Question Number 102060 by ajfour last updated on 06/Jul/20 Commented by ajfour last updated on 06/Jul/20 $${Find}\:\boldsymbol{{r}}\:{and}\:\boldsymbol{{R}}. \\ $$ Answered by mr W last updated…
Question Number 167519 by MikeH last updated on 18/Mar/22 $$\mathcal{V}_{\mathrm{4}} \:\mathrm{is}\:\mathrm{a}\:\mathrm{set}\:\mathrm{of}\:\mathrm{all}\:\mathrm{real}\:\mathrm{valued}\:\mathrm{continues}\: \\ $$$$\mathrm{functions}\:\mathrm{defined}\:\mathrm{on}\:\mathrm{the}\:\mathrm{entire}\:\mathrm{real} \\ $$$$\mathrm{line}\:\mathrm{together}\:\mathrm{with}\:\mathrm{standard}\:\mathrm{addition} \\ $$$$\mathrm{and}\:\mathrm{scalar}\:\mathrm{multiplication}.\:\mathrm{Is}\:\mathcal{V}_{\mathrm{4}} \: \\ $$$$\mathrm{a}\:\mathrm{vector}\:\mathrm{space}?\:\mathrm{Explain} \\ $$ Terms of Service…
Question Number 36237 by ajfour last updated on 30/May/18 Answered by MJS last updated on 30/May/18 $$\mathrm{the}\:\mathrm{distance}\:\mathrm{between}\:{AB}\:\mathrm{and}\:{P}\:\mathrm{must}\:\mathrm{be} \\ $$$$\mathrm{max},\:\mathrm{so}\:\mathrm{we}'\mathrm{re}\:\mathrm{looking}\:\mathrm{for}\:\mathrm{the}\:\mathrm{tangent}\:\mathrm{parallel} \\ $$$$\mathrm{to}\:{AB} \\ $$ Commented by…
Question Number 167058 by cortano1 last updated on 05/Mar/22 Answered by mr W last updated on 05/Mar/22 $$\left(\frac{\mathrm{2}}{{r}}+\frac{\mathrm{1}}{\mathrm{1}}−\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{2}\left(\frac{\mathrm{2}}{{r}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{1}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }\right) \\ $$$$\frac{\mathrm{1}}{{r}}=\frac{\mathrm{9}}{\mathrm{8}} \\…
Question Number 166943 by cortano1 last updated on 03/Mar/22 Commented by blackmamba last updated on 03/Mar/22 $$\:{By}\:{Ladder}\:{theorem} \\ $$$$\:\frac{\mathrm{1}}{{x}+\mathrm{4}+\mathrm{5}+\mathrm{10}}+\frac{\mathrm{1}}{\mathrm{10}}=\frac{\mathrm{1}}{\mathrm{4}+\mathrm{10}}+\frac{\mathrm{1}}{\mathrm{5}+\mathrm{10}} \\ $$$$\Rightarrow\frac{\mathrm{1}}{{x}+\mathrm{19}}=\frac{\mathrm{1}}{\mathrm{14}}+\frac{\mathrm{1}}{\mathrm{15}}−\frac{\mathrm{1}}{\mathrm{10}} \\ $$$$\Rightarrow\frac{\mathrm{1}}{{x}+\mathrm{19}}=\frac{\mathrm{4}}{\mathrm{105}}\:;\:{x}=\frac{\mathrm{29}}{\mathrm{4}}=\mathrm{7}.\mathrm{25}\: \\ $$…
Question Number 35696 by Tinkutara last updated on 22/May/18 Commented by Rasheed.Sindhi last updated on 22/May/18 $$\mathrm{Mr}\:\mathrm{Tinkutara}, \\ $$$$\:^{\bullet} \mathrm{I}'\mathrm{ve}\:\mathrm{tried}\:\mathrm{many}\:\mathrm{attempts}\:\mathrm{to}\:\mathrm{your} \\ $$$$\mathrm{Q}#\mathrm{34870}.\:\mathrm{I}\:\mathrm{could}\:\mathrm{be}\:\mathrm{able}\:\mathrm{to}\:\mathrm{complete} \\ $$$$\:\mathrm{only}\:\mathrm{one}\:\mathrm{solution}\:\mathrm{under}\:\mathrm{the}\:\mathrm{topic}, \\…
Question Number 166738 by ajfour last updated on 26/Feb/22 Commented by ajfour last updated on 26/Feb/22 $$\:\:{Find}\:{r}_{{max}} \:{in}\:{terms}\:{of}\:{b}. \\ $$ Answered by mr W last…
Question Number 35646 by ajfour last updated on 21/May/18 Commented by ajfour last updated on 21/May/18 $${Find}\:{the}\:{equation}\:{of}\:{the}\:{parabola} \\ $$$${that}\:{touches}\:{the}\:{three}\:{circles};\:\left({the}\right. \\ $$$$\left.{larger}\:{circle}\:{at}\:{the}\:{vertex}\right). \\ $$ Commented by…
Question Number 166583 by ajfour last updated on 22/Feb/22 Answered by ajfour last updated on 23/Feb/22 $$\frac{\left({x}−{a}\right)^{\mathrm{2}} }{{a}^{\mathrm{2}} }+\frac{\left({x}^{\mathrm{2}} −{b}\right)^{\mathrm{2}} }{{b}^{\mathrm{2}} }=\mathrm{1} \\ $$$${x}^{\mathrm{4}} −\mathrm{2}{bx}^{\mathrm{2}}…
Question Number 35469 by tanmay.chaudhury50@gmail.com last updated on 19/May/18 $${find}\:{distance}\:{between}\:\left({x}_{\mathrm{1},} {y}_{\mathrm{1}} \right)\:{and}\:\left({x}_{\mathrm{2}} ,{y}_{\mathrm{2}} \right)\:{when} \\ $$$${x}\:{axis}\:{and}\:{y}\:{axis}\:{inclined}\:{ai}\:{angle}\:\theta \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com