Category: Coordinate Geometry

Question Number 208756 by efronzo1 last updated on 22/Jun/24 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 208554 by efronzo1 last updated on 18/Jun/24 Answered by liuxinnan last updated on 18/Jun/24 Commented by efronzo1 last updated on 18/Jun/24 Answered by…

Question Number 208327 by efronzo1 last updated on 12/Jun/24 Answered by A5T last updated on 12/Jun/24 $$DE=5x,DF=12x$$$$LettheperpendicularfromAtoBCmeetitatH;$$$$AH\times BC=3\times 4=12\Rightarrow AH=\frac{12}{5}$$$$\Rightarrow BH=\sqrt{9-\frac{144}{25}}=\frac{9}{5}$$$$\frac{{AD}}{{AB}}=\frac{{DE}}{{BC}}={x}\Rightarrow{AD}=\mathrm{3}{x}\Rightarrow{AE}=\mathrm{4}{x}…

Question Number 207879 by efronzo1 last updated on 29/May/24 Answered by mr W last updated on 29/May/24 $$f\left(x\right)=x^2-6x+12={(x-3)}^2+3⩾3$$$$f\left(a\right)=65539=a^2-6a+12$$$$\Rightarrow{a}^{\mathrm{2}}…

Question Number 207231 by efronzo1 last updated on 10/May/24 Answered by Sutrisno last updated on 11/May/24 $$\bullet f\left(x\right)+f(1-\frac{1}{x})=1x+1\dots \left(1\right)$$$$\bullet x=1-\frac{1}{x}$$$$f(1-\frac{1}{x})+f\left(\frac{-1}{x-1}\right)=2-\frac{1}{x}\dots \left(2\right)$$$$\bullet x=\frac{-1}{x-1}$$$${f}\left(\frac{−\mathrm{1}}{{x}−\mathrm{1}}\right)+{f}\left({x}\right)=\frac{−\mathrm{1}}{{x}−\mathrm{1}}+\mathrm{1}\:…\left(\mathrm{3}\right)…