-minor-axis-

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Question Number 51269 by peter frank last updated on 25/Dec/18 $F i n d t h e e c e n t r i c i t y I f$ $(1) l a c t u s r e c t u m i s h a l f$ $m a j o r a x i s$ $(2) l a c t u s r e c t u m i s h a l f$ $m i n o r a x i s$ Answered by tanmay.chaudhury50@gmail.com last…

Category: Coordinate Geometry