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Question Number 27870 by ajfour last updated on 15/Jan/18 Commented by ajfour last updated on 15/Jan/18 $${Q}.\mathrm{27818}\:{another}\:{solution} \\ $$ Answered by ajfour last updated on…
Question Number 158927 by cherokeesay last updated on 10/Nov/21 Answered by amin96 last updated on 10/Nov/21 $${area}\:{triangle}=\frac{\mathrm{126}−\mathrm{16}\sqrt{\mathrm{21}}}{\mathrm{5}} \\ $$ Commented by cherokeesay last updated on…
Question Number 27818 by ajfour last updated on 15/Jan/18 Commented by ajfour last updated on 15/Jan/18 $${If}\:{y}={Ax}^{\mathrm{2}} \:{is}\:{reflected}\:{in}\:{the}\:{line} \\ $$$$\frac{{x}}{{a}}+\frac{{y}}{{b}}=\mathrm{1}\:,\:{find}\:{equation}\:{of}\:{its} \\ $$$${reflection}\:{f}\left({x},{y}\right)=\mathrm{0}\:. \\ $$ Commented…
Question Number 158708 by ajfour last updated on 07/Nov/21 Commented by ajfour last updated on 07/Nov/21 $${Find}\:{equation}\:{of}\:{parabola}. \\ $$ Answered by mr W last updated…
Question Number 158143 by alcohol last updated on 31/Oct/21 Commented by TheHoneyCat last updated on 31/Oct/21 $$\mathrm{G}_{\mathrm{3}} \:\mathrm{and}\:\mathrm{G}_{\mathrm{2}} \:\mathrm{are}\:\mathrm{clearly}\:\mathrm{isomorphical}\:\mathrm{buy}\:\mathrm{looking} \\ $$$$\mathrm{at}\:\mathrm{their}\:\mathrm{respectiv}\:\mathrm{tables}. \\ $$$$\mathrm{we}\:\mathrm{just}\:\mathrm{need}\:\mathrm{to}\:\mathrm{map}\:\mathrm{as}\:\mathrm{follow}: \\ $$$$\begin{cases}{\mathrm{1}}&{\leftrightarrows}&{\mathrm{1}}\\{\mathrm{5}}&{\leftrightarrows}&{\mathrm{3}}\\{\mathrm{7}}&{\leftrightarrows}&{\mathrm{5}}\\{\mathrm{11}}&{\leftrightarrows}&{\mathrm{7}}\end{cases}…
Question Number 158101 by zainaltanjung last updated on 31/Oct/21 $$ \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{image}\:\mathrm{of}\:\mathrm{points}\: \\ $$$$\mathrm{K}\:\left(\mathrm{5},\mathrm{2}\right)\:\mathrm{and}\:\mathrm{L}\:\left(\mathrm{1}\:\mathrm{5}\right)\:\mathrm{after}\: \\ $$$$\mathrm{being}\:\mathrm{reflected}\:\mathrm{about}\:\mathrm{the}\:\mathrm{x} \\ $$$$\mathrm{axis}. \\ $$ Answered by Rasheed.Sindhi last updated…
Question Number 158102 by zainaltanjung last updated on 31/Oct/21 $$ \\ $$$$\mathrm{Given}\:\mathrm{the}\:\mathrm{quadrilateral}. \\ $$$$\mathrm{D}.\mathrm{ABC}\:\mathrm{Find}\:\mathrm{the}\:\mathrm{measure}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{angle}\:\mathrm{between}\:\mathrm{AB}\:\mathrm{and}\:\mathrm{CD}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 158069 by zainaltanjung last updated on 30/Oct/21 Answered by Rasheed.Sindhi last updated on 30/Oct/21 $${Let}\:{the}\:{side}\:{of}\:\:{old}\:\:{hexagon}={a} \\ $$$$\blacktriangle_{{old}} =\mathrm{6}\sqrt{\frac{\mathrm{3}{a}}{\mathrm{2}}\left(\frac{\mathrm{3}{a}}{\mathrm{2}}−{a}\right)^{\mathrm{3}} } \\ $$$$\blacktriangle_{{old}} =\mathrm{6}\sqrt{\frac{\mathrm{3}{a}}{\mathrm{2}}\left(\frac{{a}}{\mathrm{2}}\right)^{\mathrm{3}} }\:=\mathrm{6}\sqrt{\mathrm{3}\left(\frac{{a}}{\mathrm{2}}\right)^{\mathrm{4}}…
Question Number 157995 by zainaltanjung last updated on 30/Oct/21 $$\mathrm{Given}\:\mathrm{the}\:\mathrm{following}\:\mathrm{tetra}− \\ $$$$\mathrm{hedral}\:\mathrm{figure}.\:\mathrm{The}\:\mathrm{length}\:\mathrm{of}\: \\ $$$$\mathrm{the}\:\mathrm{rib}\:\mathrm{is}\:\mathrm{10}\:\mathrm{cm}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{area} \\ $$$$\:\mathrm{of}\:\:\mathrm{triangle}\:\mathrm{DEF}. \\ $$$$ \\ $$$$ \\ $$ Terms of Service…