Question Number 88683 by jagoll last updated on 12/Apr/20 Answered by mr W last updated on 12/Apr/20 Commented by mr W last updated on 12/Apr/20…
Question Number 88673 by ajfour last updated on 12/Apr/20 Commented by john santu last updated on 12/Apr/20 $${eqn}:\:{ellips}\:\frac{{x}^{\mathrm{2}} }{{a}^{\mathrm{2}} }\:+\:\frac{{y}^{\mathrm{2}} }{{b}^{\mathrm{2}} }\:=\:\mathrm{1} \\ $$$${eqn}:\:{circle}\:{x}^{\mathrm{2}} \:+\left({y}−{r}\right)^{\mathrm{2}}…
Question Number 88656 by ajfour last updated on 12/Apr/20 Commented by ajfour last updated on 12/Apr/20 $${If}\:\:{AB}={BC}\:,\:{find}\:{radius}\:{r}\:. \\ $$ Answered by ajfour last updated on…
Question Number 154138 by iloveisrael last updated on 14/Sep/21 Answered by EDWIN88 last updated on 14/Sep/21 Commented by EDWIN88 last updated on 14/Sep/21 $$\Rightarrow{Red}\:{area}\:=\:\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{18}}{\mathrm{7}}×\frac{\mathrm{24}}{\mathrm{7}}=\frac{\mathrm{216}}{\mathrm{49}} \\…
Question Number 154089 by iloveisrael last updated on 14/Sep/21 Answered by talminator2856791 last updated on 14/Sep/21 $$\: \\ $$$$\:\equiv\:\mathrm{max}\left(\frac{\mathrm{9}\centerdot\mathrm{sin}\left(\theta\right)\mathrm{9}\centerdot\mathrm{cos}\left(\theta\right)+\mathrm{3}\centerdot\mathrm{sin}\left(\theta\right)\mathrm{3}\centerdot\mathrm{cos}\left(\theta\right)}{\mathrm{2}}\right) \\ $$$$\:=\:\mathrm{max}\left(\frac{\mathrm{90}\left(\mathrm{sin}\left(\theta\right)\mathrm{cos}\left(\theta\right)\right)}{\mathrm{2}}\right) \\ $$$$\:\:\:\: \\ $$$$\:\:\:\:\mathrm{trigonometry}\:\mathrm{identity}:…
Question Number 154088 by iloveisrael last updated on 14/Sep/21 Commented by Tawa11 last updated on 14/Sep/21 $$\mathrm{Weldone}\:\mathrm{sir} \\ $$ Answered by mr W last updated…
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Question Number 154085 by iloveisrael last updated on 14/Sep/21 Commented by iloveisrael last updated on 14/Sep/21 $${find}\:{area}\:{of}\:{triangle}\:{ABC} \\ $$ Answered by EDWIN88 last updated on…
Question Number 154078 by iloveisrael last updated on 14/Sep/21 Commented by iloveisrael last updated on 14/Sep/21 $${super}\:{easy}\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 88525 by jagoll last updated on 11/Apr/20 Commented by jagoll last updated on 11/Apr/20 $$\mathrm{i}\:\mathrm{got}\:\mathrm{20}^{\mathrm{o}} \\ $$ Commented by mr W last updated…