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Question Number 90326 by ajfour last updated on 22/Apr/20 Commented by ajfour last updated on 22/Apr/20 $${Find}\:{a}/{b}.\:{Ellipse}\:\:{b}^{\mathrm{2}} {x}^{\mathrm{2}} +{a}^{\mathrm{2}} {y}^{\mathrm{2}} ={a}^{\mathrm{2}} {b}^{\mathrm{2}} . \\ $$…
Question Number 155866 by cherokeesay last updated on 05/Oct/21 Answered by talminator2856791 last updated on 05/Oct/21 $$\:\mathrm{2}\sqrt{\mathrm{3}}\:+\:\mathrm{2}\sqrt{\mathrm{3}}\:−\:\frac{\mathrm{9}\pi\centerdot\mathrm{arctan}\left(\frac{\mathrm{2}\sqrt{\mathrm{3}}}{\mathrm{2}}\right)}{\mathrm{2}\pi}\:−\:\frac{\pi}{\mathrm{4}}\:−\:\frac{\mathrm{arctan}\left(\frac{\mathrm{2}}{\mathrm{2}\sqrt{\mathrm{3}}}\right)}{\mathrm{2}}\:\: \\ $$$$\:=\:\mathrm{4}\sqrt{\mathrm{3}}\:−\:\frac{\mathrm{9}}{\mathrm{2}}\:\mathrm{arctan}\left(\sqrt{\mathrm{3}}\right)−\:\frac{\pi}{\mathrm{4}}\:−\:\mathrm{arctan}\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\right) \\ $$$$\:=\:\mathrm{4}\sqrt{\mathrm{3}}\:−\:\frac{\mathrm{9}\pi}{\mathrm{6}}\:−\:\frac{\pi}{\mathrm{4}}\:−\:\frac{\pi}{\mathrm{6}} \\ $$$$\:=\:\mathrm{4}\sqrt{\mathrm{3}}\:−\:\frac{\mathrm{13}\pi}{\mathrm{12}} \\ $$…
Question Number 90252 by ajfour last updated on 22/Apr/20 Commented by ajfour last updated on 22/Apr/20 $${If}\:{both}\:{ellipses}\:{have}\:{the}\:{same} \\ $$$${shape},\:{find},\:{b}/{a}\:.{Also}\:{find} \\ $$$${circumradius}\:{in}\:{terms}\:{of}\:{a}. \\ $$ Answered by…
Question Number 155735 by BHOOPENDRA last updated on 04/Oct/21 Answered by ajfour last updated on 04/Oct/21 Commented by ajfour last updated on 04/Oct/21 $${x}^{\mathrm{2}} +\left({y}−\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}}…
Question Number 155720 by ajfour last updated on 03/Oct/21 Commented by ajfour last updated on 03/Oct/21 $${If}\:{the}\:{polynomial}\:{curve}\:{is} \\ $$$$\:\:{y}={x}\left({x}^{\mathrm{2}} −{p}^{\mathrm{2}} \right)\:,\:{find}\:{r}\left({p}\right). \\ $$ Answered by…
Question Number 24555 by ajfour last updated on 20/Nov/17 Commented by ajfour last updated on 20/Nov/17 $${Find}\:{the}\:{maximum}\:{radius}\:{of} \\ $$$${a}\:{circle}\:{such}\:{that}\:{it}\:{touches}\:{the} \\ $$$${parabola}\:{y}={Ax}^{\mathrm{2}} \:{at}\:{its}\:{vertex}, \\ $$$${and}\:{lies}\:{above}\:{it}\:{and}\:{cuts}\:{it} \\…
Question Number 24379 by j.masanja06@gmail.com last updated on 16/Nov/17 Answered by mrW1 last updated on 17/Nov/17 $${x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{8}{y}+\mathrm{20}=\mathrm{0} \\ $$$$\left({x}−\mathrm{2}\right)^{\mathrm{2}} −\mathrm{4}+\left({y}+\mathrm{4}\right)^{\mathrm{2}} −\mathrm{16}+\mathrm{20}=\mathrm{0} \\ $$$$\left({x}−\mathrm{2}\right)^{\mathrm{2}}…
Question Number 24362 by gopikrishnan005@gmail.com last updated on 16/Nov/17 $${if}\:{the}\:{points}\:{P},{Q}\left({x},\mathrm{7}\right),{R},{S}\left(\mathrm{6},{y}\right)\:{in}\:{this}\:{order}\:{divide}\:{the}\:{line}\:{segment}\:{joining}\:{A}\left(\mathrm{2},{p}\right)\:{and}\:{B}\left(\mathrm{7},\mathrm{10}\right)\:{in}\:\mathrm{5}\:{equal}\:{parts}\:{find}\:{x},{y},\:{and}\:{p}. \\ $$ Commented by gopikrishnan005@gmail.com last updated on 17/Nov/17 $${pls}\:{help} \\ $$ Terms of Service…
Question Number 24347 by math solver last updated on 16/Nov/17 Commented by math solver last updated on 16/Nov/17 $$\mathrm{it}\:\mathrm{have}\:\:\mathrm{more}\:\mathrm{than}\:\mathrm{1}\:\mathrm{answer}. \\ $$ Commented by math solver…