Question Number 173352 by cortano1 last updated on 10/Jul/22 Answered by mr W last updated on 10/Jul/22 $${x}_{{n}+\mathrm{1}} ^{\mathrm{2}} =\frac{\mathrm{2}{x}_{{n}} }{{x}_{{n}} +\mathrm{1}} \\ $$$$\left(\frac{\mathrm{1}}{{x}_{{n}+\mathrm{1}} }\right)^{\mathrm{2}}…
Question Number 107696 by ajfour last updated on 12/Aug/20 Commented by ajfour last updated on 12/Aug/20 $${If}\:{both}\:{circles}\:{have}\:{the}\:{equal}\:{radius}, \\ $$$${find}\:{the}\:{radius}. \\ $$ Answered by mr W…
Question Number 107594 by Rio Michael last updated on 11/Aug/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{greatest}\:\mathrm{common}\:\mathrm{divisor}\:\mathrm{of}\:\mathrm{1122}\:\mathrm{and}\:\mathrm{1001}\:\mathrm{and}\: \\ $$$$\mathrm{express}\:\mathrm{the}\:\mathrm{greatest}\:\mathrm{common}\:\mathrm{divisor}\:{d}\:\mathrm{in}\:\mathrm{the}\:\mathrm{form}. \\ $$$$\:\:{d}\:=\:\mathrm{1122}{x}\:+\:\mathrm{1001}{y} \\ $$$$\mathrm{Using}\:\mathrm{the}\:\mathrm{above}\:\mathrm{result}\:\mathrm{solve}\:\mathrm{the}\:\mathrm{congruence}\:\mathrm{equation} \\ $$$$\:\mathrm{37}{x}\:\equiv\:\mathrm{11}\:\left(\mathrm{mod}\:\mathrm{33}\right) \\ $$ Answered by 1549442205PVT last…
Question Number 173033 by cortano1 last updated on 05/Jul/22 Answered by greougoury555 last updated on 05/Jul/22 $$\:{f}\:'\left({x}\right)=\:\mathrm{cos}\:{x}−\mathrm{sin}\:{x}\:−\frac{\mathrm{4}{k}\:\mathrm{cos}\:\mathrm{2}{x}}{\mathrm{sin}\:^{\mathrm{2}} \mathrm{2}{x}}\:=\mathrm{0} \\ $$$$\:\left(\mathrm{cos}\:{x}−\mathrm{sin}\:{x}\right)\left(\mathrm{1}−\frac{\mathrm{4}{k}\left(\mathrm{cos}\:{x}+\mathrm{sin}\:{x}\right)}{\mathrm{sin}\:^{\mathrm{2}} \mathrm{2}{x}}\right)=\mathrm{0} \\ $$$$\left(°\right)\:\mathrm{tan}\:{x}=\mathrm{1}\Rightarrow{f}\:=\sqrt{\mathrm{2}}\:+\mathrm{2}{k}\: \\ $$$$\left(°°\right)\:\mathrm{1}\:=\frac{\mathrm{4}{k}\left(\mathrm{cos}\:{x}+\mathrm{sin}\:{x}\right)}{\mathrm{sin}\:^{\mathrm{2}}…
Question Number 173002 by Mikenice last updated on 04/Jul/22 Commented by kaivan.ahmadi last updated on 05/Jul/22 $$\mathrm{1}−{tg}^{\mathrm{2}} \theta=\mathrm{1}−\frac{{sin}^{\mathrm{2}} \theta}{{cos}^{\mathrm{2}} \theta}=\frac{{cos}^{\mathrm{2}} \theta−{sin}^{\mathrm{2}} \theta}{{cos}^{\mathrm{2}} \theta}= \\ $$$$\frac{\mathrm{1}−\mathrm{2}{sin}^{\mathrm{2}}…
Question Number 172878 by Mikenice last updated on 02/Jul/22 Commented by Mikenice last updated on 02/Jul/22 $${please}\:{if}\:{anyone}\:{want}\:{to}\left[{solve}\:{this}\right. \\ $$$${problem}\:{should}\:{please}\:{show}\:{the} \\ $$$${diagram} \\ $$ Answered by…
Question Number 41686 by ajfour last updated on 11/Aug/18 Commented by ajfour last updated on 11/Aug/18 $${Find}\:{radius}\:{of}\:{circle}\:{in}\:{terms}\:{of}\:{a}. \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on…
Question Number 172392 by greougoury555 last updated on 26/Jun/22 Commented by Rasheed.Sindhi last updated on 26/Jun/22 $$\theta=\mathrm{125}° \\ $$ Commented by mr W last updated…
Question Number 172179 by Mikenice last updated on 23/Jun/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 40857 by ajfour last updated on 28/Jul/18 Commented by ajfour last updated on 28/Jul/18 $${Find}\:{circumsphere}\:{radius}\:{R}\:{of} \\ $$$${a}\:{general}\:{triangular}\:{pyramid}. \\ $$ Commented by MJS last…