Question Number 178131 by cortano1 last updated on 13/Oct/22 Commented by Frix last updated on 13/Oct/22 $$\mathrm{the}\:\mathrm{radius}\:\mathrm{is}\:{s}×{r}\:\mathrm{with}\:{r}\:\mathrm{being}\:\mathrm{the}\:\mathrm{real} \\ $$$$\mathrm{solution}\:\mathrm{of} \\ $$$${r}^{\mathrm{3}} −\mathrm{2}{r}^{\mathrm{2}} +\frac{\mathrm{3}{r}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{4}}=\mathrm{0} \\ $$$$\mathrm{which}\:\mathrm{is}…
Question Number 112576 by ajfour last updated on 08/Sep/20 Commented by ajfour last updated on 08/Sep/20 $${Find}\:{OA}={AB}. \\ $$ Answered by mr W last updated…
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Question Number 46935 by ajfour last updated on 02/Nov/18 Commented by ajfour last updated on 03/Nov/18 $${If}\:{both}\:{coloured}\:{regions}\:{have}\:{the} \\ $$$${same}\:{area},\:{find}\:{locus}\:{of}\:{C}\:{in} \\ $$$${polar}\:{form}\:{or}\:{cartesian}\:{form}. \\ $$$${Take}\:{center}\:{of}\:{rectangle}\:{as}\:{origin}, \\ $$$${and}\:{radius}\:{of}\:{circle}\:{R}.…
Question Number 177980 by infinityaction last updated on 11/Oct/22 Answered by mr W last updated on 11/Oct/22 Commented by mr W last updated on 11/Oct/22…
Question Number 112356 by ajfour last updated on 07/Sep/20 Commented by ajfour last updated on 07/Sep/20 $${Find}\:{minimum}\:{length}\:{of}\:{PQ}\:{in} \\ $$$${terms}\:{of}\:{a}\:{and}\:{b}.\:\:\:\:\:\:\: \\ $$ Answered by bemath last…
Question Number 177787 by mr W last updated on 09/Oct/22 Commented by mr W last updated on 09/Oct/22 $${elipse}\:{with}\:{parameters}\:{a}\:{and}\:{b}\:{is} \\ $$$${rotated}\:{about}\:{its}\:{center}\:{by}\:{angle}\:\varphi. \\ $$$${find}\:{the}\:{overlapping}\:{area}\:{in}\:{terms} \\ $$$${of}\:{a},\:{b},\:\varphi.…
Question Number 112179 by ajfour last updated on 06/Sep/20 Commented by ajfour last updated on 06/Sep/20 $${If}\:{AC}={BC}=\:{a}=\mathrm{5} \\ $$$$\&\:\:\:{AD}={BE}={b}=\mathrm{6} \\ $$$${find}\:{equation}\:{of}\:{lines}\:{AC}\:{and}\:{BC}. \\ $$ Answered by…
Question Number 112159 by bobhans last updated on 06/Sep/20 $$\left(\mathrm{1}\right)\mathrm{Find}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{hyperbola}\:\mathrm{with}\: \\ $$$$\mathrm{centre}\:\mathrm{point}\:\mathrm{at}\:\left(\mathrm{1},−\mathrm{2}\right)\:\mathrm{and}\:\mathrm{coordinates} \\ $$$$\mathrm{of}\:\mathrm{foci}\:\mathrm{is}\:\left(\mathrm{6},−\mathrm{2}\right)\:\mathrm{and}\:\left(−\mathrm{4},−\mathrm{2}\right) \\ $$$$\left(\mathrm{2}\right)\:\mathrm{If}\:\mathrm{hyperbola}\:\frac{\mathrm{x}^{\mathrm{2}} −\mathrm{2nx}+\mathrm{n}^{\mathrm{2}} }{\mathrm{25}}−\frac{\mathrm{y}^{\mathrm{2}} −\mathrm{2my}+\mathrm{m}^{\mathrm{2}} }{\mathrm{16}}=\mathrm{1} \\ $$$$\mathrm{have}\:\mathrm{a}\:\mathrm{asympyotes}\:\mathrm{passes}\:\mathrm{through}\:\mathrm{at}\: \\ $$$$\left(\mathrm{0},\mathrm{1}\right),\:\mathrm{then}\:\mathrm{5m}−\mathrm{4n}\:=\: \\…
Question Number 177628 by mr W last updated on 07/Oct/22 Commented by mr W last updated on 07/Oct/22 $${elipse}\:{with}\:{a}=\mathrm{10}{cm}\:{and}\:{b}=\mathrm{6}{cm}\:{is} \\ $$$${rotated}\:{about}\:{its}\:{center}\:{by}\:\mathrm{60}°.\:{find} \\ $$$${the}\:{shaded}\:{area}. \\ $$…