Question Number 44096 by peter frank last updated on 21/Sep/18 Answered by $@ty@m last updated on 21/Sep/18 $$\left({a}\right)\:\mathrm{cos}\:{A}=\frac{{b}^{\mathrm{2}} +{c}^{\mathrm{2}} −{a}^{\mathrm{2}} }{\mathrm{2}{bc}} \\ $$$${a}^{\mathrm{2}} ={b}^{\mathrm{2}} +{c}^{\mathrm{2}}…
Question Number 44088 by peter frank last updated on 21/Sep/18 Answered by $@ty@m last updated on 21/Sep/18 $$\left(\boldsymbol{{a}}\right)\:\angle{BCA}=\angle{BCD}\:\left({same}\:{angle}\right) \\ $$$$\angle{ABC}=\angle{BDC}\:\left({right}\:{angle}\right) \\ $$$$\angle{BAC}=\angle{DBC}\:\left({third}\:{angle}\right) \\ $$$$\therefore\bigtriangleup{ABC}\sim\bigtriangleup{BDC} \\…
Question Number 43990 by ajfour last updated on 19/Sep/18 Commented by ajfour last updated on 27/Sep/18 $${Unique}\:{parabola}\:{or}\:{not}\:? \\ $$$${Asking}\:{again}.\:{some}\:{batsmen} \\ $$$${say},\:{not}\:{unique},\:{i}\:{seek}\:{opinions} \\ $$$${again}.. \\ $$…
Question Number 109483 by ajfour last updated on 24/Aug/20 Commented by ajfour last updated on 24/Aug/20 $${If}\:{the}\:{cubic}\:{curve}\:{has}\:{equation}, \\ $$$${y}={x}^{\mathrm{3}} −\mathrm{21}{x}−\mathrm{20} \\ $$$${Find}\:{coordinates}\:{of}\:{P}. \\ $$ Commented…
Question Number 43921 by peter frank last updated on 17/Sep/18 $${prove}\:{that}\:{product}\:{of}\:{lengths}\:{of}\:{perpendiculars} \\ $$$${from}\:{any}\:{point}\:{of}\:{hyperbola}\:{to}\:{its} \\ $$$${asymptotes}\:{is}\:{constant} \\ $$ Answered by math1967 last updated on 18/Sep/18 $${let}\:{equn}.\:{of}\:{hyperbola}\:{is}\frac{{x}^{\mathrm{2}}…
Question Number 43919 by peter frank last updated on 17/Sep/18 $${The}\:{tangent}\:{at}\:{P}\:{to}\:{an}\:{ellipse}\:{meet}\: \\ $$$${diretrix}\:{at}\:{Q}.{prove}\:{that}\:{the}\:{line}\:{joining} \\ $$$${the}\:{corresponding}\:{focus}\:{to}\:{P}\:{and}\:{Q}\:{are}\:{perpendicular} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 43875 by peter frank last updated on 16/Sep/18 $${if}\:\:\:\mathrm{tan}\:\left({x}+{y}\right)=\frac{\mathrm{3}}{\mathrm{4}}\:\:{and}\:\mathrm{tan}\left({x}−{y}\right)=\frac{\mathrm{8}}{\mathrm{15}}\: \\ $$$${show}\:{that}\:\:\mathrm{tan}\:\mathrm{2}{x}=\:\frac{\mathrm{77}}{\mathrm{36}} \\ $$ Answered by ajfour last updated on 16/Sep/18 $$\mathrm{tan}\:\left({x}+{y}+{x}−{y}\right)=\frac{\frac{\mathrm{3}}{\mathrm{4}}+\frac{\mathrm{8}}{\mathrm{15}}}{\mathrm{1}−\frac{\mathrm{2}}{\mathrm{5}}} \\ $$$$\Rightarrow\:\:\:\:\:\mathrm{tan}\:\mathrm{2}{x}\:=\:\frac{\mathrm{77}}{\mathrm{36}}\:.…
Question Number 43783 by ajfour last updated on 15/Sep/18 Commented by ajfour last updated on 16/Sep/18 $${can}\:{an}\:{app}\:{plot}\:{it}\:{if}\:{it}\:{be}\:{unique}? \\ $$ Commented by ajfour last updated on…
Question Number 174816 by aupo14 last updated on 11/Aug/22 Commented by a.lgnaoui last updated on 13/Aug/22 $${the}\:{folowing}\:{anser}\:\mathrm{2}/\mathrm{2}\:{wil}\:{be}\:{sent}\:{is}\:{in}\:{the}\:{next}\:{anser}\: \\ $$ Answered by MikeH last updated on…
Question Number 43404 by peter frank last updated on 10/Sep/18 Answered by alex041103 last updated on 10/Sep/18 $$\frac{{d}}{{dx}}\left(\frac{{x}^{\mathrm{2}} }{\mathrm{16}}−\frac{{y}^{\mathrm{2}} }{\mathrm{4}}=\mathrm{1}\right) \\ $$$$\frac{{x}}{\mathrm{8}}−\frac{{y}}{\mathrm{2}}\left(\frac{{dy}}{{dx}}\right)=\mathrm{0} \\ $$$$\Rightarrow\frac{{dy}}{{dx}}=\frac{{x}}{\mathrm{4}{y}} \\…