Question Number 203465 by princemurtuja last updated on 19/Jan/24 $$\mathrm{Focus}\:\mathrm{and}\:\mathrm{vertex}\:\mathrm{of}\:\mathrm{a}\:\mathrm{parabola}\:\mathrm{are}\:\mathrm{at}\:\left(\mathrm{3},\:\mathrm{4}\right)\:\mathrm{and}\:\left(\mathrm{0},\mathrm{0}\right). \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{directrix}. \\ $$ Answered by mr W last updated on 20/Jan/24 $${F}\left(\mathrm{3},\:\mathrm{4}\right) \\ $$$${V}\left(\mathrm{0},\:\mathrm{0}\right)…
Question Number 203159 by a.lgnaoui last updated on 11/Jan/24 $$\mathrm{Q202938} \\ $$$$\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{is}}\:\mathrm{15}\: \\ $$$$\left(\boldsymbol{{Voir}}\:\boldsymbol{{reponse}}\:\boldsymbol{{develope}}\:\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 201989 by cortano12 last updated on 18/Dec/23 Answered by mr W last updated on 18/Dec/23 Commented by mr W last updated on 18/Dec/23…
Question Number 201829 by 281981 last updated on 13/Dec/23 $${shortest}\:{distance}\:{from}\:\left(−\mathrm{6},\mathrm{0}\right){to}\:{x}^{\mathrm{2}} −{y}^{\mathrm{2}} +\mathrm{16}=\mathrm{0} \\ $$ Answered by esmaeil last updated on 13/Dec/23 $${d}=\sqrt{\left({x}+\mathrm{6}\right)^{\mathrm{2}} +{y}^{\mathrm{2}} }=\sqrt{\overset{\mathrm{2}} {{x}}+\mathrm{12}{x}+\mathrm{36}+\overset{\mathrm{2}}…
Question Number 201660 by LimPorly last updated on 10/Dec/23 $${An}\:{equilateral}\:{triangle}\:{inscribed}\:{in}\:{a}\:{parabola} \\ $$$${y}^{\mathrm{2}} =\mathrm{4}{x}.\:{One}\:{of}\:{its}\:{vertices}\:{is}\:{at}\:{the}\:{vertex}\:{of}\:\:{the}\:{parabola}. \\ $$$${Find}\:{the}\:{length}\:{of}\:{each}\:{side}\:{of}\:{the}\:{triangle}\:{in}\:{units}. \\ $$ Answered by som(math1967) last updated on 10/Dec/23 $$\:{slope}\:{of}\:{AB}\:={tan}\mathrm{30}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}…
Question Number 201659 by LimPorly last updated on 10/Dec/23 $${Find}\:{the}\:{shortest}\:{distance}\:{between}\: \\ $$$${point}\:{A}\left(\mathrm{3},\mathrm{2}\right)\:{and}\:{curve}\:{y}=\sqrt{{x}}\:\left({x}>\mathrm{0}\right). \\ $$ Answered by mr W last updated on 10/Dec/23 $${say}\:{the}\:{distance}\:{is}\:{s}. \\ $$$${say}\:{the}\:{point}\:{on}\:{the}\:{curve}\:{is}\:\left({p}^{\mathrm{2}}…
Question Number 201581 by cortano12 last updated on 09/Dec/23 Answered by mr W last updated on 09/Dec/23 Commented by mr W last updated on 09/Dec/23…
Question Number 201383 by cortano12 last updated on 05/Dec/23 Commented by mr W last updated on 05/Dec/23 Commented by ahmetgg last updated on 09/Dec/23 Commented…
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Question Number 200636 by a.lgnaoui last updated on 21/Nov/23 $$\mathrm{1}−\mathrm{Determiner}\:\mathrm{la}\:\mathrm{valeur}\:\mathrm{de}\:\:\boldsymbol{\mathrm{EF}} \\ $$$$\mathrm{2}−\mathrm{Laire}\:\mathrm{du}\:\mathrm{triangle}\:\:\boldsymbol{\mathrm{ADE}} \\ $$$$ \\ $$ Commented by a.lgnaoui last updated on 21/Nov/23 Commented by…