Question Number 40847 by LXZ last updated on 28/Jul/18 $${If}\:{the}\:{coordinate}\:{of}\:{the}\:{points}\:{A}\: \\ $$$${and}\:{B}\:{be}\:\left(\mathrm{3},\mathrm{3}\right)\:{and}\:\left(\mathrm{7},\mathrm{6}\right)\:{then}\:{the} \\ $$$${length}\:{of}\:{the}\:{portion}\:{of}\:{the}\:{line}\: \\ $$$${AB}\:{intercepted}\:{between}\:{the}\:{axes}\:{is} \\ $$$$\left({a}\right)\:\:\frac{\mathrm{5}}{\mathrm{4}}\:\:\:\left({b}\right)\:\:\:\frac{\sqrt{\mathrm{10}}}{\mathrm{4}}\:\:\:\:\left({c}\right)\:\:\frac{\sqrt{\mathrm{13}}}{\mathrm{3}}\:\:\:\:\left({d}\right)\:{none} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated…
Question Number 106356 by bobhans last updated on 04/Aug/20 $$\mathrm{find}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{set}\:\mathrm{of}\:\mathrm{equation}\: \\ $$$$\mid\mathrm{x}^{\mathrm{2}} −\mathrm{5x}+\mathrm{4}\mid\:=\:\mathrm{x}^{\mathrm{2}} −\mathrm{5}\mid\mathrm{x}\mid\:+\:\mathrm{4}\: \\ $$ Commented by bobhans last updated on 05/Aug/20 $$\mathrm{thanm}\:\mathrm{you}\:\mathrm{both} \\…
Question Number 106029 by ajfour last updated on 02/Aug/20 Commented by ajfour last updated on 02/Aug/20 $${Find}\:{coordinates}\:{of}\:{A}\left({x}_{{A}} ,\:{y}_{{A}} \right)\:\:{if} \\ $$$${all}\:{four}\:{quadrants}\:{receive}\:{equal} \\ $$$${area}\:{portions}\:{of}\:\bigtriangleup{ABC}.\:\:\left({x}_{{A}} \geqslant{y}_{{A}} \right)…
Question Number 171512 by infinityaction last updated on 16/Jun/22 Answered by som(math1967) last updated on 17/Jun/22 $$\overset{\frown} {{DL}}=\overset{\frown} {{LM}}=\overset{\frown} {{MB}} \\ $$$$\therefore\:\angle{DAL}=\angle{LAM}=\angle{MAB}=\mathrm{30} \\ $$$${ar}.\bigtriangleup{ALM}=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{8}{sin}\mathrm{30}×\mathrm{8}=\mathrm{16}{cm}^{\mathrm{2}} \\…
Question Number 171283 by cortano1 last updated on 11/Jun/22 Commented by mr W last updated on 11/Jun/22 $${a}=\mathrm{2}{R}\:\mathrm{sin}\:\mathrm{70}° \\ $$$${b}=\mathrm{2}{R}\:\mathrm{sin}\:\mathrm{60}° \\ $$$${c}=\mathrm{2}{R}\:\mathrm{sin}\:\mathrm{50}° \\ $$$${a}+{b}+{c}=\mathrm{24} \\…
Question Number 39955 by rahul 19 last updated on 13/Jul/18 Commented by tanmay.chaudhury50@gmail.com last updated on 14/Jul/18 Commented by tanmay.chaudhury50@gmail.com last updated on 14/Jul/18 Answered…
Question Number 105422 by ajfour last updated on 28/Jul/20 Commented by ajfour last updated on 28/Jul/20 $${Find}\:{radius}\:{of}\:{circle}\:{in}\:{terms}\:{of} \\ $$$${a}\:{and}\:{b}. \\ $$ Answered by ajfour last…
Question Number 39860 by ajfour last updated on 12/Jul/18 Commented by ajfour last updated on 12/Jul/18 $${OA}\:=\:{BP}\:\:\:,\:{OT}\:=\mathrm{1},\:\:\:\&\: \\ $$$$\angle{OTB}\:=\:\angle{BTP}\:\:\:\left({given}\:{conditions}\right). \\ $$ Answered by ajfour last…
Question Number 170890 by nadovic last updated on 02/Jun/22 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{which} \\ $$$$\mathrm{touches}\:\mathrm{the}\:\mathrm{line}\:{x}−\mathrm{3}{y}+\mathrm{13}\:=\:\mathrm{0}\: \\ $$$$\mathrm{and}\:\:\mathrm{passes}\:\mathrm{through}\:\mathrm{the}\:\mathrm{points}\:\left(\mathrm{6},\:\mathrm{3}\right) \\ $$$$\mathrm{and}\:\left(\mathrm{4},\:−\mathrm{1}\right). \\ $$ Answered by aleks041103 last updated on 02/Jun/22…
Question Number 105273 by ajfour last updated on 27/Jul/20 Commented by ajfour last updated on 27/Jul/20 $${Given}\:{P}\left({h},{k}\right)\:\:\:{and}\:\:{B}\left({p},{q}\right) \\ $$$${To}\:{find}\:{image}\:{I}\left({r},{t}\right)\:{of}\:{B}\left({p},{q}\right) \\ $$$${in}\:{the}\:{mirror}\:{line}\:{AT}. \\ $$ Answered by…