Question Number 167058 by cortano1 last updated on 05/Mar/22 Answered by mr W last updated on 05/Mar/22 $$\left(\frac{\mathrm{2}}{{r}}+\frac{\mathrm{1}}{\mathrm{1}}−\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{2}\left(\frac{\mathrm{2}}{{r}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{1}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }\right) \\ $$$$\frac{\mathrm{1}}{{r}}=\frac{\mathrm{9}}{\mathrm{8}} \\…
Question Number 166943 by cortano1 last updated on 03/Mar/22 Commented by blackmamba last updated on 03/Mar/22 $$\:{By}\:{Ladder}\:{theorem} \\ $$$$\:\frac{\mathrm{1}}{{x}+\mathrm{4}+\mathrm{5}+\mathrm{10}}+\frac{\mathrm{1}}{\mathrm{10}}=\frac{\mathrm{1}}{\mathrm{4}+\mathrm{10}}+\frac{\mathrm{1}}{\mathrm{5}+\mathrm{10}} \\ $$$$\Rightarrow\frac{\mathrm{1}}{{x}+\mathrm{19}}=\frac{\mathrm{1}}{\mathrm{14}}+\frac{\mathrm{1}}{\mathrm{15}}−\frac{\mathrm{1}}{\mathrm{10}} \\ $$$$\Rightarrow\frac{\mathrm{1}}{{x}+\mathrm{19}}=\frac{\mathrm{4}}{\mathrm{105}}\:;\:{x}=\frac{\mathrm{29}}{\mathrm{4}}=\mathrm{7}.\mathrm{25}\: \\ $$…
Question Number 35696 by Tinkutara last updated on 22/May/18 Commented by Rasheed.Sindhi last updated on 22/May/18 $$\mathrm{Mr}\:\mathrm{Tinkutara}, \\ $$$$\:^{\bullet} \mathrm{I}'\mathrm{ve}\:\mathrm{tried}\:\mathrm{many}\:\mathrm{attempts}\:\mathrm{to}\:\mathrm{your} \\ $$$$\mathrm{Q}#\mathrm{34870}.\:\mathrm{I}\:\mathrm{could}\:\mathrm{be}\:\mathrm{able}\:\mathrm{to}\:\mathrm{complete} \\ $$$$\:\mathrm{only}\:\mathrm{one}\:\mathrm{solution}\:\mathrm{under}\:\mathrm{the}\:\mathrm{topic}, \\…
Question Number 166738 by ajfour last updated on 26/Feb/22 Commented by ajfour last updated on 26/Feb/22 $$\:\:{Find}\:{r}_{{max}} \:{in}\:{terms}\:{of}\:{b}. \\ $$ Answered by mr W last…
Question Number 35646 by ajfour last updated on 21/May/18 Commented by ajfour last updated on 21/May/18 $${Find}\:{the}\:{equation}\:{of}\:{the}\:{parabola} \\ $$$${that}\:{touches}\:{the}\:{three}\:{circles};\:\left({the}\right. \\ $$$$\left.{larger}\:{circle}\:{at}\:{the}\:{vertex}\right). \\ $$ Commented by…
Question Number 166583 by ajfour last updated on 22/Feb/22 Answered by ajfour last updated on 23/Feb/22 $$\frac{\left({x}−{a}\right)^{\mathrm{2}} }{{a}^{\mathrm{2}} }+\frac{\left({x}^{\mathrm{2}} −{b}\right)^{\mathrm{2}} }{{b}^{\mathrm{2}} }=\mathrm{1} \\ $$$${x}^{\mathrm{4}} −\mathrm{2}{bx}^{\mathrm{2}}…
Question Number 35469 by tanmay.chaudhury50@gmail.com last updated on 19/May/18 $${find}\:{distance}\:{between}\:\left({x}_{\mathrm{1},} {y}_{\mathrm{1}} \right)\:{and}\:\left({x}_{\mathrm{2}} ,{y}_{\mathrm{2}} \right)\:{when} \\ $$$${x}\:{axis}\:{and}\:{y}\:{axis}\:{inclined}\:{ai}\:{angle}\:\theta \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 35470 by tanmay.chaudhury50@gmail.com last updated on 19/May/18 $${prove}\:{sin}\mathrm{0}^{{o}} =\mathrm{0}\:\:{and}\:{cos}\mathrm{0}^{{o}} =\mathrm{1} \\ $$ Answered by $@ty@m last updated on 19/May/18 $${We}\:{have} \\ $$$${When}\:\theta\:{is}\:{too}\:{small}, \\…
Question Number 35446 by ajfour last updated on 19/May/18 Commented by ajfour last updated on 19/May/18 $${Solution}\:{to}\:\:{Q}.\mathrm{35439} \\ $$ Answered by ajfour last updated on…
Question Number 35439 by ajfour last updated on 19/May/18 Commented by ajfour last updated on 19/May/18 $${The}\:{radius}\:{of}\:{sphere}\:{is}\:{R}.\:{It} \\ $$$${touches}\:{the}\:{lower}\:{plane}\:{at}\:{A}\:{at} \\ $$$${a}\:{distance}\:{AH}={a}\:{from}\:{line}\:{of} \\ $$$${intersection}\:{of}\:{planes}\:\left({that}\:{make}\:\right. \\ $$$${an}\:{angle}\:\theta\:{with}\:{each}\:{other}.\:{Sphere}…