Question Number 95779 by i jagooll last updated on 27/May/20 $$\mathrm{if}\:\mathrm{plane}\:\mathrm{3x}+\mathrm{4y}+\mathrm{tz}=\mathrm{2}\:\mathrm{and}\: \\ $$$$\mathrm{kx}+\mathrm{6y}+\mathrm{5z}−\mathrm{2}=\mathrm{0}\:\mathrm{are}\:\mathrm{parallel}. \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{k}\:\mathrm{and}\:\mathrm{t}\: \\ $$ Answered by john santu last updated on 27/May/20…
Question Number 95726 by Rio Michael last updated on 27/May/20 $$\mathrm{th}\:\mathrm{forces}\:{F}_{\mathrm{1}} \:,{F}_{\mathrm{2}} ,{F}_{\mathrm{3}} \:\mathrm{act}\:\mathrm{at}\:\mathrm{points}\:\mathrm{ith}\:\mathrm{position}\:\mathrm{vectors}\:{r}_{\mathrm{1}} ,{r}_{\mathrm{2}} ,{r}_{\mathrm{3}} \:\:\mathrm{where} \\ $$$${F}_{\mathrm{1}} \:=\:\left(\mathrm{4}{i}\:+\:{j}\:+\:\mathrm{2}{k}\right){N}\:\:\:\:\:\:\:{r}_{\mathrm{1}} \:=\:\left(\mathrm{6}{i}\:+\:\mathrm{4}{j}\:+\:{k}\right)\:\mathrm{m} \\ $$$${F}_{\mathrm{2}} \:=\:\left({i}−\mathrm{2}{j}\:+\:{k}\right){N}\:\:\:\:\:\:\:\:\:\:\:{r}_{\mathrm{2}} \:=\:\left({i}\:+\:\mathrm{5}{j}\:−\mathrm{2}{k}\right)\:\mathrm{m}…
Question Number 30166 by Tinkutara last updated on 17/Feb/18 Commented by ajfour last updated on 18/Feb/18 Commented by ajfour last updated on 18/Feb/18 $${centre}\:{of}\:{circle}\:\:{Q}\left(\mathrm{1},\mathrm{1}\right) \\…
Question Number 95639 by i jagooll last updated on 26/May/20 $$\mathrm{find}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}\: \\ $$$$\mathrm{containing}\:\mathrm{the}\:\mathrm{point}\:\left(−\mathrm{2},\mathrm{2}\right)\:\mathrm{and} \\ $$$$\mathrm{passing}\:\mathrm{throught}\:\mathrm{the}\:\mathrm{points}\:\mathrm{of}\: \\ $$$$\mathrm{intersection}\:\mathrm{of}\:\mathrm{the}\:\mathrm{two}\:\mathrm{circle}\: \\ $$$$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{3x}−\mathrm{2y}−\mathrm{4}=\mathrm{0}\:\mathrm{and}\: \\ $$$$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} −\mathrm{2x}−\mathrm{y}−\mathrm{6}=\mathrm{0}…
Question Number 30002 by rahul 19 last updated on 14/Feb/18 Commented by ajfour last updated on 14/Feb/18 $${wrong}\:{options},\:{i}\:{think}. \\ $$ Commented by ajfour last updated…
Question Number 29960 by rahul 19 last updated on 14/Feb/18 Answered by ajfour last updated on 15/Feb/18 $$\frac{{x}^{\mathrm{2}} }{{a}^{\mathrm{2}} }+\frac{{y}^{\mathrm{2}} }{{b}^{\mathrm{2}} }=\mathrm{1}\:\Rightarrow\:\:\frac{{x}}{{a}^{\mathrm{2}} }+\frac{{y}}{{b}^{\mathrm{2}} }\left(\frac{{dy}}{{dx}}\right)=\mathrm{0} \\…
Question Number 161015 by mr W last updated on 10/Dec/21 Commented by mr W last updated on 11/Dec/21 $${The}\:{distances}\:{from}\:{the}\:{orthocenter} \\ $$$${to}\:{the}\:{vertexes}\:{of}\:{a}\:{triangle}\:{are} \\ $$$$\boldsymbol{{p}},\:\boldsymbol{{q}},\:\boldsymbol{{r}}\:{respectively}.\:{Find}\:{the}\:{side} \\ $$$${lengthes}\:{of}\:{the}\:{triangle}.…
Question Number 95464 by i jagooll last updated on 25/May/20 Commented by i jagooll last updated on 25/May/20 $$\mathrm{my}\:\mathrm{son}'\mathrm{s}\:\mathrm{exam}\:\mathrm{questions} \\ $$ Commented by john santu…
Question Number 95341 by AshrafNejem last updated on 24/May/20 $$\left.\mathrm{Q}\right)\:\mathrm{A}\:\mathrm{light}\:\mathrm{falls}\:\mathrm{on}\:\mathrm{two}\:\mathrm{slits}\:\mathrm{0}.\mathrm{15}\:{mm}\:\mathrm{apart}.\mathrm{An}\:\mathrm{interference}\:\mathrm{pattern} \\ $$$$\mathrm{is}\:\mathrm{produced}\:\mathrm{on}\:\mathrm{a}\:\mathrm{screen}\:\mathrm{60}\:{cm}\:\mathrm{from}\:\mathrm{the}\:\mathrm{slits},\:\mathrm{if}\: \\ $$$$\mathrm{the}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{the}\:\mathrm{second}\:\mathrm{and}\:\mathrm{the}\:\mathrm{fifth}\: \\ $$$$\mathrm{bright}\:\mathrm{bands}\:\left(\mathrm{frings}\right)\:\mathrm{is}\:\mathrm{0}.\mathrm{7}\:{cm}.\:\mathrm{Calculate}\:\mathrm{the}\: \\ $$$$\mathrm{avelength}\:\mathrm{of}\:\mathrm{the}\:\mathrm{used}\:\mathrm{light}. \\ $$$$\boldsymbol{{solution}}: \\ $$$$\Delta{y}_{{n}=\mathrm{2}\rightarrow\mathrm{n}=\mathrm{5}} =\mathrm{0}.\mathrm{7}\Rightarrow\Delta{y}=\mathrm{0}.\mathrm{7}/\mathrm{3}=\mathrm{0}.\mathrm{233}×\mathrm{10}^{−\mathrm{2}} \:{m} \\…
Question Number 29770 by gyugfeet last updated on 12/Feb/18 $${find}\:{the}\:{equation}\:{of}\:{a}\:{pair}\:{of}\:{straight}\:{lines}\:{represented}\:{by}\:{given}\:{equation}\:\mathrm{2}{x}^{\mathrm{2}\:} −\mathrm{5}{xy}−\mathrm{3}{y}^{\mathrm{2}} +\mathrm{3}{x}+\mathrm{19}{y}−\mathrm{20}=\mathrm{0} \\ $$ Answered by ajfour last updated on 12/Feb/18 $${let}\:{eq}.\:{of}\:{pair}\:{be} \\ $$$$−\mathrm{3}\left({y}−{m}_{\mathrm{1}} {x}−{c}_{\mathrm{1}}…