Question Number 49020 by ajfour last updated on 01/Dec/18 Commented by ajfour last updated on 01/Dec/18 $${If}\:{the}\:{inscribed}\:{ellipse}\:{is}\:{of}\:{maximum} \\ $$$${area}\:{with}\:{its}\:{major}\:{axis}\:{parallel}\:{to} \\ $$$${side}\:{PQ}\:{of}\:\bigtriangleup{PQR}\:{with}\:{PR}\:=\:{q}\:{and} \\ $$$${QR}\:={p}\:,\:{find}\:\boldsymbol{{a}},\:\boldsymbol{{b}}\:{of}\:{the}\:{ellipse}. \\ $$…
Question Number 48846 by ajfour last updated on 29/Nov/18 Commented by ajfour last updated on 29/Nov/18 $${Find}\:{maximum}\:{area}\:{of}\:\bigtriangleup{ABC}\:{in} \\ $$$${terms}\:{of}\:{radii}\:{a},\:{b}\:{and}\:{R}. \\ $$ Terms of Service Privacy…
Question Number 48656 by rahul 19 last updated on 26/Nov/18 Commented by rahul 19 last updated on 26/Nov/18 $${I}'{m}\:{getting}\:\left({b}\right)\:{but}\:{ans}.\:{is}\:\left({c}\right)! \\ $$ Commented by ajfour last…
Question Number 179515 by cortano1 last updated on 30/Oct/22 Answered by Acem last updated on 30/Oct/22 Commented by Acem last updated on 30/Oct/22 $$ \\…
Question Number 179458 by cortano1 last updated on 29/Oct/22 $$ \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{triangle}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{first}\:\mathrm{quadrant}\:\mathrm{between}\:\mathrm{the}\:\mathrm{x}\:\mathrm{and}\:\mathrm{y} \\ $$$$\mathrm{axis}\:\mathrm{and}\:\mathrm{the}\:\mathrm{tangent}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{relationship}\:\mathrm{curve}\:\mathrm{y}=\frac{\mathrm{5}}{\mathrm{x}}−\frac{\mathrm{x}}{\mathrm{5}}\:\mathrm{and}\:\mathrm{x}\:\mathrm{dont} \\ $$$$\mathrm{equal}\:\mathrm{0}\:\mathrm{at}\:\left(\mathrm{0},\mathrm{5}\right) \\ $$ Commented by Acem…
Question Number 48359 by ajfour last updated on 22/Nov/18 Answered by mr W last updated on 23/Nov/18 $$\frac{{x}^{\mathrm{2}} }{{a}^{\mathrm{2}} }+\frac{{y}^{\mathrm{2}} }{{b}^{\mathrm{2}} }=\mathrm{1} \\ $$$$\frac{{x}}{{a}^{\mathrm{2}} }+\frac{{yy}'}{{b}^{\mathrm{2}}…
Question Number 179360 by a.lgnaoui last updated on 28/Oct/22 $${Donnes}:\:\mathrm{AD}=\mathrm{1};\:\mathrm{DB}=\mathrm{6};\:\measuredangle{BCD}=\mathrm{45}°\:;\:\measuredangle{BAC}=\mathrm{90}° \\ $$$${Determiner} \\ $$$$\left.\mathrm{1}\right)\:\:\mathrm{A}{C}\:\:?\:\: \\ $$$$\left.\mathrm{2}\right)\:\:\mathrm{A}{E}? \\ $$$$−−−−−−−−−−−− \\ $$$${Solution} \\ $$$$\bigtriangleup{BAC}\:\:\:\:\:\:\measuredangle{BAC}=\mathrm{90}° \\ $$$${BC}^{\mathrm{2}} ={AB}^{\mathrm{2}}…
Question Number 48250 by ajfour last updated on 21/Nov/18 Commented by ajfour last updated on 21/Nov/18 $${Find}\:{minimum}\:{area}\:{of}\:\bigtriangleup{ABC} \\ $$$${in}\:{terms}\:{of}\:{ellipse}\:{parameters} \\ $$$${a}\:{and}\:{b}. \\ $$ Commented by…
Question Number 48246 by ajfour last updated on 21/Nov/18 Commented by ajfour last updated on 21/Nov/18 $${Find}\:{a}/{b}\:,\:{if}\:{the}\:{ellipse}\:{parameters} \\ $$$${are}\:{even}\:{a}\:{and}\:{b}. \\ $$ Answered by mr W…
Question Number 113740 by bemath last updated on 15/Sep/20 $${In}\:{triangle}\:{ABC}\:{has}\:{positive}\:{integer} \\ $$$${sides}\:;\:\angle{A}\:=\:\mathrm{2}\:\angle{B}\:{and}\:\angle{C}\:>\:\frac{\pi}{\mathrm{2}}. \\ $$$${What}\:{is}\:{the}\:{minimum}\:{length} \\ $$$${of}\:{the}\:{perimeter}\:{of}\:{the}\:{triangle}?\: \\ $$ Answered by bobhans last updated on 15/Sep/20…